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a/ \(-\frac{81}{504}=-\frac{9}{56};-\frac{10101}{101010}=\frac{-1}{10}\)
b/ \(\frac{72\cdot5+72\cdot3}{144\cdot2+144\cdot6}=\frac{72\left(5+3\right)}{144\left(2+6\right)}=\frac{8}{2\cdot8}=\frac{1}{2}\)
\(\frac{-81}{504}=-\frac{81:9}{504:9}=-\frac{9}{56}\)
\(\frac{-10101}{101010}=\frac{-10101:10101}{101010:10101}=\frac{-1}{10}\)
\(\frac{72.5+72.3}{144.2+144.6}=\frac{72.\left(5+3\right)}{144\left(2+6\right)}=\frac{72.8}{144.8}=\frac{72.8}{72.2.8}=\frac{1}{2}\)
\(\frac{-1997\cdot1996+1}{-1995\cdot\left(-1997\right)+1996}\)
\(=\frac{-1997\cdot\left(1995+1\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1997\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1996\right)}{1995\cdot1997+1996}\)
\(=-1\)
\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{1995.1997+1996}\)
\(=\frac{-1997.\left(1995+1\right)+1}{1995.1997+1996}\)
\(=\frac{-1997.1995+-1997+1}{1995.1997+1996}\)
\(=\frac{1995.-1997+-1996}{1995.1997+1996}\)
\(=\frac{-\left(1995.1997+1996\right)}{1995.1997+1996}\)
\(=-1\)
\(\frac{8,5-8,2}{16}\)=\(\frac{0,3}{16}\)= \(\frac{3}{160}\)=0,01875
\(\frac{11,4-11}{2-13}\)=\(\frac{0,4}{-11}\)=\(\frac{-2}{55}\)
học tốt
4x-(7+5x)=15+(-29). b,x/11=x+4/33
4x-7-5x=-14. 33x=11(x+4)
4x-5x=14+7. 33x=11x+44
-x=21. 33x-11x=44
x=-21 22x=44
x=44:22=2
\(C=\frac{8\cdot5-8\cdot2}{16}=\frac{8\cdot(5-2)}{16}=\frac{1\cdot(5-2)}{2}=\frac{1\cdot3}{2}=\frac{3}{2}\)
\(H=\left[\frac{-5}{24}+0,75+\frac{7}{12}\right]:\left[-2\frac{1}{8}\right]\)
\(H=\left[\frac{-5}{24}+\frac{75}{100}+\frac{7}{12}\right]:\left[-\frac{17}{8}\right]\)
\(H=\frac{9}{8}:\left[\frac{-17}{8}\right]=\frac{9}{8}\cdot\frac{8}{-17}=\frac{9}{1}\cdot\frac{1}{-17}=\frac{9}{-17}=\frac{-9}{17}\)
A=\(\frac{1.2.3.....20.\left(21.22.23.....39\right)}{\left(21.22.23.....39\right).40}\)
A=\(\frac{1.2.3.....20}{40}\)
A=\(1.3.4.5.....18.19\)
+2.20/40.
A=1.3.4.5.....18.19+1.
A= tự bấm máy là ra.
tk mk nha các bn.
-chúc ai tk mk học giỏi-
3/2=1,5
cách giải thế nào đã rồi mình tick cho