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đặt 12+22+32+...+20152 = M
22+42+62+...+40302 = N
ta có: N = (2.1)2+(2.2)2+(2.3)2+...+(2.2015)2
N = 22.12+22.22+22.32+...+22.20152
N = 22.(12+22+32+...+20152)
N = 4.M
=> M:N = 1/4
hay B = 1/4
\(P=\left(1^2+2^2+...............+2015^2\right):\left(2^2+4^2+........+4030^2\right)\)
\(P=\left(1^2+2^2+............+2015^2\right):\left[\left(1.2\right)^2+\left(2.2\right)^2+.............+\left(2.2015\right)^2\right]\)
\(P=\left(1^2+2^2+........+2015^2\right):\left(1^2.2^2+2^2.2^2+...............+2015^2.2^2\right)\)
\(P=\left(1^2+2^2+......+2015^2\right):2^2.\left(1^2+2^2+.........+2015^2\right)\)
\(P=\left(1^2+2^2+........+2015^2\right).\frac{1}{2^2.\left(1^2+2^2+..............+2015^2\right)}\)
\(P=\frac{1^2+2^2+...............+2015^2}{2^2.\left(1^2+2^2+............+2015^2\right)}=\frac{1}{2^2}=\frac{1}{4}\)
Chúc bạn học tốt
A=1+2+22+23+...+263
2A=2+22+23+...+263+264
\(-\)
\(A=1+2+2^2+....+2^{63}\)
\(A=2^{64}-1\)
Vậy A=264-1
a)2A=4+4^2+4^3+...+4^101
2A-A=4^101-1
A=4^101-1
khong bit phai hoi muon gioi phai hoc
a)A=1+22+24+...+214+216
2A=2(1+22+24+...+214+216)
2A=2+23+25+...+215+217
2A-A=(2+23+25+...+215+217)-(1+22+24+...+214+216)
1A=(217-1)/1
A=217-1
b)B=1-3+32-33+...-32015+32017
3B=3(1-3+32-33+...-32015+32017)
3B=3-32+33-...-32016+32017)
Mà B=1-3+32-33+...-32015+32017
=>3B-B=1+22017
=>4B=1+32016
=>B=(1+32017)/4
\(\frac{2^4.3^2}{6^3}=\frac{2^4.3^2}{\left(2.3\right)^3}=\frac{2^4.3^2}{2^3.3^3}=\frac{2}{3}\)
A=1+4+42+43+44+........+42015
4A=4(A=1+4+42+43+44+........+42015)
4A=4+42+43+44+45+........+42016
4A-A=(4+42+43+44+45+........+42016)-(1+4+42+43+44+........+42015)
3A=42016-1
A=(42016-1):3
\(\Rightarrow2A=2+2^2+2^3+2^4+...+2^{11}\)
\(\Leftrightarrow2A-A=A\)
\(\Rightarrow A=\left(2+2^2+2^3+2^4+...+2^{11}\right)-\left(1+2+2^2+2^3+...+2^{10}\right)\)
\(\Rightarrow A=2^{11}-1\)
Đặt:12+22+33+.....+20152=M
22+42+62+.....+30302=N
Ta có:
N=(2.1)2+(2.2)2+(2.3)2+.....+(2.2015)2
N=22.12+22.22+22.32+....+22.20152
N=22(12+22+32+....+20152)
N=4.M
Suy ra:
M:N=1/4
Hay B=1/4