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a)\(\frac{2.4}{6.18}\)=\(\frac{2.2.2}{2.3.2.3.3}\)=\(\frac{2.1.1}{1.3.1.3.3}\)=\(\frac{2}{27}\)
b)\(\frac{3.5.7}{6.9.14}\)=\(\frac{3.5.7}{2.3.3.3.2.7}\)=\(\frac{1.5.1}{2.1.3.3.2.1}\)=\(\frac{5}{36}\)
c)\(\frac{4.7-4.5}{64}\)=\(\frac{4.\left(7-5\right)}{64}\)=\(\frac{4.2}{64}\)=\(\frac{8}{64}\)=\(\frac{1}{8}\)
a, \(\dfrac{2.4}{6.18}\)=\(\dfrac{2}{27}\)
b,\(\dfrac{3.5.7}{6.9.14}\)=\(\dfrac{105}{756}\)=\(\dfrac{35}{232}\)
c,\(\dfrac{4.7-4.5}{64}\)=\(\dfrac{28-20}{64}\)=\(\dfrac{8}{64}\)=\(\dfrac{1}{8}\)
nhớ like nhé
\(\dfrac{2.4}{6.18}=\dfrac{8}{108}=\dfrac{2}{27}\)
\(\dfrac{3.5.7}{6.9.14}=\dfrac{105}{756}=\dfrac{35}{252}\)
\(\dfrac{4.7-4.5}{64}=\dfrac{4.\left(7-5\right)}{64}=\dfrac{4.2}{64}=\dfrac{8}{64}=\dfrac{1}{8}\)
Chúc bạn học tốt
\(\frac{2^2.3^3.5^7}{2^3.3^4.5^6}=\frac{1.1.5}{2.3.1}=\frac{5}{6}\)
Làm tương tự
\(A=\frac{15.39}{9.25}=\frac{3.5.3.13}{3.3.5.5}=\frac{13}{5}\)
\(B=\frac{21-21.5}{2^2}=\frac{21.\left(1-5\right)}{4}=\frac{21.\left(-4\right)}{4}=-21\)
\(C=\frac{1.2.3....20}{2.4...40}=\frac{1.2.3...20}{2\left(1.2.3...20\right)}=\frac{1}{2}\)
Ta có :
\(A=\frac{15.39}{9.25}=\frac{3.5.39}{3^2.5^2}=\frac{39}{3.5}=\frac{39}{15}\)
\(B=\frac{21-21.5}{2^2}=\frac{21.\left(1-5\right)}{4}=\frac{21.\left(-4\right)}{4}=\frac{21.\left(-1\right)}{1}=-21\)
\(C=\frac{1.2.3...20}{2.4.6...40}=\frac{\left(1.3.5...19\right).\left(2.4.6...20\right)}{\left(2.4.6...20\right).\left(22.24.26...40\right)}=\frac{1.3.5.19}{22.24.26...40}\)
\(A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\)
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{2}-\frac{1}{100}\)
\(A=\frac{49}{100}\)
\(B=\frac{5}{1.4}+\frac{5}{4.7}+...+\frac{5}{100.103}\)
\(B=\frac{5}{3}.\left(\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{100.103}\right)\)
\(B=\frac{5}{3}.\left(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{100}-\frac{1}{103}\right)\)
\(B=\frac{5}{3}.\left(\frac{1}{1}-\frac{1}{103}\right)\)
\(B=\frac{510}{103}\)
P=1-\(\frac{1}{2}\)+\(\frac{1}{2}\)-\(\frac{1}{4}\)+...........+\(\frac{1}{46}\)-\(\frac{1}{56}\)
P=1-\(\frac{1}{56}\)
P=\(\frac{55}{56}\)
\(a,\frac{6}{10}=\frac{3}{5};\frac{6}{16}=\frac{3}{8};-\frac{15}{20}=\frac{3}{4};-\frac{10}{30}=\frac{-1}{3}\)
\(b,\frac{42}{28}=\frac{3}{2};\frac{54}{-21}=-\frac{10}{7};-\frac{27}{33}=-\frac{9}{11};\frac{25}{14}=\frac{25}{14}\)
\(c,\frac{125}{1000}=\frac{1}{8};\frac{198}{126}=\frac{11}{7};\frac{3}{243}=\frac{1}{81};\frac{103}{2090}=\frac{103}{2090}\)
\(d,\frac{2.3}{9.14}=\frac{28}{3}\)
Rút gọn
a, \(\frac{4.7}{9.32}\)
b, \(\frac{3.21}{14.15}\)
c, \(\frac{2.5.13}{26.35}\)
[ . là nhân nha ]
a, \(\frac{4.7}{9.32}\)= \(\frac{7}{9.8}\)=\(\frac{7}{72}\)
\(\frac{2.4}{6.18}=\frac{1.2}{3.9}=\frac{2}{27}\)
\(\frac{3.5.7}{6.9.14}=\frac{1.5.7}{2.9.2}=\frac{35}{36}\)
\(\frac{4.7-4.5}{64}=\frac{4\left(7-5\right)}{64}=\frac{8}{64}=\frac{1}{8}\)
a, \(\frac{2.4}{6.18}\)
\(=\frac{2.2.2}{2.3.2.9}=\frac{2}{27}\)
P/s: Trl từng câu :)