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a(b-c-d)-a(b+c-d)=a(b-c-d-b+c-d)=a[(b-b)-(c-c)-(d+d)]=2[0-2d]=2*(-2d)=2(1+d)
1) -a(-a+c-d)-(c-a+d)
=ad-ac+a2-c+a-d
2) -(a+b)-(c+d)+(a-b-c-d)
=-a-b-c-d+a-b-c-d
=-2b-2c-2d
3) a(b-c-a)-a(b+c-d)
=-ac+ab-a2+ad-ac-ab
=ad-2ac-a2
- (a + b - c) + (b - c + d) - (-a + b + d)
= -a -b + c + b - c + d + a - b - d
= -b
-(a+b-c+d)+(a-b-c-d)=-a-b+c-d+a-b-c-d=(-a+a)-(b+b)+(c-c)-(d+d)=0-2b+0-2d=-2b+(-2)d=-2(b+d)
-(a+b-c+d)+(a-b-c-d)
= -a-b+c-d+a-b-c-d
= -2b-2d
Nhấn đúng cho mk nha!!!!!!!!!!!
1) \(=ac+ad+bc+bd-ab-ac-db-dc=ad+bc-dc-ab=d\left(a-c\right)-b\left(a-c\right)=\left(a-c\right)\left(d-b\right)\)
2) \(=ac-ad+bc-bd-ac-ad+bc+bd=2bc-2ad=2\left(bc-ad\right)\)
3) \(\left(a+b\right)\left(a+b\right)-\left(a-b\right)\left(a-b\right)=a^2+2ab+b^2-a^2+2ab-b^2=4ab\)
\(\text{- ( a - b - c ) + ( b - c + d) - ( -a + b + d) }\)
\(=-a+b+c+b-c+d+a-b-d\)
\(=\left(-a+a\right)+\left(b+b-b\right)+\left(c-c\right)+\left(d-d\right)\)
\(=0+b+0+0\)
\(=b\)
\(\left(a+b\right)\left(c-d\right)-\left(a-b\right)\left(c+d\right)\)
\(=\left(ac-ab+bc-bd\right)-\left(ac+ad-bc-bd\right)\)
\(=ac-ad+bc-bd-ac-ad+bc+bd\)
\(=2bc-2ad\)
\(=2\left(bc-ad\right)\)