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a. -1-(5-x)=-3
5-x=(-1)-(-3)
5-x=2
x=5-2
x=3
b. 132-(x+5)=-24
x+5=132-(-24)
x+5=156
x=156-5
x=151
c. 3.(x-2)+2x-15=-1
3x-6+2x-15=-1
3x+(-6)+2x+(-15)=-1
5x+(-21)=-1
5x=(-1)-(-21)
5x=20
x=20:5
x=4
X : 0,25 + X : 0,2 + X : 0,5 = 132
\(X\times4+X\times5+X\times2=132\)
\(X\times\left(4+5+2\right)=132\)
\(X\times11=132\)
\(X=132\div11=12\)
Ko biết ##########################################################
a) n = 32 x (132 - 247) - 132 x (32 - 247)
n = 32 x 132 - 32 x 247 - 132 x 32 - 132 x 247
n = 32 x (132 - 247 - 132) - 132 x 247
n = 32 x (-247) - 132 x 247
n = 32 x (-247) - (-132) x (-247)
n = 32 x (-247) + 132 x (-247)
n = (-247) x (32 + 132)
n = (-247) x 164
n = -40508
b) 3n + 6 \(⋮\)n + 1
=> (3n + 1) + 5 \(⋮\)n + 1
=> 5 \(⋮\)n + 1
=> n + 1 \(\in\)Ư(5) = {1;5}
=> n \(\in\){0;4}
Ta có:
(1/2 + 1/4 + 1/8 + 1/16) = 8/16 + 4/16 + 2/16 + 1/16 = 15/16.
1/2 + 1/6 + 1/12 + 1/20 +…+ 1/132 = 1/(1.2) + 1/(2.3) + 1/(3.4) + 1/(4.5) +…+1/(11.12)
= (1 – 1/2) + (1/2 – 1/3) + (1/3 – 1/4) + (1/4 – 1/5) +…+ (1/11 – 1/12)
= 1 – 1/12 = 11/12
Vậy x = (15/16) : (11/12) = 45/44.
(1/2+1/4+1/8+1/16):x=1/2+1/6+1/12+1/20+...+1/132
(1-1/2+1/2-1/4+1/4-1/8+1/8-1/16):x=1/1x2+1/2x3+1/3x4+1/4x5+...+1/11x12
(1-1/16):x=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/11-1/12
15/16:x=1-1/12
15/16:x=11/12
x=15/16:11/12
x=45/44
3 ( x + 4 ) + 2 ( 5 - x ) = 132
<=>3x+12+10-2x=132
<=>3x-2x=132-12-10
<=>x=110
vậy x=110
k mk nha bạn
- dễ mà VD : tách 1/30 thành 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 + 1/9.10 + 1/10.11 +1/11.12 - x =2/3
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
\(x\left(x+1\right)=132\)
\(=x^2+x-132=0\)
\(=>x\left(x+1\right)-132=0\)
ta có: \(x.\left(x+1\right)=132\)
\(\Rightarrow x^2+x=132\)
\(\Rightarrow x=11\)
Thử lại: \(11^2+11=121+11=131\)