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864.48-432.96/864.48-432
= ( 864.48)-(432.96) / ( 864.48)-(432.1)
= 41472-41472 / 40608 - 432
= 0/ 40376
= 0
\(\frac{864.48-432.96}{864.48+432}\)
\(=\frac{864.48-432.2.48}{864.48+432}\)
\(=\frac{864.48-864.48}{864.48+432}\)
\(=\frac{0}{864.48+432}\)
\(=0\)
Học tốt
\(\frac{8x75x3+6x25x4-240}{15x2x6+18x16x5}\)
=\(\frac{2x4x5x5x3x3+2x3x5x5x4-3x2x4x2x5}{3x5x2x2x3+3x2x3x2x2x4x5}\)
=\(\frac{2x3x4x5x\left(5x3+5-2\right)}{3x2x3x5x2x\left(1+2x4\right)}\)
=\(\frac{2x18}{3x9}\)
=\(\frac{4}{3}\)
TL:
\(\frac{123}{123}\)+ \(\frac{4}{5}\) x \(\frac{123}{123}\)+ \(\frac{4}{5}\)
\(=\)\(\frac{123}{123}\)\(+\)\(\frac{123}{123}\)x \(\frac{4}{5}\)\(+\)\(\frac{4}{5}\)
\(=\)\(1\)\(x\)\(1\)
\(=\)\(1\).
~HT~
Các bạn giải chi tiết vào , không giải chi tiết cho sai luôn và có đáp án đúng mà trình bày không chi tiết thì cho sai luốn nha các bạn !
\(P=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}=\frac{1}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{97.99}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{99}\right)=\frac{1}{2}.\frac{98}{99}=\frac{49}{99}\)
\(8\frac{1}{6}:2\frac{1}{2}=\frac{49}{6}:\frac{5}{2}=\frac{98}{30}=\frac{49}{15}\)
\(1\frac{3}{10}:5\frac{7}{8}=\frac{13}{10}:\frac{47}{8}=\frac{104}{470}=\frac{52}{235}\)
Bn như thần ý nhỉ :)
trả lời:
8x1/6:2x1/2
=4/3:1
=4/3
1x3/10:5x7/8
=3/10:35/8
=12/175
chúc học tốt
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{y\times\left(y+1\right)}=\frac{996}{997}\)
\(\Leftrightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{y}-\frac{1}{y+1}=\frac{996}{997}\)
\(\Leftrightarrow1-\frac{1}{y+1}=\frac{996}{997}\)
\(\Leftrightarrow\frac{1}{y+1}=1-\frac{996}{997}=\frac{1}{997}\)
\(\Leftrightarrow y+1=997\Leftrightarrow y=996\)
Vậy y = 996
a) \(\frac{5}{1.4}+\frac{5}{4.7}+\frac{5}{7.10}+.....+\frac{5}{27.30}\)
\(=\frac{5}{3}\left(\frac{1}{1.4}+\frac{1}{4.7}+........+\frac{1}{27.30}\right)\)
\(=\frac{5}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.....+\frac{1}{27}-\frac{1}{30}\right)\)
\(=\frac{5}{3}\left(1-\frac{1}{30}\right)\)
\(=\frac{5}{3}.\frac{29}{30}=\frac{29}{36}\)
Đặt \(A=\frac{12}{3\cdot5}+\frac{12}{5\cdot7}+\frac{12}{7\cdot9}+....+\frac{12}{97\cdot99}\)
\(2A=\frac{12}{3}-\frac{12}{5}+\frac{12}{5}-\frac{12}{7}+...+\frac{12}{97}-\frac{12}{99}\)
\(2A=\frac{12}{3}-\frac{12}{99}\)
\(A=\frac{128}{33}\cdot\frac{1}{2}=\frac{64}{33}\)
\(=\frac{432x2x48-432x96}{846x48x432}\)
\(=\frac{432x96-432x96}{846x48x432}\)
\(=\frac{0}{846x48x432}\)
\(=0\)
\(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot2\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot96-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{96\cdot\left(432-432\right)}{864\cdot48\cdot432}\)
\(=0\)