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a) 225 - ( -45 ) - 100
=225+45-100
=270-100
=170
b) | - 25 | + | 25 | - ( - 50 )
=25+25+50
=50+50
=100
c) 25 - 5. [( -4 )2 + 4 ] . ( -1)5
=25-5.[(-16)+4].(-5)
=25-5.(-12).(-5)
=25-(-60).(-5)
=25-300
=-275
tick nha
a/[25-(-75)]+32-(32+55)
=[25+75]+32-(32+55)
=25+75+32-32-55
=[25+75]+[32-32]-55
=100+0-55
=100-55
=45
a) 50+3x(25-16)2+150
=50+3x92+1
=50+3x81+1
=50+243+1
=294
b)22x52-35/32
=(2x5)2-35-2
=102-33
=100-27
=73
c)80-[130-(12-4)2 ]
=80-[130-82 ]
=80-[130-64]
=80-66
=14
d)100:[2x(52-35-8)]
=100:[2x9]
=100:18
=100/18
e)24:{300:[375-(150+15x5)]}
=24:{300:[375-(150+75)]}
=24:{300:[375-225]}
=24:{300:50}
=24:6
=4
\(A=\left(\frac{21}{5}-\frac{3}{5}\right):\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}:\frac{16}{8}:\frac{9}{10}\)
\(A=\frac{18}{5}\times\frac{8}{16}\times\frac{10}{9}\)
\(A=\frac{9}{5}\times\frac{8}{8}\times\frac{10}{9}\)
\(A=\frac{72}{40}\times\frac{10}{9}\)
\(A=\frac{8}{4}\times\frac{1}{1}\)
\(A=\frac{8}{9}\)
\(B=\left(1\frac{1}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(2+\frac{14}{16}\right)\)
\(B=\left(\frac{21}{20}+\frac{36}{100}\right):\frac{84}{25}:\left(\frac{32}{16}+\frac{14}{16}\right)\)
\(B=\left(\frac{105}{100}+\frac{36}{100}\right):\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}:\frac{84}{25}:\frac{46}{16}\)
\(B=\frac{141}{100}\times\frac{25}{84}\times\frac{16}{46}\)
\(B=\frac{141}{4}\times\frac{1}{84}\times\frac{16}{46}\)
\(B=\frac{141}{336}\times\frac{16}{46}\)
\(B=\frac{141}{21}\times\frac{1}{46}\)
\(B=\frac{141}{966}\)
Tính:
\(A=\left(-2\right)^3.\left(-5\right)^2-41.\left(-8\right)\)
\(=\left(-8\right).25-41.\left(-8\right)\)
\(=\left(-8\right).\left(25-41\right)\)
\(=\left(-8\right).\left(-16\right)\)
\(=128\)
\(B=2018-2018:\left(4^2-3^2\right)\)
\(=2018-2018:\left(16-9\right)\)
\(=2018-2018:5\)
\(=2018-403,6\)
\(=1614,4\)
\(C=\left(-5\right).\left(-25\right).\left(-50\right)+5.25.50\)
\(=\left(-6250\right)+6250\)
\(=0\)
a)(357.252.714):510=(57.77.54.714):510=(511.721):510=5.721
b)=215.520.212.54 /22.52=227.524/22.52=225.522
\(\left(-2\right)^3.\left(-5\right)^2-41.\left(-8\right)\)
\(=\)\(-8.25-41.\left(-8\right)\)
\(=-8\left(25-41\right)\)
\(=-8.\left(-16\right)\)
\(=128\)
\(2018-1018:\left(4^2-3^2\right)\)
\(=2018-1018:7\)
\(=2018-\frac{1018}{7}\)
\(=\frac{13108}{7}\)
\(-5.\left(-25\right).\left(-50\right)+5.25.50\)
\(=-6250+6250\)
\(=0\)
Ta có :
a, \(25.4.100.8\)
\(=\left(25.4\right).100.8\)
\(=100.100.8\)
\(=80000\)
b, \(50.0,1.5^2\)
\(=5.1.5^2\)
\(=5^3\)
\(=125\)
a ) \(25.4.100.8=\left(25.4\right).100.8\)
\(=100.100.8\)
\(=80000\)
b ) \(50.0,1.5^2=5.1.5^2\)
\(=5^3=125\)