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= 1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90
= 1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90
= 9 – (1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90)
= 9 – [1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+1/(5x6)+1/(6x7)+1/(7x8)+1/(8x9)+1/(9x10)]
= 9 – ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)
= 9 – (1 – 1/10) = 9 – 9/10 = 81/10
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+...+\frac{89}{90}\)
\(=\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+\left(1-\frac{1}{12}\right)+...+\left(1-\frac{1}{90}\right)\)
\(=\left(1-\frac{1}{1.2}\right)+\left(1-\frac{1}{2.3}\right)+\left(1-\frac{1}{3.4}\right)+...+\left(1-\frac{1}{9.10}\right)\)
\(=\left(1+1+1+...+1\right)-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)
9 số 1
\(=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=9-\left(1-\frac{1}{10}\right)\)
\(=9-\frac{9}{10}\)
\(=\frac{81}{10}\)
Ủng hộ mk nha ^-^
232 x 68 + 232 x 31 + 232
= 232 x ( 68 + 31 + 1 )
= 232 x 100
= 23200
29+29+......+29+83+...+83
=29.17+83.29
=29(17+83)
=29.100
=2900
tick bạn
i don't now
mong thông cảm !
...........................
\(29.\left(79-34\right)-79.\left(29+34\right)\)
\(=29.79-29.34-79.29-79.34\)
\(=0-34.\left(29+79\right)\)
\(=0-34.108\)
\(=0-3672\)
\(=-3672\)
\(29.\left(79-34\right)-79.\left(29+34\right)\)
\(=29.79-29.34-79.29-79.34\)
\(=\left(29.79-79.29\right)-34.\left(29+79\right)\)
\(=0-34.108\)
\(=0-3672\)
\(=-3672\)
173 - 536 + 173 - [ 29 - 29 + 526 ]
= 173 - 536 + 173 - 526
= ( 173 + 173 ) - 536 - 526
= 346 - 536 - 526
= -716
a) 45 - 5 (10 + 11)= 45 - 50 - 55 = -60
b) 29 . 6 - 9 . ( 10 + 6 ) = 6 . (29 - 9) - 9 . 10 = 6 . 20 - 9 . 10 = 12. 10 - 9 . 10 =
10 . (12 - 9) = 30
Sân si tí...
Ta có: \(29\cdot\left(232+68\right)+71\cdot\left(232+29\right)\)
\(=29\cdot232+29\cdot68+71\cdot232+29\cdot71\)
\(=\left(29\cdot232+71\cdot232\right)+\left(29\cdot68+29\cdot71\right)\)
\(=232\cdot100+29\cdot139\)
\(=23200+4031\)
\(=27231\)