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\(\frac{3}{1\times2}+\frac{3}{2\times3}+...+\frac{3}{5\times6}\)
\(=3\left(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{5\times6}\right)\)
\(=3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\right)\)
\(=3\left(1-\frac{1}{6}\right)=3\times\frac{5}{6}=\frac{5}{2}\)
\(\frac{11}{2}\): \(\frac{11}{3}\): \(\frac{11}{4}\)
= \(\frac{11}{2}\): ( \(\frac{3}{11}\): \(\frac{4}{11}\)
Bài làm :
Ta có :
\(A=\frac{1}{2}\div\frac{3}{4}+\frac{1}{6}\div\frac{3}{4}=\left(\frac{1}{2}+\frac{1}{6}\right)\div\frac{3}{4}=\frac{8}{9}\)
Bài làm :
\(a,\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}\)
\(=\left(\frac{1}{2}+\frac{1}{6}\right):\frac{3}{4}\)
\(=\frac{2}{3}:\frac{3}{4}\)
\(=\frac{8}{9}\)
Bài làm
\(\frac{27}{8}-\frac{7}{3}+\frac{4}{3}-2\)
=\(\frac{27}{8}-\left(\frac{7}{3}-\frac{4}{4}\right)-2\)
=\(\frac{27}{8}-1-2\)
=\(\frac{27}{8}-\frac{8}{8}-\frac{16}{8}\)
=\(\frac{3}{8}\)
`3/4 +1/2 +1/4 +3/2`
`= (3/4+1/4)+(1/2+3/2)`
`= 4/4 + 4/2`
`=1+2`
`=3`
3/4+1/2+1/4+3/2
=(3/4+1/4)+(1/2+3/2)
=1+2
=3