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a) Ta có:
\(\frac{2,5}{3,5}=\frac{25}{35}=\frac{5}{7}\); \(4:12=\frac{4}{12}=\frac{1}{3}\)
Các tỉ số = nhau trong các tỉ số đã cho là: \(\frac{1}{3}=4:12\)
Các tỉ lệ thức lập được là: \(\frac{1}{4}=\frac{3}{12};\frac{3}{1}=\frac{12}{4};\frac{3}{12}=\frac{1}{4}\)
b) Ta có:
\(\frac{18}{42}=\frac{3}{7}\); \(\frac{-2}{-4,5}=\frac{2}{4,5}=\frac{20}{45}=\frac{4}{9}\); \(21:49=\frac{21}{49}=\frac{3}{7}\)
Các tỉ số = nhau trong các tỉ số đã cho là:\(\frac{18}{42}=21:49\)
Các tỉ lệ thức lập được là: \(\frac{18}{21}=\frac{42}{49};\frac{42}{18}=\frac{49}{21};\frac{42}{49}=\frac{18}{21}\)
\(\frac{x}{4}=\frac{16}{128}\)
\(x=\frac{16\times4}{128}\)
\(x=\frac{1}{2}\)
***
\(1^5_6=-\frac{x}{5}\)
\(\frac{x}{5}=-\frac{11}{6}\)
\(x=-\frac{11\times5}{6}\)
\(x=-\frac{55}{6}\)
***
\(4,25\div8=3,5\div x\)
\(\frac{3,5}{x}=\frac{4,25}{8}\)
\(x=\frac{3,5\times8}{4,25}\)
\(x=\frac{112}{17}\)
a) \(\frac{x}{4}=\frac{16}{128}=\frac{1}{8}\)
=> 8x = 4
=> x = 4 : 8 \(=\frac{1}{2}\)
b) \(1\frac{5}{6}=\frac{-x}{5}\)
=> \(\frac{11}{6}=\frac{-x}{5}\)
=> 11.5 = -x.6
=> 55 = x.(-6)
=> \(x=\frac{55}{-6}=-\frac{55}{6}\)
c) 4,25 : 8 = 3,5 : x
=> \(\frac{17}{4}.\frac{1}{8}=\frac{7}{2}:x\)
=> \(\frac{17}{32}=\frac{7}{2}:x\)
=> \(x=\frac{7}{2}:\frac{17}{32}\)
=> \(x=\frac{7}{2}.\frac{32}{17}=\frac{112}{17}\)
a.
\(\frac{x}{4}=\frac{3}{2}\)
\(x=\frac{3}{2}\times4\)
\(x=6\)
b.
\(\frac{x}{16}=\frac{9}{x}\)
\(x\times x=16\times9\)
\(x^2=144\)
\(x^2=\left(\pm12\right)^2\)
\(x=\pm12\)
Vậy \(x=12\) hoặc \(x=-12\)
c.
\(\frac{x^2}{6}=\frac{24}{25}\)
\(x^2=\frac{24}{25}\times6\)
\(x^2=\frac{144}{25}\)
\(x^2=\left(\pm\frac{12}{5}\right)^2\)
\(x=\pm\frac{12}{5}\)
Vậy \(x=\frac{12}{5}\) hoặc \(x=-\frac{12}{5}\)
d.
\(\frac{72-9}{7}=\frac{x-40}{9}\)
\(\frac{x-40}{9}=\frac{63}{7}\)
\(x-40=\frac{63}{7}\times9\)
\(x-40=81\)
\(x=81+40\)
\(x=121\)
a) \(\frac{x}{7}=\frac{18}{14}\)
\(\Rightarrow\frac{x}{7}=\frac{9}{7}\)
\(\Rightarrow x=7\)
Vậy x=7
b)\(6:x=1\frac{3}{4}:5\)
\(\frac{6}{x}=\frac{7}{4}:5\)
\(\frac{6}{x}=\frac{7}{20}\)
\(\Rightarrow6.20=7x\)
\(\Rightarrow120=7.x\)
\(\Rightarrow x=\frac{120}{7}\)
Vậy \(x=\frac{120}{7}\)
a: 2x+3>=1
=>2x>=-2
hay x>=-1
b: -3x+4<=5
=>-3x<=1
hay x>=-1/3
c: 3x+5<4-2x
=>5x<-1
hay x<-1/5
d: 1/2x+7>-5/2
=>1/2x>-19/2
hay x>-19
b. (x+1)(1/10+1/11+1/12-1/13-1/14)=0
x+1=0 (vì : 1/10+1/11+1/12-1/13-1/14>0)
x=-1
a) \(\frac{2}{\left(x+2\right).\left(x+4\right)}+\frac{4}{\left(x+4\right).\left(x+8\right)}+\frac{6}{\left(x+8\right).\left(x+14\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow\frac{1}{x+2}-\frac{1}{x+4}+\frac{1}{x+4}-\frac{1}{x+8}+\frac{1}{x+8}-\frac{1}{x+14}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow\frac{1}{x+2}-\frac{1}{x+14}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow\frac{x+14}{\left(x+2\right).\left(x+14\right)}-\frac{x+2}{\left(x+2\right).\left(x+14\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow\frac{x+14-x+2}{\left(x+2\right).\left(x+14\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow\frac{16}{\left(x+2\right).\left(x+4\right)}=\frac{x}{\left(x+2\right).\left(x+14\right)}\)
\(\Rightarrow x=16\)
Vậy x = 16
\(b,\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
\(\Leftrightarrow x+1=0\left(vì\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\right)\)
\(\Leftrightarrow x=-1\)
\(\text{Vậy }x=-1\)
a)\(\frac{x}{4}=\frac{16}{128}\)
\(\frac{x}{4}=\frac{1}{8}\)
Suy ra:\(8x=4\)
\(x=\frac{1}{2}\)
b)\(1\frac{5}{6}=-\frac{x}{5}\)
\(\frac{11}{6}=-\frac{x}{5}\)
Suy ra:\(-6x=55\)
\(x=\frac{55}{6}\)
c)4,25:8=-3,5:x
\(-3,5x=\frac{17}{32}\)
\(x=-\frac{17}{112}\)
thank yooooooo