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Bài 1:
\(\dfrac{2}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{2}{5}\)
=\(\dfrac{40}{60}\) + \(\dfrac{45}{60}\) - \(\dfrac{24}{60}\)
= \(\dfrac{61}{60}\)
b; \(\dfrac{12}{13}\) x \(\dfrac{3}{4}\) - \(\dfrac{7}{13}\)
= \(\dfrac{9}{13}\) - \(\dfrac{7}{13}\)
= \(\dfrac{2}{13}\)
c; \(\dfrac{15}{17}\) : \(\dfrac{19}{34}\) - \(\dfrac{17}{19}\)
= \(\dfrac{15}{17}\) x \(\dfrac{34}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{30}{19}\) - \(\dfrac{17}{19}\)
= \(\dfrac{13}{19}\)
Bài 2:
a; \(\dfrac{x}{5}\) x \(\dfrac{3}{7}\) = \(\dfrac{9}{35}\)
\(\dfrac{x}{5}\) = \(\dfrac{9}{35}\) : \(\dfrac{3}{7}\)
\(\dfrac{x}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) x 5
\(x\) = 3
1.
\(\frac{5}{3}-\frac{1}{4}+\frac{1}{3}-\frac{3}{4}\)
\(=\left(\frac{5}{3}+\frac{1}{3}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1=1\)
\(\frac{2}{7}\cdot\frac{1}{5}+\frac{2}{7}\cdot\frac{4}{5}=\frac{2}{7}\cdot\left(\frac{1}{5}+\frac{4}{5}\right)=\frac{2}{7}\cdot1=\frac{2}{7}\)
#Louis
\(1.a)\frac{5}{3}-\frac{1}{4}+\frac{1}{3}-\frac{3}{4}\)
\(=\left(\frac{5}{3}+\frac{1}{3}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1\)
\(=1\)
\(b)\frac{2}{7}\times\frac{1}{5}+\frac{2}{7}\times\frac{4}{5}\)
\(=\frac{2}{7}\times\left(\frac{1}{5}+\frac{4}{5}\right)\)
\(=\frac{2}{7}\times1\)
\(=\frac{2}{7}\)
\(2.a)\frac{5}{6}+\frac{7}{12}-\frac{2}{9}\)
\(=\frac{30}{36}+\frac{21}{36}-\frac{8}{36}\)
\(=\frac{43}{36}\)
\(b)\frac{4}{9}\times\frac{5}{8}+\frac{1}{6}\)
\(=\frac{5}{18}+\frac{1}{6}=\frac{5}{18}+\frac{3}{18}\)
\(=\frac{8}{18}=\frac{4}{9}\)
\(c)2:\frac{3}{11}-\frac{13}{12}\)
\(=2\times\frac{11}{3}-\frac{13}{12}\)
\(=\frac{22}{3}-\frac{13}{12}\)
\(=\frac{25}{4}\)
A, X x 3/5 + X x 7/5 = 9/4 B, X - 4/7 = 1/5 : 7/2
<=> X x (3/5 + 7/5) = 9/4 <=> X - 4/7 = 2/35
<=> X x 2 = 9/4 <=> X = 2/35 + 4/7 <=> X = 22/35
<=> X= 9/4 : 2 <=> X = 9/8
#HT#
\(a,x.\frac{3}{5}+x.\frac{7}{5}=\frac{9}{4}\)
\(\Leftrightarrow x.\left(\frac{3}{5}+\frac{7}{5}\right)=\frac{9}{4}\)
\(\Leftrightarrow x.2=\frac{9}{4}\)
\(\Leftrightarrow x=\frac{9}{8}\)
\(b,x-\frac{4}{7}=\frac{1}{5}:\frac{7}{2}\)
\(\Leftrightarrow x-\frac{4}{7}=\frac{2}{35}\)
\(\Leftrightarrow x=\frac{22}{35}\)
tính giá trị biểu thức P = A x 100 + B x 10 + C
a ] A = 5 ,B = 7 và C = 8
=> P = 5 x 100 + 7 x 10 + 8 =578
b ] A = 4 ,B = 0 Và c = 3
=> P = 4 x 100 + 0 x 10 + 3 =403
c ] A = 1 ,B = 2 VÀ C = 0
=> P = 1 x 100 + 2 x 10 + 0 = 120
mk làm hơi ngăn gọi bn thông cảm nha
a)P=5 x 100 + 7 x 10 + 8=578
b)P=4 x 100 + 0 x 10 + 3=403
c) P=1 x 100 + 2 x 10 + 0=120
a) \(\frac{3}{5}+\frac{2}{7}\times\frac{7}{8}=\frac{3}{5}+\frac{2}{8}=\frac{3}{5}+\frac{1}{4}=\frac{12}{20}+\frac{5}{20}=\frac{17}{20}\)
b) \(1-\frac{3}{4}:\frac{5}{6}=1-\frac{3}{4}\times\frac{6}{5}=1-\frac{18}{20}=1-\frac{9}{10}=\frac{10}{10}-\frac{9}{10}=\frac{1}{10}\)
1.
a. = 135 x ( 6 + 4 )
= 135 x 10
= 1350
b. = 432 x (4 + 3 + 2 + 1)
= 432 x 10
= 4320
2.
a. X x (2 + 3 + 4) = 234
X x 9 = 234
X = 234 : 9
X = 26
b. X x (1 + 2) = 12
X x 3 = 12
X = 12 : 3
X = 4
c. X x (1 + 3 + 5) = 135
X x 9 = 135
X = 135 : 9
X = 15
A)135x(4+6)=135x10=1350
B)432x(4+3+2+1)=432x10=4320
A)Xx(2+3+4)=234
Xx9=234
X=36
\(4\cdot3,7\cdot2,5=4\cdot2,5\cdot3,7=10\cdot3,7=37\)
\(1,25\cdot0,7\cdot8=1,25\cdot8\cdot0,7=10\cdot0,7=7\)
\(3,2\cdot0,7+3,2\cdot0,2+3,2\cdot0,1=3,7\left(0,7+0,2+0,1\right)\)
\(=3,2\cdot10=32\)
=a + (1/2x2/5+4/5+1)
=a+2 =136
a =136-2
a =134