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\(\left(\sqrt{4,5}-\frac{1}{2}.\sqrt{72}+5\sqrt{\frac{1}{2}}\right).\left(42\sqrt{\frac{25}{6}}-10\sqrt{\frac{3}{2}}-12\sqrt{\frac{98}{3}}\right)\)
=\(\left(\frac{3\sqrt{2}}{2}-3\sqrt{2}+\frac{5\sqrt{2}}{2}\right).\left(35\sqrt{6}-5\sqrt{6}-28\sqrt{6}\right)\)
=\(\left(\frac{3\sqrt{2}-6\sqrt{2}+5\sqrt{2}}{2}\right).2\sqrt{6}\)
=\(2\sqrt{2}.\sqrt{6}=4\sqrt{3}\)
a) \(2\sqrt{50}-3\sqrt{32}-\sqrt{162}+5\sqrt{98}\)
=\(2.5\sqrt{2}-3.4\sqrt{2}-9\sqrt{2}+5.7\sqrt{2}\)
= \(10\sqrt{2}-12\sqrt{2}-9\sqrt{2}+35\sqrt{2}\)
= \(24\sqrt{2}\)
b) \(\sqrt{8+2\sqrt{7}}+\sqrt{11-4\sqrt{7}}\)
= \(\sqrt{7+2\sqrt{7}+1}+\sqrt{7-4\sqrt{7}+4}\)
= \(\sqrt{\left(\sqrt{7}+1\right)^2}+\sqrt{\left(\sqrt{7}-2\right)^2}\)
= \(\sqrt{7}+1+\sqrt{7}-2\)
= \(2\sqrt{7}-1\)
c) \(\dfrac{10}{\sqrt{5}}+\dfrac{8}{3+\sqrt{5}}-\dfrac{\sqrt{18}-3\sqrt{5}}{\sqrt{2}-\sqrt{5}}\)
= \(2\sqrt{5}+6-2\sqrt{5}-3\)
= 3
a) \(5\sqrt{\frac{1}{5}}+\frac{1}{2}\sqrt{20}+\sqrt{5}\)
\(=\sqrt{25.\frac{1}{5}}+\sqrt{\frac{1}{4}.20}+\sqrt{5}\)
\(=\sqrt{5}+\sqrt{5}+\sqrt{5}\)
\(=3\sqrt{5}\)
b) \(\sqrt{20}-\sqrt{45}+3\sqrt{18}+\sqrt{72}\)
\(=\sqrt{4.5}-\sqrt{5.9}+3\sqrt{18}+\sqrt{8.9}\)
\(=2\sqrt{5}-3\sqrt{5}+3\sqrt{18}+3\sqrt{8}\)
\(=2\sqrt{5}-3\sqrt{5}+3\sqrt{18}+3\sqrt{8}\)
\(=-\sqrt{5}+3.\left(\sqrt{18}+\sqrt{8}\right)\) (Tới đây không biết làm gì nữa)
b,= \(3\sqrt{25.2}-4\sqrt{4.3}+5\sqrt{36.2}-3\sqrt{9.3}\)
= \(3.5\sqrt{2}-4.2\sqrt{3}-5.6\sqrt{2}-3.3\sqrt{3}\)
=\(15\sqrt{2}-8\sqrt{3}-30\sqrt{2}-9\sqrt{3}\)
a) 2 50 - 3 98 + 4 32 - 5 72
= 10 2 - 21 2 + 16 2 - 30 2
= -25 2