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\(\frac{12}{23}+\frac{24}{23}\) = ?
Trả lời : \(\frac{12}{23}\)+ \(\frac{24}{23}\)= \(\frac{36}{23}\)
\(\frac{77}{23}+\frac{23}{23}\)\(=\frac{77}{23}+1=\frac{100}{23}\)
\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)
\(=\left(\frac{19}{15}-\frac{4}{15}\right)+\left(\frac{31}{23}-\frac{8}{23}\right)\)
\(=\frac{15}{15}+\frac{23}{23}\)
\(=1+1=2\)
\(\frac{19}{15}+\frac{31}{23}-\frac{14}{15}-\frac{8}{23}\)
\(=\frac{19}{15}-\frac{4}{15}+\frac{31}{23}-\frac{8}{23}\)
\(=1+1=2\)
chúc bạn học giỏi
\(\frac{5}{10}< \frac{5}{3}\)
\(\frac{13}{23}< \frac{18}{19}\)
\(\frac{9}{11}>\frac{23}{45}\)
Câu 1:\(\frac{12}{23}\times\frac{9}{28}+\frac{11}{23}\times\frac{9}{28}\)
\(=\frac{9}{28}\times\left(\frac{12}{23}+\frac{11}{23}\right)\)
\(=\frac{9}{28}\times\frac{23}{23}\)
\(=\frac{9}{28}\times1\)
\(=\frac{9}{28}\)
Câu 2:
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)
\(=\left(3+2+2+3\right)+\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)\)
\(=10+\frac{9}{9}\)
\(=10+1\)
\(=11\)
\(\frac{12}{23}x\frac{9}{28}+\frac{11}{23}x\frac{9}{28}=\)\(\left(\frac{12}{23}+\frac{11}{23}\right)x\frac{9}{28}\)\(=\) \(1x\frac{9}{28}=\frac{9}{28}\)
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)\(=\) \(\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)+\left(3+2+3+2\right)\)\(=\) \(1+3+2+3+2=\)\(11\)
Để kết quả của phép tính trên là 0 thì :
\(\frac{32}{46}\)X x - \(\frac{16}{23}\)X \(\frac{21}{23}\)= 0
\(\frac{16}{23}\)X x - \(\frac{16}{23}\)X \(\frac{21}{23}\)= 0
\(\frac{16}{23}\)X ( x - \(\frac{21}{23}\)) = 0
x - \(\frac{21}{23}\)= 0 ( chia cả 2 vế cho \(\frac{16}{23}\))
x = 0 + \(\frac{21}{23}\)
x = \(\frac{21}{23}\)
Vậy x = \(\frac{21}{23}\)
\(\frac{23}{4}+\frac{16}{3}\)
= \(\frac{69}{12}+\frac{64}{12}\)
= \(\frac{133}{12}\)
\(\frac{23}{4}+\frac{16}{3}\)
\(=\frac{23}{4}+\frac{8}{1}\)
\(=\frac{23}{4}+\frac{32}{4}\)
\(=\frac{55}{4}\)
Học tốt
\(\frac{23}{6}:x-\frac{2}{5}=\frac{1}{4}\)
\(\frac{23}{6}:x=\frac{1}{4}+\frac{2}{5}\)
\(\frac{23}{6}:x=\frac{13}{20}\)
\(x=\frac{23}{6}:\frac{13}{20}\)
\(x=\frac{230}{39}\)
~ Thiên mã ~
\(\frac{112}{23}+\frac{345}{23}+\frac{145}{23}+\frac{666}{23}=\left(\frac{112}{23}+\frac{666}{23}\right)+\left(\frac{345}{23}+\frac{145}{23}\right)=\frac{778}{23}+\frac{490}{23}=\frac{1268}{23}\)