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31 tháng 3 2017
a;\(\dfrac{-6}{11}\) : \(\dfrac{12}{55}\) = \(\dfrac{-5}{2}\)
b;\(\dfrac{7}{12}\) + \(\dfrac{5}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{47}{72}\) - \(\dfrac{11}{36}\) = \(\dfrac{25}{72}\)
c;\(\dfrac{13}{10}\) : \(\dfrac{-5}{13}\) = \(\dfrac{-169}{50}\)
d; {\(\dfrac{5}{12}\) + \(\dfrac{5}{11}\) } : { \(\dfrac{5}{3}\) -\(\dfrac{7}{11}\) } = \(\dfrac{115}{132}\) : \(\dfrac{34}{33}\) = \(\dfrac{115}{136}\)
lưu ý mk ko chép đầu bài
VT
31 tháng 3 2017
mình cần gấp lắm đến chiều mai là phải nộp rùi
giúp mình nha thanks cá bạn trước 
ko có tâm trạng mà cười nữa
2 tháng 4 2017
Tìm x biết:
\(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{4}\)
\(\Leftrightarrow\left(4,5-2x\right)=\dfrac{11}{4}:1\dfrac{4}{7}\)
\(\Leftrightarrow4,5-2x=\dfrac{7}{4}\)
\(\Leftrightarrow2x=4,5-\dfrac{7}{4}\)
\(\Leftrightarrow2x=\dfrac{11}{4}\)
Vậy \(x=\dfrac{11}{8}\)
Tìm số nguyên x biết:
Theo đề bài, ta có:
\(4\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
\(\Leftrightarrow-\dfrac{13}{9}\le x\le-\dfrac{11}{18}\) hay \(-\dfrac{26}{18}\le x\le-\dfrac{11}{18}\)
\(\Leftrightarrow-1,\left(4\right)\le x\le-0,6\left(1\right)\)
Mà \(x\in Z\) nên x=-1
Vậy x = -1
Q
7 tháng 4 2017
a, \(\dfrac{3}{4}.x+\dfrac{1}{5}=\dfrac{1}{6}\)
\(\dfrac{3}{4}.x=\dfrac{1}{6}-\dfrac{1}{5}\)
\(\dfrac{3}{4}.x=\dfrac{-1}{30}\)
\(x=\dfrac{-1}{30}:\dfrac{3}{4}\)
\(x=\dfrac{-2}{45}\)
b, \(\left(4\dfrac{1}{2}-\dfrac{2}{5}x\right):\dfrac{7}{4}=\dfrac{11}{14}\)
\(\left(4\dfrac{1}{2}-\dfrac{2}{5}x\right)=\dfrac{11}{14}.\dfrac{7}{4}\)
\(4\dfrac{1}{2}-\dfrac{2}{5}x=\dfrac{11}{8}\)
\(\dfrac{2}{5}x=4\dfrac{1}{2}-\dfrac{11}{8}\)
\(\dfrac{2}{5}x=\dfrac{9}{2}-\dfrac{11}{8}\)
\(\dfrac{2}{5}x=\dfrac{25}{8}\)
\(x=\dfrac{25}{8}:\dfrac{2}{5}\)
\(x=\dfrac{125}{16}\)
18 tháng 3 2018
a)\(x+\dfrac{3}{4}=\dfrac{1}{2}\\ x=\dfrac{1}{2}-\dfrac{3}{4}=\dfrac{2}{4}-\dfrac{3}{4}=-\dfrac{1}{4}\)
b)\(\dfrac{5}{3}.x=\dfrac{4}{7}\\ x=\dfrac{4}{7}:\dfrac{5}{3}=\dfrac{4}{7}.\dfrac{3}{5}=\dfrac{12}{35}\)
c)\(\dfrac{2}{3}:x=\dfrac{-1}{4}\\ x=\dfrac{2}{3}:\dfrac{-1}{4}=\dfrac{2}{3}.\left(-4\right)=-\dfrac{8}{3}\)
d)\(\dfrac{5}{9}-x=\dfrac{4}{3}\\ x=\dfrac{5}{9}-\dfrac{4}{3}=\dfrac{5}{9}-\dfrac{12}{9}=\dfrac{-7}{9}\)
e)\(x+\dfrac{4}{17}=\dfrac{2}{34}\\ x=\dfrac{1}{17}-\dfrac{4}{17}=\dfrac{-3}{17}\)
f)\(3\dfrac{4}{7}:x=11\\ x=\dfrac{25}{7}:11=\dfrac{25}{7}.\dfrac{1}{11}=\dfrac{25}{77}\)
28 tháng 3 2017
a) 11(x-6)= 4x+11
<=> 11x-66= 4x+11
<=>11x-4x= 11+66
<=> 7x= 77
=>x=11
Vậy: x=11
b) \(4\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{2}\right)=\dfrac{13}{3}.\dfrac{-1}{3}=-\dfrac{13}{9}=-1\dfrac{4}{9}\)
\(\dfrac{2}{3}\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{3}{4}\right)=\dfrac{2}{3}.\dfrac{-7}{12}=-\dfrac{7}{18}\)
Vậy: x= -1
15 tháng 5 2022
a: (x+1/2)(2/3-2x)=0
=>x+1/2=0 hoặc 2/3-2x=0
=>x=-1/2 hoặc x=1/3
b: 
c: \(\Leftrightarrow x\cdot\left(\dfrac{13}{4}-\dfrac{7}{6}\right)=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{5}{12}+\dfrac{20}{12}=\dfrac{25}{12}\)
\(\Leftrightarrow x=\dfrac{25}{12}:\dfrac{39-14}{12}=\dfrac{25}{25}=1\)
27 tháng 7 2017
Các bạn ơi,mình ghi thiếu,còn 3 câu nữa nha!!!~~nya
e)| \(\dfrac{5}{2}\)x-\(\dfrac{1}{2}\) |-(-22).\(\dfrac{1}{3}\)(0,75-\(\dfrac{1}{7}\))=\(\dfrac{-5}{13}\):2\(\dfrac{9}{13}\)-0,5.(\(\dfrac{-2}{3}\))
f)| 5x+21 | = | 2x -63 |
g) -45 - |-3x-96 | - 54=-207
Làm ơn giúp mình với ạ!Mình đang cần gấp lắm trong ngày hôm nay ạ!!!Mình xin cảm ơn các bạn nhiều nhiều lắm luôn đó!!!Thank you very much!!!(^-^)
KL
1 tháng 8 2017
a, (\(\dfrac{2}{9}\)(6x - \(\dfrac{3}{4}\)) - 3(\(\dfrac{1}{4}x-\dfrac{1}{5}\)) = \(\dfrac{-8}{15}\)
<=> (\(\dfrac{4}{3}x-\dfrac{1}{6}\)) - (\(\dfrac{3}{4}x-\dfrac{3}{5}\)) = \(\dfrac{-8}{15}\)
<=> \(\dfrac{4}{3}x-\dfrac{1}{6}-\dfrac{3}{4}x+\dfrac{3}{5}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x+\dfrac{13}{30}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x=\dfrac{-8}{15}-\dfrac{13}{30}\)
<=> \(\dfrac{7}{12}x=-\dfrac{29}{30}\)
<=> x = \(-\dfrac{58}{35}\)
@Nguyễn Gia Hân
\(\dfrac{3}{4}\)\(x\) + \(\dfrac{1}{2}\)(\(x+1\)) = \(\dfrac{-11}{4}\)
\(\dfrac{3}{4}x\) + \(\dfrac{1}{2}x\) + \(\dfrac{1}{2}\) = \(\dfrac{-11}{4}\)
\(\dfrac{5}{4}\)\(x\) + \(\dfrac{1}{2}\) = \(\dfrac{-11}{4}\)
\(\dfrac{5}{4}x\) = \(\dfrac{-11}{4}\) - \(\dfrac{1}{2}\)
\(\dfrac{5}{4}x\) = \(-\dfrac{13}{4}\)
\(x\) = - \(\dfrac{13}{4}:\dfrac{5}{4}\)
\(x=-\dfrac{13}{5}\)
Vậy \(x=-\dfrac{13}{5}\)