Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có: x2y+5xy-14y
= y(x2+5x-14)
= y(x+7)(x-2)
x3-5x2-14x
= x(x2-5x-14)
= x(x-7)(x+2)
\(x^2y+5xy-14y\)
\(=x^2y-2xy+7xy-14y\)
\(=xy\left(x-2\right)+7y\left(x-2\right)\)
\(=\left(x-2\right)\left(xy+7y\right)\)
\(x^3-5x^2-14x\)
\(=x^3-7x^2+2x^2-14x\)
\(=x^2\left(x-7\right)+2x\left(x-7\right)\)
\(=\left(x^2+2x\right)\left(x-7\right)\)
\(=x\left(x+2\right)\left(x-7\right)\)
Ta có : x2 - x + 6x - 6
= x(x - 1) + 6(x - 1)
= (x + 6)(x - 1)
b) 5x2 + 5xy - x - y
= 5x(x + y) - (x + y)
= (5x - 1)(x + y)
câu a,b làm như trên. câu c:
c, 7x - 6x2 - 2 = -6x^2 + 7x - 2 = -( 6x^2-3x-4x+2) = -[ 3x ( 2x-1)-2(2x-1)]=-(3x-2)(2x-1)
a/ 5x2-x+5xy-y
= 5x(x+y) - (x+y)
= (5x-1) (x+y)
b) 2xz + 3z + 6y + xz
= ko bt làm
a; x(5x-1)+y(5x-1)
=>( x+y).(5x-1)
b; có ghi sai đề ko vậy ; toàn x vs z thế
\(5x^3-5xy^2+10xy-5x\)
\(=5x\left(x^2-y^2+2y-1\right)\)
\(=5x\left[x^2-y^2+y+y-1\right]\)
\(=5x\left[x^2-y\left(y-1\right)+\left(y-1\right)\right]\)
\(=5x\left[x^2-\left(y+1\right)\left(y-1\right)\right]\)
\(=5x\left[x^2-\left(y^2-1^2\right)\right]\)
\(=5x\left[\left(x-y\right)\left(x+y\right)+1\right]\)
Lâu k làm, sai thông cảm
a,\(x^2y-4y=y\left(x^2-4\right)=y\left(x-2\right)\left(x+2\right)\)
b,\(x^2-y^2-2x+1=\left(x^2-2x+1\right)-y^2\)
\(=\left(x-1\right)^2-y^2\)
\(=\left(x-y+1\right)\left(x-y-1\right)\)
c,\(5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)\)
\(=\left(5x-1\right)\left(x+y\right)\)
x2y - 4y = y( x2 - 4 ) = y( x - 2 )( x + 2 )
x2 - y2 - 2x + 1 = ( x2 - 2x + 1 ) - y2 = ( x - 1 )2 - y2 = ( x - 1 - y )( x - 1 + y )
5x2 + 5xy - x - y = ( 5x2 + 5xy ) - ( x + y ) = 5x( x + y ) - ( x + y ) = ( x + y )( 5x - 1 )
\(1,x^2+5x-6=x^2-x+6x-6=x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x+6\right)\)
\(3,7x-6x^2-2=-6x^2+7x-2=-6x^2+3x+4x-2=3x\left(-2x+1\right)+2\left(2x-1\right)\)
\(=3x\left(1-2x\right)-2\left(1-2x\right)=\left(1-2x\right)\left(3x-2\right)\)
\(2,5x^2+5xy-x-y=5x\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(5x-1\right)\)
a) 5x2 - 5xy - 3x + 3y
= 5x.(x - y) - 3.(x - y)
= (x - y).(5x - 3)
b) x3 - 2x2 - x + 2
= x2.(x - 2) - (x - 2)
= (x - 2).(x2 - 1)
= (x - 2).(x - 1).(x + 1)
a/ 5x2-5xy-3x+3y
=5x.(x-y)-3(x-y)
=(5x-3).(x-y)
b/ x3-2x2-x+2
=x2.(x-2)-(x-2)
=(x2-1).(x-2)
=(x-1).(x+1).(x-2)
a, x2-5xy+2x-10y = (x2 + 2x)-(5xy+10y)
= x(x+2)-5y(x+2)
= (x+2)(x-5y)
b, x2-5x+4 = x2- x - 4x +4
= (x2-x)-(4x-4)
=x(x-1)-4(x-4)
=(x-1)(x-4)
\(a,x^2-5xy+2x-10y\)
\(=\left(x^2-5xy\right)+\left(2x-10y\right)\)
\(=x\left(x-5y\right)+2\left(x-5y\right)\)
\(=\left(x-5y\right)\left(x+2\right)\)
\(b,x^2-5x+4\)
\(=x^2-4x-x+4\)
\(=x\left(x-4\right)-\left(x-4\right)\)
\(=\left(x-1\right)\left(x-4\right)\)
5x2+5xy-x-y
=5x(x+y) - (x+y)
=(x+y)(5x-1)