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5 tháng 10 2020

a) x2-y2-2x+2y

=(x+y)(x-y)-2(x-y)

=(x-y)(x+y-2)

b) 2x + 2y - x2 -xy

=2(x+y) - x(x+y)

=(x+y)(2-x)

c) 3a2 - 6ab + 3b2 - 12c2

= 3(a2+b2) -3(2ab+4c2)

= 3(a2+b2-2ab-4c2)

d) x2 - 25 + y2 + 2xy

= x2 + 2xy + y2 -25

= (x+y)2 - 52

= (x+y+5)(x+y-5)

e) x2y - x3 - 9y + 9x

= (9x - x3)+(x2y -9y)

= x(9-x2)+y(x2 - 9)

= x(9-x2)-y(9-x2)

= (9-x2)(x-y)

f) x2-2x-4y2-4y

= x2-4y2-2(x+2y)

=(x+2y)(x-4y)-2(x+2y)

=(x+2y)(x-4y-2)

câu g trùng với câu e

h) x2(x-1)+16(1-x)

= x2(x-1)-16(x-1)

= (x2-16)(x-1)

= (x+4)(x-4)(x-1)

1 tháng 7 2017

chữ đẹp...rắn đẹp....rùa đẹphaha

26 tháng 6 2016

\(a,x^2-y^2-2x+2y=\left(x^2-y^2\right)-\left(2x-2y\right)=\left(x-y\right)\left(x+y\right)-2\left(x-y\right)=\left(x-y\right)\left(x+y-2\right).\) \(b,2x+2y-x^2-xy=2\left(x+y\right)-x\left(x+y\right)=\left(x+y\right)\left(2-x\right)\)

\(c,3a^2-6ab+3b^2-12c^2=3\left(a^2-2ab+b^2-4c^2\right)=3.\left(\left(a-b\right)^2-\left(2c\right)^2\right)\)

                                                     \(=3\left(a-b-2c\right).\left(a-b+2c\right)\)

\(d,x^2-25+y^2-2xy=\left(x^2-2xy+y^2\right)-5^2=\left(x-y\right)^2-5^2\)

                                           \(=\left(x-y+5\right)\left(x-y-5\right)\)

\(e,a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\left(a+b\right)=\left(a+b\right)\left(a+b-c\right)\)

\(f,x^2-2x-4y^2-4y=\left(x^2-4y^2\right)-\left(2x+4y\right)=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)

                                         \(=\left(x+2y\right)\left(x-2y-2\right)\)

\(h,x^2\left(x-1\right)+16\left(1-x\right)=x^2\left(x-1\right)-16\left(x-1\right)=\left(x-1\right)\left(x^2-16\right)=\)

                                                    \(=\left(x-1\right)\left(x-4\right)\left(x+4\right)\)

a: \(=\dfrac{27a^6b^3\cdot a^2b^6}{a^8b^8}=27b\)

b: \(=3y^2-5x^2y^3-2y^2+3x^2y^3\)

\(=y^2-2x^2y^3\)

c: \(=6x-y+2x^2+3y-2x^2+x\)

\(=7x+2y\)

d: \(=x-y+2y^2-6xy+\dfrac{10x^2}{y}\)

2 tháng 7 2017

a) \(25.\left(x-1\right)^2-16\left(x+y\right)^2\)

= \(\left(5x-5\right)^2-\left(4x+y\right)^2\)

= \(\left(5x-5-4x-y\right)\left(5x-5+4x+y\right)\)

= \(\left(x-y-5\right)\left(9x+y-5\right)\)

b) \(x^3+3x^2+3x+1-27z^3\)

= \(\left(x+1\right)^3-27z^3\)

= \(\left(x+1-3z\right)\left(x^2+x.3z+9z^2\right)\)

c) \(x^2-2xy+y^2-xz+yz\)

= \(\left(x-y\right)^2-z\left(x-y\right)\)

= \(\left(x-y\right)\left(x-y-z\right)\)

d) \(a^3x-ab+b-x\)

= \(x\left(a^3-1\right)-b\left(a-1\right)\)

= \(x\left(a-1\right)\left(a^2+a+1\right)-b\left(a-1\right)\)

= \(\left(a-1\right)\left(a^2x+ax+x-b\right)\)

f) \(x^2+2x-4y^2-4y\)

= \(x^2+2x+1-\left(4y^2+4y+1\right)\)

= \(\left(x+1\right)^2-\left(2y+1\right)^2\)

= \(\left(x+1-2y-1\right)\left(x+1+2y+1\right)\)

= \(\left(x-2y\right)\left(x+2y+2\right)\)

g) \(xy-4+2x-2y\)

= \(y\left(x-2\right)-2\left(x-2\right)\)

= \(\left(x-2\right)\left(y-2\right)\)

a: \(=\left(5x-5\right)^2-\left(4x-4y\right)^2\)

\(=\left(5x-5-4x+4y\right)\cdot\left(5x-5+4x-4y\right)\)

\(=\left(x+4y-5\right)\left(9x-4y-5\right)\)

b: \(=\left(x+1\right)^3-\left(3z\right)^3\)

\(=\left(x+1-3z\right)\left(x^2+2x+1+3xz+3z+9z^2\right)\)

c: \(=\left(x-y\right)^2-z\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-z\right)\)

d: \(=x\left(a^3-1\right)-b\left(a-1\right)\)

\(=x\left(a-1\right)\cdot\left(a^2+a+1\right)-b\left(a-1\right)\)

\(=\left(a-1\right)\left(a^2x+ax+1-b\right)\)

1 tháng 10 2018

d,

\(a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\left(a+b\right)\)

\(=\left(a+b\right)\left(a+b-c\right)\)

Vậy..

1 tháng 10 2018

e

\(x^2-2x-4y^2-4y\)

\(=\left(x^2-2x+1\right)-\left(4y^2+4y+1\right)\)

\(=\left(x-1\right)^2-\left(2y+1\right)^2\)

\(=\left(x-2y-2\right)\left(x+2y\right)\)

28 tháng 9 2019

ko ai thèm trả lời đâu cu

28 tháng 9 2019

a) \(4x^2-6x=2x\left(2x-3\right)\)

b) \(9x^4y^3+3x^2y^4=3x^2y^3\left(3x^2+y\right)\)

c) \(3\left(x-y\right)-5x\left(y-x\right)=3\left(x-y\right)+5x\left(x-y\right)\)

\(=\left(5x+3\right)\left(x-y\right)\)

d) \(x^3-2x^2+5x=x\left(x^2-2x+5\right)\)

e) \(5\left(x+3y\right)-15x\left(x+3y\right)=\left(5-15x\right)\left(x+3y\right)\)

\(=5\left(1-3x\right)\left(x+3y\right)\)

f) \(2x^2\left(x+1\right)-4\left(x+1\right)=\left(2x^2-4\right)\left(x+1\right)\)

\(=\left(\sqrt{2}x-2\right)\left(\sqrt{2}x+2\right)\left(x+1\right)\)

a: \(=3y^2-5x^2y^3-2y^2+3x^2y^3=y^2-2x^2y^3\)

b: \(=6x-y+2x^2+3y^2-2x^2+x=7x-y+3y^2\)

c: \(=x-y+4y^2-6xy+\dfrac{10x^2}{y}\)

 

23 tháng 9 2018

\(a.\left(9x^2y^3-15x^4y^4\right):3x^2y-\left(2-3x^2y\right)y^2\)

\(=3y^2-5x^2y^3-2y^2+3x^2y^3\)

\(=y^2-2x^2y^3\)

\(b.\left(6x^2-xy\right):x+\left(2x^3y+3xy^2\right):xy-\left(2x-1\right)x\)

\(=6x-y+2x^2+3y-2+x\)

\(=2x^2+7x+2y-2\)

\(c.\left(x^2-xy\right):x+\left(6x^2y^5-9x^3y^4+15x^4y^3\right):\dfrac{3}{2}x^2y^3\)

\(=x-y+4y^2-6xy+10x^2\)

23 tháng 9 2018

Oa, giờ mới biết bác cũng ở box Toán :))