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NH
1
HT
13 tháng 6 2016
A, \(x^3-4x^2-9x+36=x^2\left(x-4\right)-9\left(x-4\right)\)
\(=\left(x-4\right)\left(x^2-9\right)=\left(x-4\right)\left(x-3\right)\left(x+3\right)\)
\(b,x^2-y^2-2x-2y=\left(x-y\right)\left(x+y\right)-2\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y-2\right)\)
KC
1
T
28 tháng 7 2018
\(=x^3+3x^2-7x^2-21x+12x+36\)
\(=x^2\left(x+3\right)-7x\left(x+3\right)+12\left(x+3\right)\)
\(=\left(x+3\right)\left(x^2-7x+12\right)\)
\(=\left(x+3\right)\left(x^2-4x-3x+12\right)\)
\(=\left(x+3\right)[x\left(x-4\right)-3\left(x-4\right)]\)
\(=\left(x+3\right)\left(x-4\right)\left(x-3\right)\)
14 tháng 8 2021
1: \(6x^2y-9xy^2+3xy\)
\(=3xy\left(2x-3y+1\right)\)
2: \(\left(4-x\right)^2-16\)
\(=\left(4-x-4\right)\left(4-x+4\right)\)
\(=-x\cdot\left(8-x\right)\)
3: \(x^3+9x^2-4x-36\)
\(=x^2\left(x+9\right)-4\left(x+9\right)\)
\(=\left(x+9\right)\left(x-2\right)\left(x+2\right)\)
14 tháng 8 2021
1) \(6x^2y-9xy^2+3xy=3xy\left(2x-3y+1\right)\)
2) \(\left(4-x\right)^2-16=\left(4-x\right)^2-4^2=\left(4-x-4\right)\left(4-x+4\right)=-x\left(8-x\right)\)
3) \(x^3+9x^2-4x-36\\ =\left(x^3-2x^2\right)+\left(11x^2-22x\right)+\left(18x-36\right)\\ =x^2\left(x-2\right)+11x\left(x-2\right)+18\left(x-2\right)\\ =\left(x^2+11x+18\right)\left(x-2\right)\\ =\left[\left(x^2+2x\right)+\left(9x+18\right)\right]\left(x-2\right)\\ =\left[x\left(x+2\right)+9\left(x+2\right)\right]\left(x-2\right)\\ =\left(x+2\right)\left(x+9\right)\left(x-2\right)\)
KT
20 tháng 7 2018
a) \(4x^3-4x^2=4x^2\left(x-1\right)\)
b) mk chỉnh đề
\(9x^2y^2+15x^2y-21xy^2=3xy\left(3xy+5x-7y\right)\)
c) \(4x^2\left(x-2y\right)-20x\left(2y-x\right)=4x\left(x-2y\right)\left(x+5\right)\)
d) \(4x^2-4x+1=\left(2x-1\right)^2\)
e) bạn ktra lại đề
f) \(16x^2+24xy+9y^2=\left(4x+3y\right)^2\)
MT
8 tháng 7 2015
d) x3-4x2-9x+36
=x2(x-4)-9(x-4)
=(x-4)(x2-9)
=(x-4)(x+3)(x-3)
e)(x+1)3+(2x-1)3
=x3+3x2+3x+1+8x3-12x2+6x-1
=9x3-9x2+9x
=9x(x2-x+1)
g)x3+3x2-4x-12
=x2(x+3)-4(x+3)
=(x+3)(x2-4)
=(x+3)(x+2)(x-2)
h) x3-4x2+4x-1
=x3-1-4x2+4x
=(x-1)(x2+x+1)-4x(x-1)
=(x-1)(x2+x+1-4x)
=(x-1)(x2-3x+1)
DL
19 tháng 8 2019
a) \(4x^4+4x^3-x^2-x=4x^3\left(x+1\right)-x\left(x+1\right)\)
\(=\left(4x^3-x\right)\left(x+1\right)=x\left(4x^2-1\right)\left(x+1\right)\)
\(=x\left\{\left(2x\right)^2-1\right\}\left(x+1\right)=x\left(2x-1\right)\left(2x+1\right) \left(x+1\right)\)
c) \(x^4-4x^3+8x^2-16x+16=x^4+8x^2+16-\left(4x^3+16x\right)\)
\(=\left(x^2+4\right)^2-4x\left(x^2+4\right)=\left(x^2-4x+4\right)\left(x^2+4\right)=\left(x-2\right)^2\left(x^2+4\right)\)
DL
19 tháng 8 2019
b) \(x^6-x^4-9x^3+9x^2=x^4\left(x^2-1\right)-\left(9x^3-9x^2\right)\)
\(=x^4\left(x-1\right)\left(x+1\right)-9x^2\left(x-1\right)\)
\(=\left(x^5+x^4-9x^2\right)\left(x-1\right)=\left(x-1\right)x^2\left(x^3+x^2-9\right)\)
TD
2
H
2 tháng 12 2018
\(a,2x+2y-x^2-xy=2x+2y-\left(x^2+xy\right).\)
\(=2\left(x+y\right)-x\left(x+y\right)\)
\(=\left(2-x\right)\left(x+y\right)\)
7 tháng 8 2023
`@` `\text {Ans}`
`\downarrow`
`4x^3 - 4x^2 - 9x + 9`
`= (4x^3 - 4x^2) - (9x - 9)`
`= 4x^2(x - 1) - 9(x - 1)`
`= (4x^2 - 9)(x - 1)`
____
`x^3 + 6x^2 + 11x + 6`
`= x^3 + x^2 + 5x^2 + 5x + 6x + 6`
`= (x^3 + x^2) + (5x^2 + 5x) + (6x + 6)`
`= x^2*(x + 1) + 5x(x + 1) + 6(x + 1)`
`= (x^2 + 5x + 6)(x+1)`
____
`x^2y - x^3 - 9y + 9x`
`= (x^2y - 9y) - (x^3 - 9x)`
`= y(x^2 - 9) - x(x^2 - 9)`
`= (y - x)(x^2 - 9)`
7 tháng 8 2023
b: =x^3+x^2+5x^2+5x+6x+6
=(x+1)(x^2+5x+6)
=(x+1)(x+2)(x+3)
c: =x^2(y-x)-9(y-x)
=(y-x)(x^2-9)
=(y-x)(x-3)(x+3)
a: =(4x^3-4x^2)-(9x-9)
=4x^2(x-1)-9(x-1)
=(x-1)(4x^2-9)
=(x-1)(2x-3)(2x+3)
5 tháng 8 2021
f) = x2( x - 4 ) - 9( x - 4 ) = ( x - 4 )( x - 3 )( x + 3 )
g) = 4( x - y ) + ( x - y )2 = ( x - y )( x - y + 4 )
h) = x3( x + 1 ) + ( x - 1 )( x + 1 ) = ( x + 1 )( x3 + x - 1 )
i) = ( x - y )( x + y ) - 4( x + y ) = ( x + y )( x - y - 4 )
j) = ( x - y )( x2 + xy + y2 ) - 3( x - y ) = ( x - y )( x2 + xy + y2 - 3 )
QA
5 tháng 8 2021
Trả lời:
f, x3 - 4x2 - 9x + 36 = ( x3 - 4x2 ) - ( 9x - 36 ) = x2 ( x - 4 ) - 9 ( x - 4 ) = ( x - 4 )( x2 - 9 ) = ( x - 4 )( x - 3 )( x + 3 )
g, 4x - 4y + x2 - 2xy + y2 = ( 4x - 4y ) + ( x2 - 2xy + y2 ) = 4 ( x - y ) + ( x - y )2 = ( x - y ) ( 4 + x - y )
h, x4 + x3 + x2 - 1 = ( x4 + x3 ) + ( x2 - 1 ) = x3 ( x + 1 ) + ( x - 1 )( x + 1 ) = ( x + 1 )( x3 + x - 1 )
i, x2 - y2 - 4x - 4y = ( x2 - y2 ) - ( 4x + 4y ) = ( x - y )( x + y ) - 4 ( x + y ) = ( x + y )( x - y - 4 )
j, x3 - y3 - 3x + 3y = ( x3 - y3 ) - ( 3x - 3y ) = ( x - y )( x2 + xy + y2 ) - 3 ( x - y ) = ( x - y )( x2 + xy + y2 - 3 )