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a) 8x2-2x-1=8x2+4x-2x-2x-1=(8x2+4x)-(2x+1)=4x.(2x+1)-(2x+1)=(2x+1).(4x-1)
b) x2-y2+10x-6y+16x=x2-y2+10x+10y-16y+16x=(x-y)(x+y)+10(x+y)-16(y+x)=(x+y)(x-y+10+16)
a, \(3x^2-9x-2x+6=3x\left(x-3\right)-2\left(x-3\right)=\left(x-3\right)\left(3x-2\right)\)
b. \(8x^2-2x+12x-3=2x\left(4x-1\right)+3\left(4x-1\right)=\left(4x-1\right)\left(2x+3\right)\)
c. đề kiểu gì vậy? -2x-x để thành -3x à? xem lại đi nha
d. \(\left(x^2+10x+25\right)-\left(y^2+6y+9\right)=\left(x+5\right)^2-\left(y+3\right)^2=\left(x+5-y-3\right)\left(x+5+y+3\right)=\left(x-y+2\right)\left(x+y+8\right)\)
e. \(=x^4+2x^2y^2+y^4-x^2y^2=\left(x^2+y^2\right)^2-x^2y^2=\left(x^2+y^2-xy\right)\left(x^2+y^2+xy\right)\)
nhớ L I K E
a.\(3x^2-11x+6\)
= \(3x^2-9x-2x+6\)
=\(3x\left(x-3\right)-2\left(x-3\right)\)
=\(\left(x-3\right)\left(3x-2\right)\)
b\(8x^2+10x-3\)
=.\(8x^2-2x+12x-3\)
=\(2x\left(4x-1\right)+3\left(4x-1\right)\)
=\(\left(4x-1\right)\left(2x+3\right)\)
d.\(x^2-y^2+10x-6y+16\)
=\(\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)
=\(\left(x+5\right)^2-\left(y+3\right)^2\)
=\(\left(x+5-y-3\right)\left(x+5+y+3\right)\)
=\(\left(x-y+2\right)\left(x+y+8\right)\)
e.\(x^4+x^2y^2+y^4\)
=\(x^4+2x^2y^2+y^4-x^2+y^2\)
=\(\left(x^2+y^2\right)^2-x^2y^2\)
=\(\left(x^2+y^2-xy\right)\left(x^2+y^2+xy\right)\)
a)
\(=3x^2-9x-2x+6=3x\left(x-3\right)-2\left(x-3\right)=\left(x-3\right)\left(3x-2\right)\)
a) 8x2 - 2x - 1
=8x2+2x-4x-1
=2x.(4x+1)-(4x+1)
=(4x+1)(2x-1)
b) x2 - y2 + 10x - 6y + 16
=x2+10x+25-y2-6y-9
=(x+5)2-(y+3)2
=(x+5-y-3)(x+5+y+3)
=(x-y+2)(x+y+8)
x^2-y^2+10x-6y-9
=x^2+10x -(y^2+6y+9)
= x^2+10x-(y^2+2.3.y+3^2)
=x^2+10x-(y+3)^2
=\(\left[x^2-\left(y+3\right)^2\right]+10x \)
={\(\left(x+x+3\right)\left[x-\left(x+3\right)\right]\)}\(+10x\)
=\(\left(x+x+3\right).\left(x-x-3\right)+10x\)
(đến đây b tự lm nhé, m cx k bt đúng k nx )
\(1,4x^4+4x^2y^2-8y^4\)
\(=4\left(x^4+x^2y^2-y^4-y^4\right)\)
\(=4\left[\left(x^4-y^4\right)+\left(x^2y^2-y^4\right)\right]\)
\(=4\left[\left(x^2+y^2\right)\left(x^2-y^2\right)+y^2\left(x^2-y^2\right)\right]\)
\(=4\left(x^2-y^2\right)\left(x^2+y^2+y^2\right)\)
\(=4\left(x-y\right)\left(x+y\right)\left(x^2+2y^2\right)\)
\(2,12x^2y-18xy^2-30y^3\)
\(=6y\left(2x^2-3xy-5y^2\right)\)
\(=6y\left[\left(2x^2+2xy\right)-\left(5xy+5y^2\right)\right]\)
\(=6y\left[2x\left(x+y\right)-5y\left(x+y\right)\right]\)
\(=6y\left(x+y\right)\left(2x-5y\right)\)
x^2-y^2+10x-6y+16=(x^2-10x+25)-(y^2+6y+9)=(x-5)^2-(y+3)^2=(x-5-y-3)(x-5+y+3)=(x-y-8)(x+y-2)
(x2-10x+25)-(y2+6y+9)=(x-5)2-(y+3)2=(x-y-8)(x+y-2)