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a)x^2-(a+b)x+ab
= x^2 - ax - bx + ab
= (x^2 - ax) - (bx - ab)
= x(x-a) - b(x-a)
= (x-b)(x-a)
b)7x^3-3xyz-21x^2+9z
=
c)4x+4y-x^2(x+y)
= 4(x + y) - x^2(x+y)
= (4-x^2) (x+y)
= (2-x)(2+x)(x+y)
d) y^2+y-x^2+x
= (y^2 - x^2) + (x+y)
= (y-x)(y+x)+ (x+y)
= (y-x+1) (x+y)
e)4x^2-2x-y^2-y
= [(2x)^2 - y^2] - (2x +y)
= (2x-y)(2x+y) - (2x+y)
= (2x -y -1)(2x+y)
f)9x^2-25y^2-6x+10y
=
a,\(\left(x-5\right)^2-16=\left(x-5\right)^2-4^2=\left(x-5-4\right)\left(x-5+4\right)=\left(x-9\right)\left(x-1\right)\)
a) \(x-xy+y-y^2=x\left(1-y\right)+y\left(1-y\right)=\left(x+y\right)\left(1-y\right)\)
b) \(x^2-2x-y^2+1=\left(x^2-2x+1\right)-y^2=\left(x-1\right)^2-y^2=\left(x-y-1\right)\left(x+y-1\right)\)
c) \(4x^2-4xy+y^2=\left(2x\right)^2-2.2x.y+y^2=\left(2x-y\right)^2\)
d) \(9x^3-9x^2y-4x+4y=9x^2\left(x-y\right)-4\left(x-y\right)=\left(9x^2-4\right)\left(x-y\right)=\left(3x-2\right)\left(3x+2\right)\left(x-y\right)\)
e) \(x^3+2+3\left(x^3-2\right)=x^3+2+3x^3-6=4x^3-4=4\left(x^3-1\right)=4\left(x-1\right)\left(x^2+x+1\right)\)
a) 5xy ( x - y ) - 2x + 2y
= 5xy ( x - y ) - 2 ( x - y )
= ( x - y ) ( 5xy - 2 )
b) 6x-2y-x(y-3x)
= 2 ( y - 3x ) - x ( y - 3x )
= ( y - 3x ( ( 2 - x )
c) x2 + 4x - xy-4y
= x ( x + 4 ) - y ( x + 4 )
( x + 4 ) ( x - y )
d) 3xy + 2z - 6y - xz
= ( 3xy - 6y ) + ( 2z - xz )
= 3y ( x - 2 ) + z ( x - 2 )
= ( x - 2 ) ( 3y + z )
a,5xy(x-y)-2x+2y=5xy(x-y)-2(x-y)=(x-y)(5xy-2)
b,6x-2y-x(y-3x)=-2(y-3x)-x(y-3x)=(y-3x)(-2-x)
c,x^2+4x-xy-4y=x(x+4)-y(x+4)=(x+4)(x-y)
d,3xy+2z-6y-xz=(3xy-6y)+(2z-xz)=3y(x-2)+z(2-x)=3y(x-2)-z(x-2)=(x-2)(3y-z)
11)
a,4-9x^2=0
(2-3x)(2+3x)=0
2-3x=0=>x=2/3 hoặc 2+3x=0=>x=-2/3
b,x^2 +x+1/4=0
(x+1/2)^2 =0
x+1/2=0
x=-1/2
c,2x(x-3)+(x-3)=0
(x-3)(2x+1)=0
x-3=0=>x=3 hoặc 2x+1=0=>x=-1/2
d,3x(x-4)-x+4=0
3x(x-4)-(x-4)=0
(x-4)(3x-1)=0
x-4=0=>x=4 hoặc 3x-1=0=>x=1/3
e,x^3-1/9x=0
x(x^2-1/9)=0
x(x+1/3)(x-1/3)=0
x=0 hoặc x+1/3=0=>x=-1/3 hoặc x-1/3=0=>x=1/3
f,(3x-y)^2-(x-y)^2 =0
(3x-y-x+y)(3x-y+x-y)=0
2x(4x-2y)=0
4x(2x-y)=0
x=0hoặc 2x-y=0=>x=y/2
1) x^2-1+2xy+y^2 = (x^2+2xy+y^2)-1 = (x+y)^2 - 1^2 = (x+y-1)*(x+y+1)
2) x^4-x^3-x+1 = (x^4-x)-(x^3-1) = x*(x^3-1)-(x^3-1) = (x^3-1)*(x-1)
3) 7x^2-63y^2 = 7*(x^2-9y^2) = 7*[x^2-(3y)^2] = 7*(x-3y)*(x+3y)
còn lại bn tự tính ik nha
chuyển về dạng nguyên thể rồi tính thể chất khối lượng sau đó quay về đang tìm mũ của nhiều số làm ra rồi thì dễ lắm bạn ạ k minh nha
a)\(\left(x^2-2\right)\left(x^2+2x+2\right)\)
b)\(\left(x-1\right)\left(2x+1\right)\left(3x+7\right)\)
c)\(-2\left(x-4\right)\left(2x+1\right)\)
d)\(\left(x-5\right)\left(4x+1\right)\)
e)\(3\left(x-2\right)\left(3x-2\right)\)
g)\(2\left(a-b\right)^2\)
h)\(\left(xy-3\right)\left(5y^2-2z\right)\)
i)\(\left(4x+1\right)\left(2x-y\right)\)
l)\(abc^2\left(b-a\right)\left(b+c\right)\)
m)\(\left(x-y\right)\left(y-z\right)\left(x-z\right)\)
a) 5.(x-y)-y(x-y)
= (x-y)(5-y)
b) y.(x-2)+7(2-x)
= y.(x-2) -7(x-2)
=(x-2)(y-7)
c) sửa lại đề
272.(y-1) -9x3(1-y)
=272.(y-1) + 9x3(y-1)
= (y-1)(272+9x3)
d) 4x(x-2016-x+2016)
= 4x.0
= 0
e) (2x-1)3 - 2x+1
= (2x-1)3 - (2x-1)
= (2x-1)[(2x-1)2-1]
=(2x-1)(2x-1-1)(2x-1+1)
=2x.(2x-1)(2x-2)
=4x.(x-1)(2-1)
m) 25-(3-x)2
= [5-(3-x)][5+(3-x)]
=(5-3+x)(5+3-x)
n) (x-5)2=16
=> (x-5)2=42 hoặc (x-5)2=(-4)2
=> (x-5)=4 hoặc x-5=-4
trường hợp 1
x-5=4
x= 4+5
x=9
trường hợp 2
x-5=-4
x=-4+5
x=1
vậy x=9 hoặc x=1
a) \(5.\left(x-y\right)-y.\left(x-y\right)=\left(x-y\right)\left(5-y\right)\)
b) \(y.\left(x-2\right)+7.\left(2-x\right)=\left(x-2\right)\left(y+7\right)\)