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11 tháng 10 2020

a) \(\left(3x-1\right)^2-16=\left(3x-1\right)^2-4^2=\left(3x-1-4\right)\left(3x-1+4\right)=\left(3x-5\right)\left(3x+3\right)\)b) \(\left(2x+5\right)^2-\left(x-9\right)^2=\left(2x+5+x-9\right)\left(2x+5-x+9\right)=\left(3x-4\right)\left(x+14\right)\)

c) \(\left(y^3+8\right)+\left(y^2-4\right)\)

\(=\left(y+2\right)\left(y^2-2y+4\right)+\left(y-2\right)\left(y+2\right)\)

\(=\left(y+2\right)\left(y^2-2y+4+y-2\right)\)

\(=\left(y+2\right)\left(y^2-y+2\right)\)

d) \(x^4-1=\left(x^2\right)^2-1^2=\left(x^2-1\right)\left(x^2+1\right)=\left(x-1\right)\left(x+1\right)\left(x^2+1\right)\)

e) \(81y^2-\left(y^2+6y\right)^2\)

\(=\left(9y\right)^2-\left(y^2+6y\right)^2\)

\(=\left(9y-y^2-6y\right)\left(9y+y^2+6y\right)\)

\(=\left(3y-y^2\right)\left(15y+y^2\right)\)

18 tháng 10 2018

16x4y2-25a2b2

16 tháng 10 2019

1) \(x^6+1\)

\(=x^6+x^4-x^4+x^2-x^2+1\)

\(=\left(x^6-x^4+x^2\right)+\left(x^4-x^2+1\right)\)

\(=x^2\left(x^4-x^2+1\right)+\left(x^4-x^2+1\right)\)

\(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)

2) \(x^6-y^6\)

\(=\left(x^3+y^3\right)\left(x^3-y^3\right)\)

\(=\left(x+y\right)\left(x^2-xy+y^2\right)\left(x-y\right)\left(x^2+xy+y^2\right)\)

14 tháng 8 2015

a/ \(=3y^2-6y-2x+1\)

b/ \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

c/ \(=\left(2-x\right)^3\)

d/ \(=xy^2+x^2y+3xy+x^2y+x^3+3x^2-3xy-3x^2-9x\)

\(=xy\left(y+x+3\right)+x^2\left(y+x+3\right)-3x\left(y+x+3\right)\)

\(=\left(xy+x^2-3x\right)\left(y+x+3\right)=x\left(y+x-3\right)\left(y+x+3\right)\)

e/ \(=xy-x^2+2x-y^2+xy-2y\)

\(=x\left(y-x+2\right)-y\left(y-x+2\right)=\left(x-y\right)\left(y-x+2\right)\)

14 tháng 8 2015

a) =(2x+3y-1)2

b)=-(x-1)3

c)=-(x3-6x2+12x-8)=-(x-2)3

d)x3 + 2x2y + xy2 – 9x

    = x(x2 + 2xy + y2 -9)

    = x[(x2 + 2xy + y2) - 32]

    = x[(x + y)2 - 32]

    = x (x + y – 3)(x + y + 3)

e) 2x-2y-x2+2xy-y2=2(x-y)-(x-y)2=(x-y)(2-x+y)

9 tháng 1 2018

a,\(x^5-x^4-x^4+x^3+2x^3-2x^2-2x^2+2\)2x-2x+2\(x^4\left(x-1\right)-x^3\left(x-1\right)+2x^2\left(x-1\right)-2x\left(x-1\right)+2\left(x-1\right)\)

=\(\left(x^4-x^3+2x^2-2x+2\right)\left(x-1\right)\)

b,

9 tháng 1 2018

câu b, c,d tương tự 

bạn tự làm nó nhé

14 tháng 10 2020

a) \(9\left(2x-3\right)^2-4\left(x+1\right)^2\)

\(=\left[3\left(2x-3\right)-2\left(x+1\right)\right]\left[3\left(2x-3\right)+2\left(x+1\right)\right]\)

\(=\left(6x-9-2x-2\right)\left(6x-9+2x+2\right)\)

\(=\left(4x-11\right)\left(8x-7\right)\)

b) \(\left(x^2+4y^2-20\right)-16\left(xy-4\right)^2\)

\(=\left[\left(x^2-4xy+4y^2\right)-4\right]\left[\left(x^2+4xy+4y^2\right)-36\right]\)

\(=\left[\left(x-2y\right)^2-4\right]\left[\left(x+2y\right)^2-36\right]\)

\(=\left(x-2y-2\right)\left(x-2y+2\right)\left(x+2y-6\right)\left(x+2y+6\right)\)

14 tháng 10 2020

a. 9 ( 2x - 3 )2 - 4 ( x + 1 )2

= [ 3 ( 2x - 3 ) ]2 - [ 2 ( x + 1 ) ]2

= [ 3 ( 2x - 3 ) - 2 ( x + 1 ) ] [ 3 ( 2x - 3 ) + 2 ( x + 1 ) ]

= ( 6x - 9 - 2x - 2 ) ( 6x - 9 + 2x + 2 )

= ( 4x - 11 ) ( 8x - 7 )

b. ( x2 + 4y2 - 20 )2 - 16 ( xy - 4 )2

= ( x2 + 4y2 - 20 )2 - [ 4 ( xy - 4 ) ]2

= [ x2 + 4y2 - 20 - 4 ( xy - 4 ) ] [ x2 + 4y2 - 20 + 4 ( xy - 4 ) ]

= ( x2 + 4y2 - 20 - 4xy + 16 ) ( x2 + 4y2 - 20 + 4xy - 16 )

 = ( x2 + 4y2 - 4xy - 4 ) ( x2 + 4y2 + 4xy - 36 )

= [ ( x - 2y )2 - 22 ] [ ( x + 2y )2 - 62 ]

= ( x - 2y - 2 ) ( x - 2y + 2 ) ( x + 2y - 6 ) ( x + 2y + 6 )