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A = 4acx + 4bcx + 4ax + 4bx ( đã sửa '-' )
= 4x( ac + bc + a + b )
= 4x[ c( a + b ) + ( a + b ) ]
= 4x( a + b )( c + 1 )
B = ax - bx + cx - 3a + 3b - 3c
= x( a - b + c ) - 3( a - b + c )
= ( a - b + c )( x - 3 )
C = 2ax - bx + 3cx - 2a + b - 3c
= x( 2a - b + 3c ) - ( 2a - b + 3c )
= ( 2a - b + 3c )( x - 1 )
D = ax - bx - 2cx - 2a + 2b + 4c
= x( a - b - 2c ) - 2( a - b - 2c )
= ( a - b - 2c )( x - 2 )
E = 3ax2 + 3bx2 + ax + bx + 5a + 5b
= 3x2( a + b ) + x( a + b ) + 5( a + b )
= ( a + b )( 3x2 + x + 5 )
F = ax2 - bx2 - 2ax + 2bx - 3a + 3b
= x2( a - b ) - 2x( a - b ) - 3( a - b )
= ( a - b )( x2 - 2x - 3 )
= ( a - b )( x2 + x - 3x - 3 )
= ( a - b )[ x( x + 1 ) - 3( x + 1 ) ]
= ( a - b )( x + 1 )( x - 3 )
d) ax2 + ay - bx2 - by
= ( ax2 + ay ) - ( bx2 + by )
= a ( x2 + y ) - b ( x2 + y )
= ( x2 + y )( a - b )
c) x2y + xy2 - x - y
= ( x2y + xy2 ) - ( x + y )
= xy ( x + y ) - ( x+ y )
= ( x + y ) ( xy - 1 )
Đề sai nhé .Sửu lại
\(x^2-4x^2y^2+4+4x\)
\(=\left(x^2+4x+4\right)-4x^2y^2\)
\(=\left(x+2\right)^2-\left(2xy\right)^2\)
\(=\left(x+2+2xy\right)\left(x+2-2xy\right)\)
a) ax2 - 2bxy + 2bx2 - axy
= ( ax2 - axy ) + ( 2bx2 - 2bxy )
= ax( x - y ) + 2bx( x - y )
= ( x - y )( ax + 2bx )
= x( x - y )( a + 2b )
b) x2 + 2x - 4y2 + 8y - 3 < đã sửa >
= ( x2 + 2x + 1 ) - ( 4y2 - 8y + 4 )
= ( x + 1 )2 - ( 2y - 2 )2
= [ ( x + 1 ) - ( 2y - 2 ) ][ ( x + 1 ) + ( 2y - 2 ) ]
= ( x + 1 - 2y + 2 )( x + 1 + 2y - 2 )
= ( x - 2y + 3 )( x + 2y - 1 )
c) x4 + 5x3 + 20x - 16
= x4 + 5x3 + 4x2 - 4x2 + 20x - 16
= ( x4 + 5x3 - 4x2 ) + ( 4x2 + 20x - 16 )
= x2( x2 + 5x - 4 ) + 4( x2 + 5x - 4 )
= ( x2 + 5x - 4 )( x2 + 4 )
ax2 - ax + bx2 -bx + a + b
= (ax2+ bx2 ) - (ax + bx) + (a + b)
=x2 (a + b) - x(a + b) + (a + b)
= (x2 - x + 1)(a + b)
ax2 - ax + bx2 - bx + a + b
= ( ax2 + bx2 ) - ( ax + bx ) + ( a + b )
= x2( a + b ) - x( a + b ) + ( a + b )
= ( a + b )( x2 - x + 1 )
a) \(x^3-2x^2+2x-1^3\)
\(=x\left(x^2-2x+1\right)+x-1\)
\(=x\left(x-1\right)+\left(x-1\right)\)
\(=\left(x+1\right)\left(x-1\right)\)
b) \(x^2y+xy+x+1\)
\(=xy\left(x+1\right)+\left(x+1\right)\)
\(=\left(xy+1\right)\left(x+1\right)\)
c) \(ax+by+ay+bx\)
\(=a\left(x+y\right)+b\left(x+y\right)\)
\(=\left(a+b\right)\left(x+y\right)\)
d) \(x^2-\left(a+b\right)x+ab\)
\(=x^2-ax-bx+ab\)
\(=\left(x^2-ax\right)-\left(bx-ab\right)\)
\(=x\left(x-a\right)-b\left(x-a\right)\)
\(=\left(x-b\right)\left(x-a\right)\)
e) Ko biết làm
f) \(ax^2+ay-bx^2-by\)
\(=\left(ax^2+ay\right)-\left(bx^2+by\right)\)
\(=a\left(x^2+y\right)-b\left(x^2+y\right)\)
\(=\left(a-b\right)\left(x^2+y\right)\)
Đặt : \(A=ax^2+a-2ax+b-2bx+bx^2\)
\(=\left(ax^2+a-2ax\right)+\left(b-2bx+bx^2\right)\)
\(=a\left(x^2+1-2x\right)+b\left(1-2x+x^2\right)\)
\(=a\left(x^2-2x+1\right)+b\left(x^2-2x+1\right)\)
\(=a\left(x-1\right)^2+b\left(x-1\right)^2\)
\(=\left(x-1\right)^2\left(a+b\right)\)