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câu 20
\(\)\(C_{20}=\left(a^2+1\right)^2-4a^2=\left(a^2+1\right)^2-\left(2a\right)^2=\left[\left(a^2+1\right)-2a\right]\left[\left(a^2+1\right)+2a\right]\)\(C_{20}=\left[a^2-2a+1\right]\left[a^2+2a+1\right]=\left(a-1\right)\left(a-1\right)\left(a+1\right)\left(a+1\right)\)
\(C_{20}=\left(a-1\right)\left(a-1\right)\left(a+1\right)\left(a+1\right)\)
a)
\(14x^2y-21xy^2+28x^2y^2\)
\(=7xy(2x-3y+4xy)\)
b) \(x(x+y)-5x-5y=x(x+y)-5(x+y)=(x-5)(x+y)\)
c)
\(10x(x-y)-8(y-x)=10x(x-y)+8(x-y)\)
\(=(x-y)(10x+8)=2(x-y)(5x+4)\)
a. \(14x^2y-21xy^2+28x^2y^2\)
\(=7xy\left(2x-3y+4xy\right)\)
b. \(x\left(x+y\right)-5x-5y\)
\(=x\left(x+y\right)-5\left(x+y\right)\)
\(=\left(x-5\right)\left(x+y\right)\)
c. \(10x\left(x-y\right)-8\left(y-x\right)\)
\(=10x\left(x-y\right)+8\left(x-y\right)\)
\(=\left(10x+8\right)\left(x-y\right)\)
d. \(\left(3x+1\right)^2-\left(x+1\right)^2\)
\(=\left(3x+1+x+1\right)\left(3x+1-x-1\right)\)
\(=2x\left(4x+2\right)\)
\(=4x\left(2x+1\right)\)
e. Vì bài này giải không ra nên mình nghĩ nó sai đề, sửa lại tí nhé!
\(x^3+y^3+z^3-3xyz\)
\(=\left(x+y\right)^3+z^3-3xy\left(x+y\right)-3xyz\)
\(=\left(x+y+z\right)\left[\left(x+y\right)^2-z\left(x+y\right)+z^2\right]-3xy\left(x+y+z\right)\)
\(=\left(x+y+z\right)\left(x^2+2xy+y^2-xz+zy+z^2-3xy\right)\)
g. \(5x^2-10xy+5y^2-20z^2\)
\(=5\left(x^2-2xy+y^2-4z^2\right)\)
\(=5\left[\left(x-y^2\right)-4z^2\right]\)
\(=5\left(x-y+z\right)\left(x-y-z\right)\)
h. \(x^3-x+3x^2y+3xy^3+y^3-y\)
\(=\left(x^3+3x^2y+3xy^2+y^2\right)-\left(x+y\right)\)
\(=\left(x+y\right)^3-\left(x+y\right)\)
\(=\left(x+y\right)\left[\left(x+y\right)^2-1\right]\)
\(=\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\)
i. \(x^2+7x-8\)
\(=x^2-x+8x-8\)
\(=x\left(x-1\right)+8\left(x-1\right)\)
\(=\left(x+8\right)\left(x-1\right)\)
1. 2xy2 +x2y4+1 = (xy2+1)2
2. a)3x2+3x-10x-10=3x(x+1)-10(x+1)=(x+1)(3x-10)
b)2x2-5x-7=2x2+2x-7x-7=2x(x+1)-7(x+1)=(x+1)(2x-7)
Mong có thể giúp được bạn
x2 - 3x + 2
= x2 - x - 2x + 2
= x(x - 1) - 2(x - 1)
= (x - 1)(x - 2)
3x2 - 7x - 10
= 3x2 + 3x - 10x - 10
= 3x(x + 1) - 10(x + 1)
= (x + 1)(3x - 10)
2x2 - 5x - 7
= 2x2 + 2x - 7x - 7
= 2x(x + 1) - 7(x + 1)
= (x + 1)(2x - 7)
a, \(x^3-x+3x^2y+3xy^2+y^3-y\)
= \((x^3+3x^2y+3xy^2+y^3)-x-y\)
= \(\left(x+y\right)^3-\left(x+y\right)\)
= \(\left(x+y\right)\left[\left(x+y\right)^2-1\right]\)
= \(\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\)
a ) = 3 ( x^2 + 2xy + y^2 - z^2 )
= 3 [ ( x + y)^2 - z^2]
= 3 ( x + y - z)( x + y + z)
b) 4 y^ 2 - 5 y - 6 = 4y^2 - 8y + 3y - 6 = 4y ( y- 2 ) + 3 ( y- 2 ) = ( 4y +3 )( y - 2 )
d) x^4 + x^2y^2 + y^4 = x^4 + 2 x^2y^2 + y^4 - x^2y^2 = ( x^2 + y^2 )^2 - (xy)^2 = ( x^2 - xy + y^ 2)( x^2 + xy + y^2)
\(1.x^3+2x+x^2=x\left(x^2+x+2\right)\)
\(2.2x^3+4x^2+2x=2x\left(x^2+2x+1\right)=2x\left(x+1\right)^2\)
\(3.-3x^3-5x^2+8x=-3x^3+3x^2-8x^2+8x\)
\(=-3x^2\left(x-1\right)-8x\left(x-1\right)=\left(3x^2+8x\right)\left(1-x\right)\)
\(=x\left(3x+8\right)\left(1-x\right)\)
\(4.x^2+4x-5=x^2-x+5x-5=\left(x-1\right)\left(x+5\right)\)
\(5.6x^2-3x-3=6x^2-6x+3x-3=3\left(x-1\right)\left(2x+1\right)\)
\(6.3x^2-2x-5=3x^2+3x-5x-5=\left(x+1\right)\left(3x-5\right)\)
\(8.x^2-2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)-2\left(x+2y\right)\)\(=\left(x+2y\right)\left(x-y-2\right)\)
\(9.x^3+2x^2y+xy^2-9x=x\left(x^2+2xy+y^2-9\right)\)
\(=x\left(x+y-3\right)\left(x+y+3\right)\)
\(10.x^2-y^2+6x+9=\left(x+3-y\right)\left(x+3+y\right)\)
2: \(=a^2\left(a+3\right)+4\left(a+3\right)=\left(a+3\right)\left(a^2+4\right)\)
3: \(=\left(2a-1\right)^2-4b^2\)
\(=\left(2a-1-2b\right)\left(2a-1+2b\right)\)
4: \(=-\left(x^2+x-2\right)=-\left(x+2\right)\left(x-1\right)\)
5: \(=7\left(x^2-2xy^2+y^4\right)=7\left(x-y^2\right)^2\)
6: \(=\left(x+2\right)^2-y^2=\left(x+2+y\right)\left(x+2-y\right)\)
1: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)
3: \(=18\left(m^2-2mn+n^2-4p^2\right)\)
\(=18\left(m-n-2p\right)\left(m-n+2p\right)\)
4: \(=9\left(a^2-2ab+b^2-4c^2\right)\)
\(=9\left(a-b-2c\right)\left(a-b+2c\right)\)
5: \(=\left(x-3y\right)\left(5a-8b\right)\)
6: \(=7\left(x^2-2xy+y^2-z^2\right)\)
\(=7\left(x-y-z\right)\left(x-y+z\right)\)