\(^{x^2-6x+xy-6y}\)

b) \(3x^2-6xy+...">

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a) \(x^2-6x+xy-6y\)

\(=\left(x^2-6x\right)+\left(xy-6y\right)\)

\(=x\left(x-6\right)+y\left(x-6\right)\)

\(=\left(x-6\right)\left(x+y\right)\)

c) \(3x^2-7x+4\)

\(=3x^2-3x-4x+4\)

\(=\left(3x^2-3x\right)-\left(4x-4\right)\)

\(=3x\left(x-1\right)-4\left(x-1\right)\)

\(=\left(x-1\right)\left(3x-4\right)\)

29 tháng 12 2019

\(3x^2-6xy+3y^2-12z^2\)

\(=3\left(x^2-2xy+y^2\right)-3\cdot4z^2\)

\(=3\left(x-y\right)^2-3\cdot4z^2\)

\(=3\left(x-y-2z\right)\left(x-y+2z\right)\)

13 tháng 8 2015

a) \(3x^2-6xy+3y^2-12z^2\Leftrightarrow3\left(\left(x^2-2xy+y^2\right)-\left(2z\right)^2\right)\Leftrightarrow3\left(x-y\right)^2-\left(2z\right)^2\) \(\Leftrightarrow3\left(\left(x-y-2z\right)\left(x-y+2z\right)\right)\)

b) \(x^4+1-2x^2=\left(x^2\right)^2-2x^2+1^2=\left(x^2-1\right)^2\)

**** mik nha bn

5 tháng 10 2020

a) 5x2 - 5xy + 7y - 7x = ( 5x2 - 5xy ) - ( 7x - 7y ) = 5x( x - y ) - 7( x - y ) = ( x - y )( 5x - 7 )

b) x2 - y2 + 2x + 1 = ( x2 + 2x + 1 ) - y2 = ( x + 1 )2 - y2 = ( x - y + 1 )( x + y + 1 )

c) 3x2 + 6xy + 3y2 - 3z2 = 3( x2 + 2xy + y2 - z2 ) = 3[ ( x2 + 2xy + y2 ) - z2 ] = 3[ ( x + y )2 - z2 ] = 3( x + y - z )( x + y + z )

d) ab( x2 + y2 ) + xy( a2 + b2 ) = abx2 + aby2 + a2xy + b2xy

                                                = ( a2xy + abx2 ) + ( aby2 + b2xy )

                                                = ax( ay + bx ) + by( ay + bx )

                                                = ( ay + bx )( ax + by )

11 tháng 12 2018

\(3y^3+6xy^2+3x^2y=3y\left(y^2+2xy+x^2\right)=3y\left(x+y\right)^2\)

\(x^3-3x^2-4x+12=x^2\left(x-3\right)-4\left(x-3\right)=\left(x-3\right)\left(x^2-4\right)=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)

\(x^3+3x^2-3x-1=\left(x-1\right)\left(x^2+x+1\right)+3x\left(x-1\right)=\left(x-1\right)\left(x^2+x+1+3x\right)\)

\(=\left(x-1\right)\left(x^2+4x+1\right)\)

Tham khảo nhé~

11 tháng 12 2018

\(x^2-2xy+y^2-z^2=\left(x-y\right)^2-z^2=\left(x-y-z\right)\left(x-y+z\right)\)

\(3x^2+6xy+3y^2-3z^2=3\left(x^2+2xy+y^2-z^2\right)=3.\left[\left(x+y\right)^2-z^2\right]=3.\left(x+y-z\right)\left(x+y+z\right)\)

\(3x^2-3xy-5x+5y=3x\left(x-y\right)-5\left(x-y\right)=\left(x-y\right)\left(3x-5\right)\)

11 tháng 12 2018

\(x^2+5x+6\)

\(=x^2+3x+2x+6\)

\(=x.\left(x+3\right)+2.\left(x+3\right)=\left(x+3\right).\left(x+2\right)\)

3 tháng 7 2017

a, \(\left(x^2-y^2\right)-\left(5x+5y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y-5\right)\)

b, \(5x^3-5x^2y-10x^2+10xy\)

\(=5x^2\left(x-y\right)-10x\left(x-y\right)\)

\(=\left(5x-10x\right)\left(x-y\right)=5x\left(x-2\right)\left(x-y\right)\)

c, \(2x^2-5x=x\left(2x-5\right)\)

f, \(3x^2-7x-10=3x^2+3x^2-10x-10\)

\(=3x^2\left(x+1\right)-10\left(x+1\right)=\left(3x^2-10\right)\left(x+1\right)\)

d, \(x^3-3x^2+1-3x=x^3-3x^2-3x+1\)

\(=x^3+x^2-4x^2-4x+x+1\)

\(=x^2\left(x+1\right)-4x\left(x+1\right)+\left(x+1\right)\)

\(=\left(x^2-4x+1\right)\left(x+1\right)\)

e, \(3x^2-6xy+3y^2-12z^2\)

\(=3\left(x^2-2xy+y^2-4z^2\right)\)

\(=3\left[\left(x-y\right)^2-4z^2\right]\)

\(=3\left(x-y-2z\right)\left(x-y+2z\right)\)

g, \(x^4+1-2x^2=\left(x^2-1\right)^2\)

h, \(3x^2-3y^2-12x+12y=3\left(x^2-y^2\right)-12\left(x-y\right)\)

\(=3\left(x-y\right)\left(x+y\right)-12\left(x-y\right)\)

\(=\left(x-y\right)\left(3x+3y-12\right)\)

\(=3\left(x-y\right)\left(x+y-4\right)\)

j, \(x^2-3x+2=x^2-2x-x+2=x\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-1\right)\left(x-2\right)\)

3 tháng 7 2017

a. \(\left(x^2-y^2\right)-5\left(x+y\right)\)

\(=\left(x-y\right)\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y-5\right)\)

b. \(5x^3-5x^2y-10x^2+10xy\)

\(=5\left[\left(x^3-x^2y\right)-\left(2x^2-2xy\right)\right]\)

\(=5\left[x^2\left(x-y\right)-2x\left(x-y\right)\right]\)

\(=5x\left(x-y\right)\left(x-2\right)\)

c. \(2x^2-5x=x\left(2x-5\right)\)

d. \(x^3-3x^2+1-3x\)

\(=\left(x^3+1\right)-\left(3x^2+3x\right)\)

\(=\left(x+1\right)\left(x^2-x+1\right)-3x\left(x+1\right)\)

\(=\left(x+1\right)\left[x^2-x+1-3x\right]\)

\(=\left(x+1\right)\left[x^2-4x+1\right]\)

\(=\left(x+1\right)\left[x^2-2.x.2+2^2-2^2+1\right]\)

\(=\left(x+1\right)\left[\left(x-2\right)^2-3\right]\)

\(=\left(x+1\right)\left(x-2+\sqrt{3}\right)\left(x-2-\sqrt{3}\right)\)

e. \(3x^2-6xy+3y^2-12z^2\)

\(=3\left[x^2-2xy+y^2-4z^2\right]\)

\(=3\left[\left(x-y\right)^2-\left(2z\right)^2\right]\)

\(=3\left(x-y+2z\right)\left(x-y-2z\right)\)

f. \(3x^2-7x-10\)

\(=3x^2-7x-7-3\)

\(=\left(3x^2-3\right)-\left(7x+7\right)\)

\(=3\left(x^2-1\right)-7\left(x+1\right)\)

\(=3\left(x+1\right)\left(x-1\right)-7\left(x+1\right)\)

\(=\left(x+1\right)\left[3\left(x-1\right)-7\right]\)

\(=\left(x+1\right)\left(3x-8\right)\)

g. \(x^4+1-2x^2=\left(x^2\right)^2-2.x^2+1=\left(x^2-1\right)^2\)

\(=\left(x+1\right)^2\left(x-1\right)^2\)

h. \(3x^2-3y^2-12x+12y\)

\(=3\left(x^2-y^2\right)-12\left(x-y\right)\)

\(=3\left(x-y\right)\left(x+y\right)-12\left(x-y\right)\)

\(=\left(x-y\right)\left[3\left(x+y\right)-12\right]\)

\(=\left(x-y\right).3.\left(x+y-4\right)\)

j. \(x^2-3x+2=x^2-x-2x+2\)

\(=x\left(x-1\right)-2\left(x-1\right)\)

\(=\left(x-1\right)\left(x-2\right)\)

P/s: ( Có j sai ns nha nhiều số quá tui rối đầu )

21 tháng 12 2017

A . 5(x-y)-y(x-y)

=(x6-y)(5-y)

B . x^2 - xy - 8x+8y

=(x^2-xy)-(8x-8y))

=x(x-y) - 8(x-y)

C. x^2-10x+25 - y^2

=(x^2 - 10x + 25 ) - y^2

=(x-5)^2 - y^2

=(x-5+y)(x-5-y)

D . x^3 - 3x^2-4x+12

=(x^3 - 3x^2 ) - (4x - 12)

=x^2 (x-3)-4(x-3)

=(x^2-4)(x-3)

=(x+2)(x-2)(x-3)

D . 2x^2-2y^2- 6x-6y

=(2^x - 2y^2) - (6x+ 6y)

=2(x^2 - y^2) - 6(x+y)

=2(x+y)(x-y) - 6(x+y)

=2(x+y)(x-y-3)

E . x^3 - 3x^2 + 3x - 1

=(x-1)^3

D.x^2+3x+2

=x^2+2x+x+2

=(x^2+2x)+(x+2)

=x(x+2)+(x+2)

=(x+2)(x+1)

21 tháng 12 2017

Sai vài chỗ nha bạn! :)

30 tháng 9 2019

a) \(x^2+7x+7y-y^2\)

\(=\left(x+y\right)\left(x-y\right)+7\left(x+y\right)\)

\(=\left(x+y\right)\left(x-y+7\right)\)

b) \(x^2-xy-6y^2\)

\(=-6y^2-3xy+2xy+x^2\)

\(=-3y\left(2y+x\right)+x\left(2y+x\right)\)

\(=\left(x-3y\right)\left(2y+x\right)\)

c) \(x^2-3x^2-6x+8\)

\(=\left(x+2\right)\left(x^2-2x+4\right)-3x\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-5x+4\right)\)

\(=\left(x+2\right)\left(x^2-4x-x+4\right)\)

\(=\left(x+2\right)\left[x\left(x-4\right)-\left(x-4\right)\right]\)

\(=\left(x+2\right)\left(x-1\right)\left(x-4\right)\)

30 tháng 9 2019

a)x2+7x+7y-y2=(x-y)(x+y)+7.(x+y)

                       =(x+y)(x-y+7)

b)x2-xy-6y2=x2-xy-4y2-2y2

                   =(x-2y)(x+2y)-y(x-2y)

                   =(x-2y)(x+2y-y)