\(x^2-5xy-14y^2\)

b) 

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26 tháng 9 2018

\(x^2-\text{5}xy-14y^2\)

\(=x^2+2xy-7xy-14y^2\)

\(=x\left(x+2y\right)-7y\left(x+2y\right)\)

\(=\left(x+2y\right)\left(x-7y\right)\)

26 tháng 9 2018

a) \(x^2-5xy-14y^2=x^2-7xy+2xy-14y^2\)

\(=\left(x-7y\right)\left(x+2y\right)\)

b) \(x^2-5x+6=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\)

c) \(x^4+4=x^4+4x^2+4-\left(2x\right)^2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2\)

\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

d) 

20 tháng 4 2017

a) x2 – 4x + 3 = x2 – x - 3x + 3

= x(x - 1) - 3(x - 1) = (x -1)(x - 3)

b) x2 + 5x + 4 = x2 + 4x + x + 4

= x(x + 4) + (x + 4)

= (x + 4)(x + 1)

c) x2 – x – 6 = x2 +2x – 3x – 6

= x(x + 2) - 3(x + 2)

= (x + 2)(x - 3)

d) x4+ 4 = x4 + 4x2 + 4 – 4x2

= (x2 + 2)2 – (2x)2

= (x2 + 2 – 2x)(x2 + 2 + 2x)


20 tháng 4 2017

Bài giải:

a) x2 – 4x + 3 = x2 – x - 3x + 3

= x(x - 1) - 3(x - 1) = (x -1)(x - 3)

b) x2 + 5x + 4 = x2 + 4x + x + 4

= x(x + 4) + (x + 4)

= (x + 4)(x + 1)

c) x2 – x – 6 = x2 +2x – 3x – 6

= x(x + 2) - 3(x + 2)

= (x + 2)(x - 3)

d) x4+ 4 = x4 + 4x2 + 4 – 4x2

= (x2 + 2)2 – (2x)2

= (x2 + 2 – 2x)(x2 + 2 + 2x)

10 tháng 7 2019

\(g,x^2-2xy+y^2-9z^2=\left(x-y\right)^2-\left(3z\right)^2\)\(=\left(x-y+3z\right)\left(x-y-3z\right)\)

\(h,5x^4-20x^2=5x^2\left(x^2-4\right)=5x^2\left(x-2\right)\left(x+2\right)\)

\(i,7x^2-7y^2-14x+14y=7\left(x-y\right)\left(x+y\right)-14\left(x-y\right)\)

\(=\left(x-y\right)\left(7x+7y-14\right)=7\left(x-y\right)\left(x+y-2\right)\)

\(k,x^2+8x+3x+24=x\left(x+8\right)+3\left(x+8\right)=\left(x+8\right)\left(x+3\right)\)

\(m,x^4-y^4=\left(x^2-y^2\right)\left(x^2+y^2\right)=\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\)

\(n,x^6-y^6=\left(x^2-y^2\right)\left(x^4+x^2y^2+y^4\right)=\left(x-y\right)\left(x+y\right)\left(x^4+x^2y^2+y^4\right)\)

Câu 2 nha

\(a,x^4+2x^3+x^2\)

\(=x^2\left(x^2+2x+1\right)\)

\(=x^2\left(x+1\right)^2\)

\(c,x^2-x+3x^2y+3xy^2+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)

26 tháng 9 2019

a) \(3x^2-9x+30=3\left(x^2-3x+10\right)\)

b) \(3x^2-5x-2=3x^2-6x+x-2\)

\(=3x\left(x-2\right)+\left(x-2\right)=\left(3x+1\right)\left(x-2\right)\)

c) \(x^4+4y^4\)

\(=x^4+4y^4+2x^2y^2+2x^2y^2-4x^2y^2+4xy^3-4xy^3+2x^3y-2x^3y\)

\(=\left(4y^4-4xy^3+2x^2y^2\right)+\left(4xy^3-4x^2y^2+2x^3y\right)\)

\(+\left(2x^2y^2-2x^3y+x^4\right)\)

\(=2y^2\left(2y^2-2xy+x^2\right)+2xy\left(2y^2-2xy+x^2\right)\)

\(+x^2\left(2y^2-2xy+x^2\right)\)

\(=\left(2y^2+2xy+x^2\right)\left(2y^2-2xy+x^2\right)\)

d) \(x^5+x+1\)

\(=x^5+x+1+x^4-x^4+x^3-x^3+x^2-x^2\)

\(=\left(x^5-x^4+x^2\right)+\left(x^4-x^3+x\right)+\left(x^3-x^2+1\right)\)

\(=x^2\left(x^3-x^2+1\right)+x\left(x^3-x^2+1\right)+\left(x^3-x^2+1\right)\)

\(=\left(x^2+x+1\right)\left(x^3-x^2+1\right)\)

26 tháng 9 2019

đang cần gấp

12 tháng 8 2018

\(C=x^3+5x^2+8x+4\)

   \(=x^3+x^2+4x^2+4x+4x+4\)

   \(=x^2\left(x+1\right)+4x\left(x+1\right)+4\left(x+1\right)\)

   \(=\left(x^2+4x+4\right)\left(x+1\right)\)

   \(=\left(x+2\right)^2.\left(x+1\right)\)

\(D=x^3-x^2-4\)

    \(=x^3-2x^2+x^2-2x+2x-4\)

    \(=x^2\left(x-2\right)+x\left(x-2\right)+2\left(x-2\right)\)

    \(=\left(x^2+x+2\right)\left(x-2\right)\)

Chúc bạn học tốt.

    

26 tháng 8 2021

Trả lời:

1) sửa đề:  \(x^4+x^3-4x-4=x^3\left(x+1\right)-4\left(x+1\right)=\left(x+1\right)\left(x^3-4\right)\)

2) \(x^2-\left(a+b\right)x+ab=x^2-ax-bx+ab=\left(x^2-ax\right)-\left(bx-ab\right)\)

\(=x\left(x-a\right)-b\left(x-a\right)=\left(x-a\right)\left(a-b\right)\)

3)  \(5xy^3-2xyz-15y^2+6z=\left(5xy^3-15y^2\right)-\left(2xyz-6z\right)\)

\(=5y^2\left(xy-3\right)-2z\left(xy-3\right)=\left(xy-3\right)\left(5y^2-2z\right)\)

27 tháng 10 2021

helpppppp

15 tháng 10 2019

b)=4a2-8ab+4b2-a2-2ab-b2

=3a2-6ab+3b2

=3(a2-2ab+b2)

=3(a-b)2

15 tháng 10 2019

c, 4 - y^2 - x^2 + 2xy

= 4-(x^2 - 2xy + y^2) 

= 4-(x - y)^2 

= (2 - x - y)(2 + x - y)

d, x^2 - 2x - 80

= x^2 + 8x - 10x - 80

= x(x + 8) - 10(x + 8)

= (x - 10(x + 8)

18 tháng 9 2020

27x6 + 125y6 = ( 3x2 )3 + ( 5y2 )3 = ( 3x2 + 5y2 )( 9x4 - 15x2y2 + 25y4 )

8a6 - 8b6 = ( 2a2 )3 - ( 2b2 )3 = ( 2a - 2b )( 4a2 + 4ab + 4b2 ) = 2( a - b )4( a2 + ab + b2 ) = 8( a - b )( a2 + ab + b2 )

x4 + 64y4 = x4 + 16x2y2 + 64y4 - 16x2y2 

                = ( x4 + 16x2y2 + 64y4 ) - 16x2y2

                = ( x2 + 8y2 )2 - ( 4xy )2

                = ( x2 + 8y2 - 4xy )( x2 + 8y2 + 4xy )

x4 + x3 + 2x2 + x + 1 = x4 + x3 + x2 + x2 + x + 1

                                  = ( x4 + x3 + x2 ) + ( x2 + x + 1 )

                                  = x2( x2 + x + 1 ) + ( x2 + x + 1 )

                                  = ( x2 + x + 1 )( x2 + 1 )

\(27x^6+125y^6=\left(3x^2\right)^3+\left(5y^2\right)^3=\left(3x^2+5y^2\right)\left(9x^4-15x^2.y^2+25y^4\right)\)

\(8a^6-8b^6=8\left(a^6-b^6\right)=8\left(\left(a^3\right)^2-\left(b^3\right)^2\right)=8\left(a^3-b^3\right)\left(a^3+b^3\right)\)

                                                       \(=8\left(a-b\right)\left(a^2+ab+b^2\right)\left(a+b\right)\left(a^2-ab+b^2\right)\)

\(x^{\text{4}}+64y^4=x^4+64y^4+16x^2y^2-16x^2y^2\)

                       \(=\left(8y^2+x^2\right)^2-\left(4xy\right)^2=\left(8y^2+x^2+4xy\right)\left(8y^2+x^2-4xy\right)\)

\(x^4+x^3+2x^2+x+1=\left(x^4+2x^2+1\right)+\left(x^3+x\right)\)

\(=\left(x^2+1\right)^2+x\left(x^2+1\right)=\left(x^2+1\right)\left(x^2+x+1\right)\)