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a) 58.57+58.150-58.125
=58.(57+150-125)
=58. 82
= 4756
b)32.5-22.7+83.20190
=9.5-4.7+83
=45-28+83
=100
c)2019+(-247)+(-53)-2019
=(2019-2019)+[ (-247)+(-53)]
0+(-300)
= -300
d)13.70-50 [(19-32):2+23]
=13.70-50[10:2+8]
=13.70-50.13
=13.(70-50)
=13.20
=260
2.
a)x-36:18=12-5
x-36:18=6
x-36=6.18
x-36=108
x=108+36
x= 144
b)92-(17+x)=72
17+x=92-72
17+x=20
x=20-17
x=3
c)720:[41-(2x+5)]=40
41-(2x+5)=720:40
41-(2x+5)= 18
2x+5=41-18
2x+5=23
2x=23-5
2x=18
x=18:2
x=9
d) (x+2)3 -23=41
(x+2)3 =41+23
(x+2)3 =64
=> (x+2)3 =43
=>x+2=4
=>x=4-2
=>x=2
a) Ta có: \(14-\left(5-8\right)^3+\left(-3\right)\cdot5\)
\(=14+27-15=26\)
b) Ta có: \(-7\cdot15+7\cdot\left(-35\right)+\left(-1\right)^{2019}\)
\(=-7\left(15+35\right)-1=-350-1=-351\)
c) Ta có: \(-18\cdot32+\left(-18\right)\cdot45+77\cdot\left(-32\right)-77\cdot50\)
\(=-18\left(32+45\right)+77\left(-32-50\right)\)
\(=-18\cdot77+77\cdot\left(-82\right)=77\left(-18-82\right)=77\cdot\left(-100\right)=-7700\)
d) Ta có: \(104-4\cdot\left[-5\cdot8+\left(7-10\right)^3\right]\)
\(=104-4\left[-40-27\right]=104-4\cdot\left(-67\right)=104+268=372\)
Thực hiện phép tính
1. [ 36 . 4 - 4 . ( 82 - 7 . 11 )2] : 4 - 20190
= [ 36 . 4 - 4 . 25 ] : 4 - 1
= [ 4.(36 - 25)] : 4 - 1
= 44 : 4 - 1
= 11 - 1
= 10
2. 500 - { 5 . [ 409 - ( 23. 3 - 21 )3] - 1724 }
a)
204 - 84 : 12
= 204 - ( 84 : 12 )
= 204 - 7
= 107
b)
15 . 23 + 4 . 32 - 5 . 7
= 15 . 8 + 4 . 9 - 5 . 7
= 120 + 36 - 35
= 156 - 35
= 121
c)
56 : 53 + 23 . 22
= 5(6-3) + 2(3+2)
= 53 + 25
= 125 + 32
= 157
d) 164 . 53 + 47 . 164
= 164 . ( 53 + 47 )
= 164 . 100
= 16400
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
1) 3 . 52 - 16 : 23 = 3 . 25 - 24 : 23
= 75 -2
=73
2) 50 - [ 20 - ( 22 : 2 -12019 ) ] = 50 - [ 20 - (2 - 1) ] ( vì 1 mũ bao nhiêu cũng bằng 1 )
= 50 - ( 20 - 1)
= 50 - 19
= 31
3) 77 - 7x = 56
<=> 7 . ( 11 - x ) = 56
<=> 11 - x = 8
<=> x = 3
4) 32 + 5x = 72
<=> 9 + 5x = 49
<=> 5x = 40
<=> x = 8
5, ( x + 3 )x-2 = 20190
<=> ( x + 3 )x-2 = 1 ( vì số nào mũ 0 cũng bằng 1 )
<=> x + 3 = 1
<=>x = -2
a: =58(57+150-125)=58x82=4756
b: \(=9\cdot5-4\cdot7+83=45-28+83=100\)
c: =(2019-2019)+(-247-53)=-300
d: \(=13\cdot70-50\cdot\left[10:2+8\right]=910-50\cdot13=910-650=260\)
\(a,=58.\left(57+150-125\right)\\ =58.82=4756\\ b,=9.5-4.7+83.1\\ =45-28+83=100\)