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1) 3^4.2+2^3.5-7(5^7:5^5)
=3^4.2+2^3.5-7.5^2
=81.2+8.5-7.25
=162+40-175
=202-175=27
2) 5.2^2.2^3-4(5^8:5^6)
=5.4.8-3.5^2
=160-100=60
3) (3^5.3^7):3^10+5.2^4-7^3:7
=3^12:3^10+5.16-7^2
=3^2+80-7^2
=9+80-49=40
4) 15:(3^5:3^4)-2^9:2^7
=15:3-2^2
=5-4=1
5) 5.3^5:(3^8:3^5)-2^3.5
=5.3^5:3^3-8.5
=5.3^2-40
=5.9-40
=45-40=5
a, \(\left(2x+7\right)^4=10^{11}:10^7\)
\(\Rightarrow\left(2x+7\right)^4=10^4\)
\(\Rightarrow2x+7=10\)
\(\Rightarrow2x=10-7\)
\(\Rightarrow2x=3\)
\(\Rightarrow x=\dfrac{3}{2}\) hay \(x=1,5\)
b, \(5^{x-1}.7^{x-1}=25.49\)
\(\Rightarrow\)\(5^{x-1}.7^{x-1}=5^2.7^2\)
\(\Rightarrow\left\{{}\begin{matrix}5^{x-1}=5^2\\7^{x-1}=7^2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x-1=2\\x-1=2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=3\\x=3\end{matrix}\right.\)
c, \(\left(x-5\right)^{2018}=9.\left(x-5\right)^{2016}\)
\(\Rightarrow\dfrac{\left(x-5\right)^{2018}}{\left(x-5\right)^{2016}}=9.\dfrac{\left(x-5\right)^{2016}}{\left(x-5\right)^{2016}}\)
\(\Rightarrow\left(x-5\right)^2=9\)
\(\Leftrightarrow\left(x-5\right)^2=3^2\)
\(\Rightarrow x-5=3\)
\(\Rightarrow x=3+5\)
\(\Rightarrow x=8\)
a) \(\left(3^5\times3^7\right):3^{10}+5\times2^4-7^3:7=3^{12}:3^{10}+5\times2^4-7^2\)
\(=3^2-5\times16-7^2=9-80-49=-120\)
b) \(15:\left(3^5:3^4\right)-2^9:2^7=15:3-2^2=5-4=1\)
c)\(5\times3^5:\left(3^8:3^5\right)-2^3\times5=5\times3^5:3^3-2^3\times5\)
\(=5\times3^2-2^3\times5=5\times9-8\times5=45-40=5\)
a) (54 + 57) . (89 - 27) . (24 - 42)
= (54 + 57) . (89 - 27) . (16 - 16)
= (54 + 57) . (89 - 27) . 0
= 0
b) (72003 + 72002) : 72001
= 72003 : 72001 + 72002 : 72001
= 72 + 7
= 49 + 7
= 53
c) (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 132)
= (169 - 42 ) × ( 169 - 52 ) ×......× ( 169 - 169)
= (169 - 42 ) × ( 169 - 52 ) ×......× 0
= 0
Tìm x biết
7 × ( x - 14 ) + 39 = 25 + 279 ÷ 9
=> 7 × ( x - 14 ) + 39 = 25 + 31
=> 7 × ( x - 14 ) + 39 = 56
=> 7 × (x - 14) = 56 - 39
=> 7 × (x - 14) = 17
=> x - 14 = 17 : 7
=> x - 14 = 17/7
=> x = 17/7 + 14
=> x = 115/7
\((5^4+4^7)\times(8^9-2^7)\times(2^4-4^2)\)
\(=(5^4+4^7)\times(8^9-2^7)\times0\)
\(=0\)
a: \(\Leftrightarrow2x+7=-4\)
=>2x=-11
hay x=-11/2
b: \(\Leftrightarrow\dfrac{7^x\cdot49+7^x\cdot7+7^x}{57}=\dfrac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
\(\Leftrightarrow7^x=5^{2x}\)
=>x=0
Giải:
a) \(100-7\left(x-5\right)=31+3^3\)
\(\Leftrightarrow100-7\left(x-5\right)=31+27\)
\(\Leftrightarrow100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
\(\Leftrightarrow x=11\)
Vậy ...
b) \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow4\left(x-1\right)=64+8\)
\(\Leftrightarrow4\left(x-1\right)=72\)
\(\Leftrightarrow x-1=18\)
\(\Leftrightarrow x=19\)
Vậy ...
c) \(24+5x=7^5:7^3\)
\(\Leftrightarrow24+5x=7^2\)
\(\Leftrightarrow24+5x=49\)
\(\Leftrightarrow5x=25\)
\(\Leftrightarrow x=5\)
Vậy ...
d) \(5x-206=2^4.4\)
\(\Leftrightarrow5x-206=2^6\)
\(\Leftrightarrow5x-206=64\)
\(\Leftrightarrow5x=270\)
\(\Leftrightarrow x=54\)
Vậy ...
\(7^7:7^5+2^{4+x}=177\)
\(\Rightarrow7^2+2^{4+x}=177\)
\(\Rightarrow2^4.2^x=177-49\)
\(\Rightarrow16.2^x=128\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)