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1/
Ta có:
356 - 355 + 354 - 353 = 353.33 - 353.32 + 353.3 - 353.1
= 353(33 - 32 +3 - 1)
=353.20
Vì 20\(⋮\)20 nên 353.20\(⋮\)20
hay 356 - 355 + 354 - 353\(⋮\)20 (đccm)
2/
Ta có: 231 + 230 = 230.2 + 230.1
=230(2 + 1)
=230.3 \(⋮\)3 (vì 3\(⋮\)3)
hay 231 + 230\(⋮\)3
Mà 329\(⋮\)3 (lũy thừa của 3) ; 328\(⋮\)3 (lũy thừa của 3)
\(\Rightarrow\)231 + 230 - 329 - 328 \(⋮\)3 (đccm)
5^6+5^7+5^8
=5^6.(1+5+5^2)
=5^6.31 chia hết cho 31
7^6+7^5-7^4
=7^4.(7^2+7-1)
=7^4.55 chia hết cho 11
BÀI 2:
a) \(5^6+5^7+5^8=5^6\left(1+5+5^2\right)=5^6.31\) \(⋮\)\(31\)
b) \(7^6+7^5-7^4=7^4.\left(7^2+7-1\right)=7^4.55\)\(⋮\)\(11\)
c) \(2^3+2^4+2^5=2^3.\left(1+2+2^2\right)=2^3.7\)\(⋮\)\(7\)
d) mk chỉnh đề
\(1+2+2^2+2^3+...+2^{59}\)
\(=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{58}+2^{59}\right)\)
\(=\left(1+2\right)+2^2\left(1+2\right)+...+2^{58}\left(1+2\right)\)
\(=\left(1+2\right)\left(1+2^2+...+2^{58}\right)\)
\(=3\left(1+2^2+...+2^{58}\right)\)\(⋮\)\(3\)
28.37+37:28+37
=28.37+37.\(\frac{1}{2^8}\)+37
=(28+\(\frac{1}{2^8}\)+1).37
=\(\approx\)562067,543
a) \(63^7< 64^7=\left(2^6\right)^7=2^{42}< 2^{48}=\left(2^4\right)^{12}=16^{12}\Rightarrow63^7< 16^{12}\)
b) \(3^{151}>3^{150}=\left(3^2\right)^{75}=9^{75}>8^{75}=\left(2^3\right)^{75}=2^{225}\)
c) \(9^{20}=\left(3^2\right)^{20}=3^{40}>3^{39}=\left(3^3\right)^{13}=27^{13}\Rightarrow9^{20}>27^{13}\)
bài 2:
a)\(2^x=32\Leftrightarrow2^x=2^5\Leftrightarrow x=5\)
b)\(2x+3^4=7^2\Leftrightarrow2x+81=49\Leftrightarrow2x=-32\Leftrightarrow x=-16\)
c)\(12x-33=3^2\Leftrightarrow12x-33=9\Leftrightarrow12x=42\Leftrightarrow x=\frac{7}{2}\)
\(\left(-1\right)^3.\left(-\frac{7}{8}\right)^3.\left(-\frac{2}{7}\right)^2.\left(-7\right).\left(-\frac{1}{14}\right)=\left(-1\right).\left(-\frac{343}{512}\right).\left(-\frac{4}{49}\right).\left(-7\right).\left(-\frac{1}{14}\right)=-\frac{343.4.7}{512.49.14}=\frac{7}{256}\)
\(\left(3x-7\right)^3=2^3.3^2+53\)
\(\left(3x-7\right)^3=8.9+53=125\)
\(\Leftrightarrow\left(3x-7\right)^3=125=5^3\)
\(\Leftrightarrow3x-7=5\)
\(\Leftrightarrow3x=5+7\)
\(\Leftrightarrow3x=12\)
\(\Leftrightarrow x=12:3\)
\(\Leftrightarrow x=4\)
(3x−7)3=23.32+53(3x-7)3=23.32+53
⇔(3x−7)3=8.9+53⇔(3x-7)3=8.9+53
⇔(3x−7)3=72+53⇔(3x-7)3=72+53
⇔(3x−7)3=125⇔(3x-7)3=125
⇔3x−7=5⇔3x-7=5
⇔3x=5+7⇔3x=5+7
⇔3x=12⇔3x=12
⇔x=12:3⇔x=12:3
⇔x=4⇔x=4
Vậy x=4
đây em nhé
x=4