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a)\(x^{10}=1^x\Leftrightarrow x=1\)
b) \(x^{10}=x\Leftrightarrow\hept{\begin{cases}x=0\\x=1\end{cases}}\)
c) \(\left(2x-15\right)^5=\left(2x-15\right)^3.4\)
\(\Leftrightarrow2x-15=0\Leftrightarrow2x=15\Leftrightarrow x=\frac{15}{2}\)
nếu thắc mắc vì sao \(2x-15=1\)vì nếu như vậy ta có vế trái =1 nhưng vế phải lại phải nhân cho 4 nên vế trái ko = vế phải
d) \(a^x-15=17\)
\(\Leftrightarrow a^x=32\)
\(\Leftrightarrow a^x=2^5\)
g) \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=800+200\)
\(\Leftrightarrow\left(7x-11\right)^3=1000\)
\(\Leftrightarrow\left(7x-11\right)^3=10^3\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=21\)
\(\Leftrightarrow x=21:7=3\)
a) 52x+1=125
=>52x+1= 53
=>2x+1=3
=>2x = 2
=>x =1
c)73<x <=93
=>343<x<=729
=> x = { 344;345;...;729}
d) (2x+3)4=81
=>(2x+3)4=34
=>2x+3 =3
=>2x =0
=> x = 0
nhớ tk nha
a)52x+1=125
52x+1=53
⏩ 2x+1=3
2x=4
x=4:2
x=2
b) (2x)2(2x) 3 =25.25
(2x) 2 (2x) 3 =210
(2x) 5=1024
(2x) 5 =45
2x=4
x=4 :2=2
d)(2x +3)4=81
(2x +3)4=34
2x+3=3
2x=0
x=0
Câu c bạn tự giải nhé
Nhớ tk giùm mình đấy
\(3^3\cdot76+84\cdot27+3^3\cdot3\cdot40\)
\(=\) \(27\cdot76+84\cdot27+27\cdot120\)
\(=\) \(27\cdot\left(76+84+120\right)\)
\(=\) \(27\cdot280\)
\(=560\)
Bài 3
\(a.\) \(5^{2x+1}=125\)
\(5^{2x+1}=5^3\)
\(2x+1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
\(a,4^x=64\)
\(4^x=4^3\)
\(x=3\)
\(b,3\cdot\left(5^x-16\right)=3^3\)
\(5^x-16=3^3:3=3^2\)
\(5^x-16=9\)
\(5^x=9+16=25\)
\(5^x=5^2\)
\(x=2\)
\(2^x=2\Rightarrow x=1\)
\(2^{2x+2}=8^2\Rightarrow2^{2x+2}=2^6\Rightarrow2x+2=6\)\(2x=6-2=3\Rightarrow x=3:2=\frac{3}{2}\)
a) \(4^x=2^{x+1}\)
\(2^{2x}=2^{x+1}\)
\(\Rightarrow2x=x+1\)
\(\Rightarrow2x-x=1\)
\(\Rightarrow x=1\)
b) \(16=\left(x-1\right)^4\)
\(2^4=\left(x-1\right)^4\)
\(\Rightarrow x-1=2\)
\(\Rightarrow x=3\)
c) \(x^{10}=1^x\)
\(x^{10}=1\)
\(x^{10}=1^{10}\)
\(\Rightarrow x=1\)
d) \(x^{10}=x\)
\(x^{10}-x=0\)
\(x\left(x^9-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x^9-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
e) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=\pm1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{15}{2}\\x=\left\{8;7\right\}\end{cases}}\)
\(A,4^X=2^{X+1}\)
\(\left(2^2\right)^X=2^{X+1}\)
\(\Rightarrow2^{2X}=2^{X+1}\)
\(\Rightarrow2X=X+1\)
\(\Rightarrow2X-X=1\Leftrightarrow X=1\)
\(B,16=\left(x-1\right)^4\)
\(\Rightarrow x-1=\hept{\begin{cases}2\\-2\end{cases}}\)
\(\Rightarrow x=\hept{\begin{cases}3\\-1\end{cases}}\)