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a)\(\left(x+8\right)-11=20-15\)
\(\left(x+8\right)-11=5\)
\( x+8=5+11\)
\(x+8=16\)
\(x=8\)
b) \(2x-\left(3+x\right)=5-7\)
\(2x-\left(3+x\right)=-2\)
\(2x-3-x=-2\)
\(x=1\)
c) \( \left(3x-2^4\right)\times7^5=2\times7^6\)
\(3x-2^4=2\times\left(7^6:7^5\right) \)
\(\left(3x-2^4\right)=2\times7^2\)
\(3x-2^4=2\times49\)
\(3x-16=98\)
\(3x=114\)
\(x=38\)
\(-2\left(2x-8\right)+3\left(4-2x\right)=-72-5\left(3x-7\right)\)
\(-4x+16+12-6x=-72-15x+35\)
\(-4x-6x+15x+28=-72+35\)
\(5x+28=-37\)
\(5x=-65\)
\(x=-13\)
Vậy \(x=-13.\)
-2(2x-8) + 3(4-2x) = -72 - 5(3x - 7)
\(\Leftrightarrow\)-4x +16 +12 - 6x = -72 - 15x + 35
\(\Leftrightarrow\)-4x - 6x +15x = 35 - 72 - 16 - 12
\(\Leftrightarrow\)5x = -65
\(\Leftrightarrow\)x=-13
k cho mk nha :)
\(a,\frac{62}{7}:x=\frac{29}{9}:\frac{3}{56}\)
\(\frac{62}{7}:x=\frac{1624}{27}\)
\(x=\frac{62}{7}:\frac{1624}{27}=\frac{837}{5684}\)
\(b,\frac{1}{5}:x=\frac{1}{5}-\frac{1}{7}\)
\(\frac{1}{5}:x=\frac{2}{35}\)
\(x=\frac{1}{5}:\frac{2}{35}=\frac{7}{2}\)
\(c,\frac{2}{3}.x-\frac{4}{7}=\frac{1}{7}\)
\(\frac{2}{3}.x=\frac{1}{7}+\frac{4}{7}=\frac{5}{7}\)
\(x=\frac{5}{7}:\frac{2}{3}=\frac{15}{14}\)
\(d,\frac{2}{7}-\frac{8}{9}.x=\frac{2}{3}\)
\(\frac{8}{9}.x=\frac{2}{7}-\frac{2}{3}=-\frac{8}{21}\)
\(x=-\frac{8}{21}:\frac{8}{9}=-\frac{3}{7}\)
\(e,\frac{4}{7}+\frac{5}{9}:x=\frac{1}{5}\)
\(\frac{5}{9}:x=\frac{1}{5}-\frac{4}{7}=-\frac{13}{35}\)
\(x=\frac{5}{9}:-\frac{13}{35}=\frac{175}{117}\)
\(i,\frac{2}{5}-\frac{2}{5}.x=\frac{2}{5}\)
\(\frac{2}{5}.\left(1-x\right)=\frac{2}{5}\)
\(1-x=\frac{2}{5}:\frac{2}{5}=1\)
\(x=1-1=0\)
\(g,\frac{2}{3}+\frac{1}{3}:x=-1\)
\(\frac{1}{3}:x=-1-\frac{2}{3}=-\frac{5}{3}\)
\(x=\frac{1}{3}:-\frac{5}{3}=-\frac{1}{5}\)
học tốt nha
\(\frac{7}{6}+\frac{5}{6}:5-\frac{3}{8}.\left(-3\right)^2\)
\(=\frac{7}{6}+\frac{5}{6}.\frac{1}{5}-\frac{3}{8}.9\)
\(=\frac{7}{6}+\frac{1}{6}-\frac{27}{8}\)
\(=\frac{8}{6}-\frac{27}{8}\)
\(=\frac{32}{24}-\frac{81}{24}\)
\(=\frac{-49}{24}\)
Chúc bạn học tốt !!!
\(\dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=\dfrac{-8}{5}\\ \dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{6x}{15}-\dfrac{10}{15}\right)=-\dfrac{8}{5}\\ \dfrac{3}{8}-\dfrac{1}{2}:\dfrac{6x-10}{15}=-\dfrac{8}{5}\\ \dfrac{1}{2}:\dfrac{6x-10}{15}=\dfrac{3}{8}+\dfrac{8}{5}\\ \dfrac{1}{2}\cdot\dfrac{15}{6x-10}=\dfrac{79}{40}\\ \dfrac{15}{6x-10}=\dfrac{79}{20}\\ 6x-10=15:\dfrac{79}{20}\\ 6x-10=\dfrac{300}{79}\\ 6x=\dfrac{300}{79}+10\\ 6x=\dfrac{1090}{79}\\ x=\dfrac{1090}{79}:6\\x =\dfrac{545}{237}\)
\(\dfrac{3}{8}-\dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=-\dfrac{8}{5}\\ \dfrac{1}{2}:\left(\dfrac{2x}{5}-\dfrac{2}{3}\right)=\dfrac{79}{40}\\ \dfrac{2x}{5}-\dfrac{2}{3}=\dfrac{20}{79}\\ \dfrac{2x}{5}=\dfrac{218}{237}\\ 2x=\dfrac{1090}{237}\\ x=\dfrac{545}{237}\)