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\(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
\(\Rightarrow\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}x=-\frac{29}{70}\)
\(\Rightarrow x=-\frac{29}{70}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{87}{140}\)
tíc mình nha
1.a) Sửa lại đề: \(\frac{11}{17}\)ở mẫu chuyển thành \(\frac{11}{7}\)
\(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}=\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{7}-\frac{3}{13}}{\frac{11}{4}+\frac{11}{5}-\frac{11}{7}-\frac{11}{13}}\)\(=\frac{3\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}{11\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}=\frac{3}{11}\)
( vì \(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\ne0\))
2.a) \(\frac{3}{5}+\frac{3}{2}.x=\frac{-5}{7}\)\(\Leftrightarrow\frac{3}{2}.x=\frac{-5}{7}-\frac{3}{5}\)
\(\Leftrightarrow\frac{3}{2}.x=\frac{-46}{35}\)\(\Leftrightarrow x=\frac{-46}{35}:\frac{3}{2}\)\(\Leftrightarrow x=\frac{-92}{105}\)
Vậy \(x=\frac{-92}{105}\)
b) \(\left(4x-\frac{1}{3}\right).\left(\frac{3}{2}x+\frac{5}{6}\right)=0\)\(\Leftrightarrow\orbr{\begin{cases}4x-\frac{1}{3}=0\\\frac{3}{2}x+\frac{5}{6}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}4x=\frac{1}{3}\\\frac{3}{2}x=\frac{-5}{6}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{12}\\x=\frac{-5}{9}\end{cases}}\)
Vậy \(x=\frac{-5}{9}\)hoặc \(x=\frac{1}{12}\)
a) \(\frac{1}{4}+\frac{1}{3}:2x=-5\)
\(\frac{1}{3}:2x=\frac{-21}{4}\)
\(2x=\frac{-4}{63}\)
\(x=\frac{2}{63}\)
b) \(\left(3x-\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-\frac{1}{4}=0\\x+\frac{1}{2}=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{12}\\x=\frac{-1}{2}\end{cases}}\)
Vậy.........
x+1/3-4=-1
=>x+1/3=-1+4
=>x+1/3=3
=>x =3-1/3
=>x =8/3
Vậy x = 8/3
(2/25-1,008):4/7:(13/4-6/5/9)*36/17
=(2/25-126/125).7/4:(13/4-59/9)*36/17
=(10/125-126/125).7/4:(117/36-236/36)*36/17
=-116/125.7/4.(-36/119).36/17
=-203/125.(-1296/2023)=263088/252875
Mình tính ko nhanh đâu
a) \(\frac{1}{2}+\frac{2}{3}:x=\frac{3}{4}\)
=> \(\frac{2}{3}:x=\frac{3}{4}-\frac{1}{2}\)
=> \(\frac{2}{3}:x=\frac{1}{4}\)
=> \(x=\frac{2}{3}:\frac{1}{4}=\frac{8}{3}\)
b) \(5,4-3\left|x-\frac{21}{10}\right|=0\)
=> \(3\left|x-\frac{21}{10}\right|=\frac{27}{5}\)
=> \(\left|x-\frac{21}{10}\right|=\frac{27}{5}:3=\frac{9}{5}\)
=> \(\left|x-\frac{21}{10}\right|=\frac{9}{5}\)
Trường hợp 1 : \(x-\frac{21}{10}=\frac{9}{5}\)
=> \(x=\frac{9}{5}+\frac{21}{10}=\frac{39}{10}\)
Trường hợp 2 : \(x-\frac{21}{10}=-\frac{9}{5}\)
=> \(x=-\frac{9}{5}+\frac{21}{10}=\frac{3}{10}\)
Vậy : ...
c) \(10\sqrt{x-5}=25\)
=> \(\sqrt{x-5}=\frac{5}{2}\)
=> \(\left(x-5\right)^2=\frac{25}{4}\)
Trường hợp 1 :
\(x-5=\frac{25}{4}\)=> \(x=\frac{25}{4}+5=\frac{45}{4}\)
Trường hợp 2 :
\(x-5=-\frac{25}{4}\)=> \(x=-\frac{25}{4}+5=-\frac{5}{4}\)(loại)
Vậy \(x=\frac{45}{4}\)