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a) 4+(12-15) và 4+12-15
4+(-3) và 16-15
1 và 1
=> Bằng nhau
b) 4-(12-15) và 4-12+15
4-(-3) và -8+15
7 và 7
=> bằng nhau
Chuyển dấu '' - '' của -7/12 sang cho 4/19 thứ 2
=> -4/9 x ( 5/12 + 7/12 ) - 15/19
= -4/9 x 1 - 15/19
= -4/9 - 15/9
= -19/9
\(-8.4+19=-32+19=-13\)
\(-11.3-28=-33-28=-61\)
\(4.\left(-15\right)-18=-60-18=-78\)
\(19-4.\left(-12\right)=19+48=67\)
\(-25.\left(-3\right)-54=75-54=21\)
\(-16-7.\left(-4\right)+24\div\left(-8\right)=-16+28-3=9\)
\(15\div\left(-3\right)+30-7.\left(-3\right)=-5+30+21=46\)
\(-48\div\left(-4\right)+15.\left(-5\right)=12-75=-63\)
\(-29+65\div\left(-5\right)+23=-29-13+23=-19\)
\(15\div\left(-5\right)-17-12.\left(-5\right)=-3-17+60=40\)
\(28.\left(-4\right)-17=-112-17=-129\)
\(-19-7.4=-19-28=-47\)
\(-14.\left(-2\right)-16=28-16=12\)
\(13.\left(-3\right)-65-4.\left(-6\right)=-39-65+24=-80\)
\(-24-8.\left(-6\right)+28=-24+48+28=52\)
Chúc bạn hok tốt!!! tỷ tỷ
\(B=1\frac{6}{41}\cdot\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}\div\frac{4+\frac{4}{15}+\frac{4}{4}+\frac{4}{2013}}{5+\frac{5}{15}+\frac{5}{4}+\frac{5}{2013}}\right)\cdot\frac{124242423}{237373735}\)
\(B=\frac{47}{41}\cdot\left[\frac{12\left(1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}\right)}{3\left(1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}\right)}\div\frac{4\left(1+\frac{1}{15}+\frac{1}{4}+\frac{1}{2013}\right)}{5\left(1+\frac{1}{15}+\frac{1}{4}+\frac{1}{2013}\right)}\right]\cdot\frac{123}{235}\)
\(B=\frac{47}{41}\cdot\left[\frac{12}{3}\div\frac{4}{5}\right]\cdot\frac{123}{235}\)
\(B=\frac{3}{5}\cdot3\cdot\frac{5}{4}\)
\(B=\frac{9}{4}\)
1) \(\frac{4}{5}.x=\frac{8}{35}\Rightarrow x=\frac{8}{25}:\frac{4}{5}\Rightarrow x=\frac{2}{5}\)
\(\frac{2}{3}.x+\frac{1}{4}=\frac{7}{12}\Rightarrow\frac{2}{3}.x=\frac{7}{12}-\frac{1}{4}\)
\(\Rightarrow\frac{2}{3}.x=\frac{1}{3}\)
\(\Rightarrow x=\frac{1}{3}:\frac{2}{3}\)
\(x=\frac{1}{2}\)
\(\frac{x}{10}=\frac{3}{10}\Rightarrow x=\frac{10.3}{10}\Rightarrow x=3\)
a) Ta có: \(\frac{-6}{12}< \frac{x}{12}< \frac{-4}{12}\Rightarrow-6< x< -4\Rightarrow x=-5\)
b) \(\frac{-6}{5}+\frac{13}{15}< \frac{x}{15}< \frac{-2}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{-1}{3}< \frac{x}{15}< \frac{-1}{15}\)
\(\Rightarrow\frac{-5}{15}< \frac{x}{15}< \frac{-1}{15}\)
\(\Rightarrow-5< x< -1\)
\(\Rightarrow x=\left\{-4;-3;-2\right\}\)
a: \(=\dfrac{15}{4}:\dfrac{2-7}{16}-\dfrac{5}{9}\cdot\left(\dfrac{3}{5}+\dfrac{4}{5}\right)\)
\(=\dfrac{15}{4}\cdot\dfrac{16}{-5}-\dfrac{5}{9}\cdot\dfrac{7}{5}\)
\(=\dfrac{-240}{20}-\dfrac{7}{9}=-12-\dfrac{7}{9}=\dfrac{-115}{9}\)
c: \(=\dfrac{1}{5}-\dfrac{7}{2}-\dfrac{3}{2}+\dfrac{5}{4}\)
\(=\dfrac{4+25}{20}-5=\dfrac{29}{20}-\dfrac{100}{20}=\dfrac{-71}{20}\)
d: \(=\dfrac{12}{17}\left(1-\dfrac{1}{15}-\dfrac{4}{5}+1\right)=\dfrac{12}{17}\cdot\dfrac{17}{15}=\dfrac{12}{15}=\dfrac{4}{5}\)
e: \(=\dfrac{2}{15}\cdot\dfrac{9}{8}-\dfrac{7}{4}\cdot\dfrac{9}{8}+\dfrac{25}{36}\)
\(=\dfrac{9}{8}\left(\dfrac{2}{15}-\dfrac{7}{4}\right)+\dfrac{25}{36}\)
\(=\dfrac{9}{8}\cdot\dfrac{8-105}{60}+\dfrac{25}{36}\)
\(=\dfrac{9}{8}\cdot\dfrac{-97}{60}+\dfrac{25}{36}=\dfrac{-1619}{1440}\)
\(5^{12}.7-5^{11}.10\)
\(=5^{11}.\left(5.7-10\right)\)
\(=5^{11}.25\)
\(=5^{11}.5^2\)
\(=5^{13}\)
\(2^{20}.15+2^{20}.85\)
\(=2^{20}.5\left(3+17\right)\)
\(=2^{20}.100\)
\(=104857600\)
\(125^3:25^4\)
\(=\left(5^3\right)^3:\left(5^2\right)^4\)
\(=5^9:5^8\)
\(=5\)
\(24^4:3^4-32^{12}:16^{12}\)
\(=\left(24:3\right)^4-\left(32:16\right)^{12}\)
\(=8^4-2^{12}\)
\(=0\)
\(a.=5-3+12-4-16\)
\(=-2\)
\(b.=-6-\left(-12\right)+7-10\)
\(=6+7-10\)
\(=3\)
\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
a: =-5-7-8-3=-26
b: =-4-2-5-6=-17
c: =-8-11-4-2=-25
d: -9-15-6-3=-30
e: =-12-9-3-8=-32
12 - 4 = 8
12 - (-4) = 12 + 4 = 16
-12 - (-4) = -12 + 4 = -8
12 + (-4) = 12 - 4 = 8
15 - (-5) = 15 + 5 = 20
12 - 4 = 8
12 - ( -4) = 12 + 4 = 16
-12 - ( -4) = -12 + 4 = - ( 12 - 4 ) = -8
12 + ( -4) = 12 - 4 =8
15 - ( -5) = 15 + 5 =20