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[(46-32)^2-(54-42)^2]*36-1872
=(14^2-12^2)*36-1872
=(196-144).36-1872
=52.36-1872
=1872-1872
=0
(x-7)^7=(x-7)^8
=>(x-7)^7-(x-7)^8=0
=>(x-7)^7.1-(x-7)^7.(x-7)=0
=>(x-7)^7.[1-(x-7)]=0
\(\Rightarrow\orbr{\begin{cases}x-7=0\\1-\left(x-7\right)=0\end{cases}\Rightarrow\orbr{\begin{cases}x=7;-7\\x=0\end{cases}}}\)
Vậy x={7;-7;0}
1+2^3+3^3-4^2.x=20
=>36-4^2.x=20
=>4^2.x=16=4^2
=>2.x=2
=>x=1
a,x-(20-3x)=x+7
=>x-20+3x=x+7
=>x-20+3x-x=7
=>x+3x-x=7+20
=>3x=27
=>x=27:3
=>x=9
a) 8 + 2x = 20
2x = 20 - 8
2x = 12
x = 12 : 2
x = 6
Vậy x = 6
b) 70 - 5(x - 3) = 45
5(x-3) = 70 - 45
5(x-3) = 25
x - 3 = 25 : 5
x - 3 = 5
x = 5 + 3
x = 8
Vậy x = 8
c) (3x - 2^4). 7^3 = 2. 7^4
(3x - 16) . 147 = 2 . 1029
(3x - 16) . 147 = 2058
3x - 16 = 2058 : 147
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
Vậy x = 10
a/ 8+2.x=20
2x=20-8
2x=12
x=12:2=4
b/70-5.(x-3)=45
5.(x-3)=70-45=25
x-3=25:5=5
x=5+3=8
c/(3.x-24).73=2.74
(3.x-24).73=4802
3x-24 =4802:73=14
3x=14+24=30
x=30:3=10
tk nhen
a. x - (17 - 8) = 5 + (10 - 3x)
=> x - 9 = 5 + 10 - 3x
=> x + 3x = 15 + 9
=> 4x = 24
=> x = 6
b. 25 - (30 + x) = x - (27 - 8)
=> 25 - 30 - x = x - 19
=> -x -x = -19 + 30 - 25
=> -2x = -14
=> x = 7
c. (x - 12) - 15 = (20 - 7) - (18 + x)
=> x - 12 - 15 = 13 - 18 - x
=> x + x = 13 - 18 + 12 + 15
=> 2x = 22
=> x = 11
a,\(\left(\frac{7}{5}-2x\right).\frac{40}{20}=\frac{8}{14}\)
\(\Rightarrow\left(\frac{7}{5}-2x\right).2=\frac{4}{7}\)
\(\Rightarrow\frac{7}{5}-2x=\frac{4}{7}:2\)
\(\Rightarrow\frac{7}{5}-2x=\frac{2}{7}\)
\(\Rightarrow2x=\frac{7}{5}-\frac{2}{7}\)
\(\Rightarrow2x=\frac{39}{35}\)
\(\Rightarrow x=\frac{39}{35}:2\)
\(\Rightarrow x=\frac{39}{70}\)
b, \(\frac{7}{2}.x-20\%.x=-4\)
\(\Rightarrow x\left(\frac{7}{2}-20\%\right)=-4\)
\(\Rightarrow x\left(\frac{7}{2}-\frac{1}{5}\right)=-4\)
\(\Rightarrow x\frac{7}{10}=-4\)
\(\Rightarrow x=-4:\frac{7}{10}\)
\(\Rightarrow x=-\frac{40}{7}\)
Bài 1:
a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)
\(=\dfrac{9}{20}-\dfrac{2}{9}\)
\(=\dfrac{41}{180}\)
b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)
\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)
\(=\dfrac{5}{6}\times\dfrac{12}{7}\)
\(=\dfrac{10}{7}\)
c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)
\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{9}\times1\)
\(=\dfrac{7}{9}\)
Bài 2:
a) \(2\times\left(x-1\right)=4026\)
\(\left(x-1\right)=4026\div2\)
\(x-1=2013\)
\(x=2014\)
Vậy: \(x=2014\)
b) \(x\times3,7+6,3\times x=320\)
\(x\times\left(3,7+6,3\right)=320\)
\(x\times10=320\)
\(x=320\div10\)
\(x=32\)
Vậy: \(x=32\)
c) \(0,25\times3< 3< 1,02\)
\(\Leftrightarrow0,75< 3< 1,02\) ( S )
=> \(0,75< 1,02< 3\)
a)x-13=-5+8
x-13=3
x=3+13
x=16 hoặc -10
b)|x-2|=|-5|
|x-2|=5|
|x|=5+2
|x|=7
x=7 hoặc -7
c)25-(30+x)=x-(27-8)
25-(30+x)=x-19
...còn lại mình bó tay
d)bó tay luôn
\(\dfrac{7}{8}+x=\dfrac{7}{20}\)
=>\(x=\dfrac{7}{20}-\dfrac{7}{8}=\dfrac{14}{40}-\dfrac{35}{40}=-\dfrac{21}{40}\)
=)x=7/20-7/8
=)x=-21/40