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\(R_{12}=\dfrac{R_1R_2}{R_1+R_2}=\dfrac{4\cdot4}{4+4}=2\left(\Omega\right)\)
\(R_{34}=R_3+R_4=3+5=8\left(\Omega\right)\)
\(R_{345}=\dfrac{R_5R_{34}}{R_5+R_{34}}=\dfrac{8\cdot8}{8+8}=4\left(\Omega\right)\)
\(R_{tđ}=R_{12}+R_{345}=2+4=6\left(\Omega\right)\)
\(I_{12}=I_{345}=I=\dfrac{U}{R_{tđ}}=\dfrac{12}{6}=2\left(A\right)\)
\(U_1=U_2=U_{12}=I_{12}\cdot R_{12}=2\cdot2=4\left(V\right)\)
\(U_5=U_{34}=U_{345}=I_{345}\cdot R_{345}=2\cdot4=8\left(V\right)\)
\(I_1=\dfrac{U_1}{R_1}=\dfrac{4}{4}=1\left(A\right)\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{4}{4}=1\left(A\right)\)
\(I_3=I_4=I_{34}=\dfrac{U_{34}}{R_{34}}=\dfrac{8}{8}=1\left(A\right)\)
\(I_5=\dfrac{U_5}{R_5}=\dfrac{8}{8}=1\left(A\right)\)
Bai 2:
R1ntR2
\(\Rightarrow U_2=U-U_1=12-3=9\left(V\right)\)
\(I=I_1=I_2=\dfrac{U_2}{R_2}=\dfrac{9}{9}=1\left(A\right)\)
\(R_1=\dfrac{U_1}{I_1}=\dfrac{3}{1}=3\Omega\)
+ - R1 R2 R3 A
R1ntR2ntR3 =>I=I1=I2=I3=1(A)
\(U_3=U-U_1-U_2=18-5.1-10.1=3\left(V\right)\)
\(R_3=\dfrac{U_3}{I_3}=\dfrac{3}{1}=3\Omega\)