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a: \(\Leftrightarrow\dfrac{1}{4}x-1+\dfrac{2}{3}x-2-\dfrac{5}{8}x-1=5\)
\(\Leftrightarrow x\cdot\dfrac{7}{24}-4=5\)
\(\Leftrightarrow x\cdot\dfrac{7}{24}=9\)
hay x=216/7
b: \(\Leftrightarrow2x-10-\left[3x-13-3+5x-4\right]=7\)
\(\Leftrightarrow2x-10-\left(8x-20\right)=7\)
=>2x-10-8x+20=7
=>-6x+10=7
=>-6x=-3
hay x=1/2
c: \(\Leftrightarrow\left(\left|2x-1\right|-3\right)\cdot\left(-2\right)=6+5=11\)
\(\Leftrightarrow\left|2x-1\right|-3=-\dfrac{11}{2}\)
=>|2x-1|=-5/2(vô lý)
a: \(\Leftrightarrow x^3-3x^2+3x-1-x^3+2x^2-x=5x\left(2-x\right)-11\left(x+2\right)\)
=>-x^2+2x-1=10x-5x^2-11x-22
=>-x^2+2x-1=-5x^2-x-22
=>4x^2+3x+21=0
=>PTVN
b: \(\Leftrightarrow\left(x+10\right)\left(x+4\right)+3\left(x+4\right)\left(x-2\right)=4\left(x+10\right)\left(x-2\right)\)
=>x^2+14x+40+3(x^2+2x-8)=4(x^2+8x-20)
=>x^2+14x+40+3x^2+6x-24=4x^2+32x-80
=>20x+16=32x-80
=>-12x=-96
=>x=8
c: \(\Leftrightarrow6\left(x-3\right)+7\left(x-5\right)=13x+4\)
=>6x-18+7x-35=13x+4
=>-53=4(loại)
d: =>3(2x-1)-5(x-2)=3(x+7)
=>6x-3-5x+10=3x+21
=>3x+21=x+7
=>x=-7
e: =>x^3-6x^2+12x-8-x^3-3x^2-3x-1=-9x^2+1
=>-9x^2+9x-9=-9x^2+1
=>9x=10
=>x=10/9
1: =>3x+1=4
=>3x=3
hay x=1
2: \(\Leftrightarrow172\cdot x^2=\dfrac{1}{2^3}+\dfrac{7^9}{98^3}=\dfrac{1}{2^3}+\dfrac{7^9}{7^6\cdot2^3}\)
\(\Leftrightarrow172\cdot x^2=\dfrac{1}{2^3}+\dfrac{7^3}{2^3}=\dfrac{344}{2^3}\)
\(\Leftrightarrow x^2=\dfrac{1}{4}\)
=>x=1/2 hoặc x=-1/2
3: \(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{2}{9}=\dfrac{4}{9}\\x-\dfrac{2}{9}=-\dfrac{4}{9}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{2}{9}\end{matrix}\right.\)
4: =>x+2=0 và y-1/10=0
=>x=-2 và y=1/10
\(\left(\dfrac{x}{2}+3\right)\left(5-6x\right)+\left(12x-2\right)\left(\dfrac{x}{4}+3\right)=0\)
\(\dfrac{5x}{2}-3x^2+15-18x+3x^2+36x-\dfrac{x}{2}-6=0\)
\(\dfrac{5x}{2}-\dfrac{x}{2}+18x+9=0\)
\(20x+9=0\)
\(x=\dfrac{-9}{20}\)