Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
b) \(697:\frac{15x+364}{x}=17\)
\(\frac{15x+364}{x}=697:17\)
\(\frac{15x+364}{x}=41\)
\(15+\frac{364}{x}=41\)
\(\frac{364}{x}=41-15\)
\(\frac{364}{x}=26\)
\(\Rightarrow x=14\)
\(T=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2008.2010}\)
\(T=2.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{2008.2010}\right)\)
\(T=2.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)
\(T=2.\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(T=2.\frac{502}{1005}=\frac{1004}{1005}\)
\(\Rightarrow T=\frac{1004}{1005}\)
\(A=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{2007.2009}+\frac{1}{2009+2011}\)
\(A=\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{2009+2011}\right)\)
\(A=\frac{1}{2}.\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2009}-\frac{1}{2011}\right)\)
\(A=\frac{1}{2}.\left(1-\frac{1}{2011}\right)\)
\(A=\frac{1}{2}.\frac{2010}{2011}\)
\(\Rightarrow A=\frac{1005}{2011}\)
\(F=\left(1000-1^3\right).\left(1000-2^3\right)....\left(1000-2015^3\right)\)
\(F=\left(1000-1^3\right).\left(1000-2^3\right).....\left(1000-10^3\right)......\left(1000-2015^3\right)\)
\(F=\left(1000-1^3\right).\left(1000-2^3\right)....0.....\left(1000-2015^3\right)\)
\(F=0\)
\(\dfrac{2006\times2005-1}{2004\times2006+2005}=\dfrac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}\)
\(=\dfrac{2004\times2006+2006-1}{2004\times2006+2005}=\dfrac{2004\times2006+2005}{2004\times2006+2005}\)
\(=1\)
\(18\times\left(\dfrac{19191919+88888}{21212121+99999}\right)=18\times\left(\dfrac{19}{21}+\dfrac{8}{9}\right)\)
\(=18\times\dfrac{113}{63}=\dfrac{226}{7}=32\dfrac{2}{7}\)
=(45900-4590-41310):5900
=0:5900
=0
\(\left(45900-45900.10:100-41310000:1000\right):25.59.4\)
= ( 45900 - 4590 - 41310 ) : 25 . 59 . 4
= 90 : 25 . 59 . 4
= 3,6 . 59 . 4
= 212,4 . 4
= 849,6
Study well