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\(=\frac{12}{7}\cdot\frac{3}{4}-\frac{6}{7}\cdot\frac{4}{3}+\frac{6}{7}\)
\(=\frac{6}{7}\left(\frac{3}{2}-\frac{4}{3}+1\right)\)
\(=\frac{6}{7}\left(\frac{1}{6}+1\right)=\frac{6}{7}\cdot\frac{7}{6}=1\)
2.
\(=2017\cdot2018\cdot\left[\left(2016\cdot2018\right)-\left(2016\cdot2017\right)\right]\)
\(=2017\cdot2018\cdot2016\left(2018-2017\right)=2016\cdot2017\cdot2018\)
3.
\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)....\left(\frac{1}{100}-1\right)=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot....\cdot\frac{99}{100}\)
\(=\frac{1}{100}\)
4.
\(=\frac{1+2+2^2+2^4+...+2^9}{2\left(1+2+2^2+2^3+2^4+...+2^9\right)}\)
\(=\frac{1}{2}\)
mình chỉ làm được câu 3 thôi
có \(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)....\left(\frac{1}{100}-1\right)\)
\(=\frac{-1}{2}\times\frac{-2}{3}\times....\times\frac{-99}{100}\)
\(=\frac{\left(-1\right)\left(-2\right)....\left(-99\right)}{2\times3\times....\times100}\)
\(=\frac{-\left(1\times2\times....\times99\right)}{2\times3\times....\times100}\)
\(=\frac{-1}{100}\)
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Ta thấy mẫu số có : 2010 chữ số 1
2009 chữ số 2
....................
1 chữ số 2010
Vậy nên mẫu số có thể viết thành : 2010.1+2009.2+....................+1.2010
Vậy phân số trên bằng 1
Xét mẫu số :(1+2+3+..................+2010)+(1+2+3+..................+2009)+(1+2)+1
Ta thấy trong mẫu trên :Có 2010 chữ số 1;2009 chữ số 2;2008 chữ số 3;........................;1 chữ số 2010
Vậy mẫu số có thể viết thành : 2010x1+2009x2+2008x3+.....................+1x2010=1x2010+2x2009+3x2008+.............................+2010x1
Vậy phân số trên bằng 1
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= \(\left(2+\dfrac{3}{2^{ }}\right)^2\) : \(\left(2+\dfrac{\left(-1\right)}{2}\right)^2\)
= \(\left(\dfrac{2+3}{2^{ }}^{ }\right)^2\): \(\left(\dfrac{2+\left(-1\right)}{2}\right)^2\)
= \(\left(\dfrac{5}{2}\right)^2\): \(\left(\dfrac{1}{2^{ }}^{ }\right)^2\)
= \(\left(\dfrac{5.5}{2.2}\right):\left(\dfrac{1.1}{2.2}\right)\)
= \(\dfrac{25}{4}:\dfrac{1}{4}\)
= \(\dfrac{25}{4}.\dfrac{4}{1}\)
= \(\dfrac{25.4}{4.1}\)
= \(\dfrac{25}{1}=25\)
- Chúc bạn học tốt <3
( 2+ \(\dfrac{3}{2}\))\(^2\) : ( 2 - \(\dfrac{1}{2}\))\(^2\)
=\(\left(\dfrac{8}{3}\right)^2\) : \(\left(\dfrac{3}{2}\right)^2\)
= \(\dfrac{64}{9}\) : \(\dfrac{9}{4}\)= \(\dfrac{64}{9}\) . \(\dfrac{4}{9}\)
= \(\dfrac{256}{81}\)
tick nha
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a/\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)
=\(\frac{2^3.5^3.7^4}{2^2.5^2.7^4}\)
=2.5
=10
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a) \(\left(\dfrac{3}{4}-5x\right)-\left(2x-\dfrac{17}{4}\right)\)=\(\dfrac{44}{7}\)
\(\left(\dfrac{3}{4}-\dfrac{17}{4}\right)-\left(5x-2x\right)\) = \(\dfrac{44}{7}\)
\(\dfrac{-14}{4}-3x\) = \(\dfrac{44}{7}\)
3x= \(\dfrac{-14}{4}-\dfrac{44}{7}\)=\(\dfrac{-98}{28}-\dfrac{176}{28}\)= \(\dfrac{-274}{28}=\dfrac{-137}{14}\)
x= \(\dfrac{-137}{14}:3\)
x= \(\dfrac{-137}{42}\)
\(\left[2^2+\left(3^4-2^3\right)+52\right]-201^1\)
\(=\left[4+73+52\right]-201\)
\(=129-201\)
\(=-72\)