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Mình xin lỗi làm thiếu phân số cuối cùng
Bài đúng là thế này xin lỗi nhé. Kết quả chính xác là 4,5
\(=\frac{1}{10}+\frac{2.2}{2.10}+\frac{3.3}{3.10}+\frac{4.4}{4.10}+\frac{5.5}{5.10}+\frac{6.6}{6.10}+\frac{7.7}{7.10}+\frac{8.8}{8.10}+\frac{9.9}{9.10}=\)
\(=\frac{1}{10}+\frac{2}{10}+\frac{3}{10}+\frac{4}{10}+\frac{5}{10}+\frac{6}{10}+\frac{7}{10}+\frac{8}{10}+\frac{9}{10}=\)
\(=\frac{1+2+3+4+5+6+7+8+9}{10}=\frac{45}{10}=4,5\)
0,1 0,5 0,3du3 0,2 du8 0,2 0,1 du24 0,1du21 0,1 du16 0,1 du9
\(P=\left(1+\frac{1}{49}\right)+\left(1+\frac{2}{48}\right)+\left(1+\frac{3}{47}\right)+...+\left(1+\frac{48}{2}\right)+1=\frac{50}{49}+\frac{50}{48}+\frac{50}{47}+...+\frac{50}{2}+\frac{50}{50}\)
\(P=50.\left(\frac{1}{49}+\frac{1}{48}+\frac{1}{47}+...+\frac{1}{2}+\frac{1}{50}\right)=50.S\)
=> S/P = 1/50
\(\frac{8}{9}+\frac{1}{3}=\frac{8}{9}+\frac{3}{9}=\frac{11}{9}\)
\(\frac{8}{9}+\frac{1}{3}=\frac{8}{9}+\frac{3}{9}=\frac{11}{9}\)
\(\frac{24}{15}-\frac{20}{25}=\frac{24}{15}-\frac{4}{5}=\frac{24}{15}-\frac{12}{15}=\frac{12}{15}\)
\(3\frac{1}{6}\times2\frac{3}{5}=\frac{19}{6}\times\frac{13}{5}=\frac{247}{30}\)
\(2\frac{1}{10}\div2\frac{2}{5}=\frac{21}{10}\div\frac{12}{5}=\frac{21}{10}\times\frac{5}{12}=\frac{7}{8}\)
25/49 x 21/29 - 25/49 x 7/29 + 24/29
= 25/49 x ( 21/ 29 - 7/29 ) + 24/49
= 25/49 x 14/29 + 24/29
= 350/1421 + 24/29
= 350/1421 + 1176/1421
= 1526/1421
\(\frac{25}{49}\times\frac{21}{29}-\frac{25}{49}\times\frac{7}{29}+\frac{24}{49}\)
\(=\frac{25\times\left(21-7\right)}{49\times29}+\frac{24}{49}\)
\(\frac{50}{7\times29}+\frac{24}{49}=\frac{2450+4872}{7\times29\times49}=\frac{7322}{7\times29\times49}=\frac{1046}{1421}\)
a)13x3x32,27+67,63x39
=39x32,27+67,63x39
=39x(32,27+67,63)
=39x100
=3900
b,= 1- [ 1/2 x 1/3 x1/4 x..... x 1/100 ]
=1/2 x 2/3 x 3/4 x .......x 99/100
= 1x2x3x......x99 / 2x3x4x...... x100 [ rút gọn ]
= 1/100
a) ta có: \(A=\frac{2017.2018-1}{2017.2018}=\frac{2017.2018}{2017.2018}-\frac{1}{2017.2018}=1-\frac{1}{2017.2018}\)
\(B=\frac{2018.2019-1}{2018.2019}=1-\frac{1}{2018.2019}\)
\(\Rightarrow\frac{1}{2017.2018}>\frac{1}{2018.2019}\)
\(\Rightarrow1-\frac{1}{2017.2018}< 1-\frac{1}{2018.2019}\)
=> A < B
a)A= 2017*2018/2017*2018-1/2017*2018=1-1/2017*2018
B = 2018*2019/2018*2019-1/2018*2019=1-1/2018*2019
vì 1/2017*2018>1/2018*2019=> A<B
b)
ra D nhớ k cho mik