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a) Ta có: \(\frac{-9}{80}=\frac{\left(-9\right)x4}{80x4}=\frac{-36}{320}\) và \(\frac{17}{320}\)
b) Ta có: \(\frac{-7}{10}=\frac{\left(-7\right)x33}{10x33}=\frac{-231}{330}\) và \(\frac{1}{33}=\frac{1x10}{33x10}=\frac{10}{330}\)
c) Ta có:
\(\frac{-5}{14}=\frac{\left(-5\right)x10}{14x10}=\frac{-50}{140}\)
\(\frac{3}{20}=\frac{3x7}{20x7}=\frac{21}{140}\)
\(\frac{9}{70}=\frac{9x2}{70x2}=\frac{18}{140}\)
d) Ta có:
\(\frac{10}{42}=\frac{10x22}{42x22}=\frac{220}{924}\)
\(\frac{-3}{28}=\frac{\left(-3\right)x33}{28x33}=\frac{-99}{924}\)
\(\frac{-55}{132}=\frac{\left(-55\right)x7}{132x7}=\frac{-385}{924}\)
\(\frac{24\cdot47-23}{24+47\cdot23}.\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{9}{11}+9}\)
\(=\frac{24\cdot\left(24+23\right)-23}{24+\left(24+23\right)\cdot23}\cdot\frac{3\left(1+\frac{1}{7}-\frac{1}{11}+\frac{1}{1001}-\frac{1}{13}\right)}{9\left(\frac{1}{1001}-\frac{1}{13}+\frac{1}{7}-\frac{1}{11}+1\right)}\)
\(=\frac{24^2+24\cdot23-23}{24+24\cdot23+23^2}\cdot\frac{3}{9}\) \(=\frac{24^2+23\cdot\left(24-1\right)}{\left(23+1\right)\cdot24\cdot23^2}\cdot\frac{1}{3}=1\cdot\frac{1}{3}=\frac{1}{3}\)
ta có : ( -5/28 +7/4 + 8/35 ) : (- 69/20)
= ( -25/140 + 245/140 + 32/140 ) x (-20/69)
= (252/140) x (-20/69)
= (9/5) x (-20/69)
= (- 12/23)
tính nhanh:
2 x 3/7 + (2/9 - 10/7) - 5/3 x 9
= 6/7 + 2/9 - 10/7 - 5/3 x 9 = 6/7 + 2/9 - 10/7 - 15
= (6/7 - 10/7 ) + (2/9 - 135/9) = ( - 4/7 ) + (-133/9 )
= (- 36/63) + (-931/63)
= (- 967/63)
(7/9/4 + 4/7/11) - 3/4/9
=7/9/4 + 4/7/11 - 3/4/9
=(7/4/9 - 3/4/9) + 4/7/11
=4 + 4/7/11
=4+ 51/11
=44/11 + 51/11
=95/11
