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\(\frac{1024}{\left(17x2^5+15x2^5\right)}=\frac{2^{10}}{32x2^5}=\frac{2^{10}}{2^5.2^5}=\frac{2^{10}}{2^{10}}=1\) (1024=210; 32=25)
chị giúp nhưng phải k cho c nhé.
\(1024:\left(17x2^5+15x2^5\right)\)
\(=\)\(1024:\left[\left(17+15\right)x2^5\right]\)
\(=1024:\left(32x2^5\right)\)
\(=2^{10}:\left(2^5x2^5\right)\)
\(=2^{10}:2^{10}=1\)
1)\(2^3\cdot37-2^3\cdot63-10=2^3\left(37-63\right)-10=8\cdot-26-10\)=-218
2)\(2^3+2^2+2^4=2^2\left(1+2+4\right)=4\cdot7=28\)
3)\(5^3-5=5\left(5^2-1\right)=5\cdot24=120\)
4)\(3+3^2+3^4=3\left(1+3+3^3\right)=3\cdot13=39\)
5)\(x^{n+1}-x^n=x^n\left(x-1\right)\)
a) (2n - 1)7 = 510 : 53
=> (2n - 1)7 = 57
=> 2n - 1 = 5
=> 2n = 6
=> n = 6 : 2
=> n = 3
b) 5n + 2 . 53 = 254
5n + 2 . 53 = (52)4
=> 5n + 2 + 3 = 52.4
=> 5n + 5 = 58
=> n + 5 = 8
=> n = 8 - 5
=> n = 3
c) 9n + 1 . 3n + 2 = 319
=> (32)(n + 1) . 3n + 2 = 319
=> 32(n + 1) . 3n + 2 = 319
=> 32(n + 1) + n + 2 = 319
=> 2(n + 1) + n + 2 = 19
=> 2n + 2 + n + 2 = 19
=> 3n + 4 = 19
=> 3n = 15
=> n = 5
d) 25n + 2 : 5n + 1 = 1255
=> (52)(n + 2) : 5n + 1 = (53)5
=> 52.(n + 2) : 5n + 1 = 53 . 5
=> 52.(n + 2) - (n + 1) = 515
=> 2(n + 2) - (n + 1) = 15
=> 2n + 4 - n - 1 = 15
=> n + 3 = 15
=> n = 12
a. (2n - 1)7 = 510 : 53
<=> (2n - 1)7 = 57
<=> 2n - 1 = 5
<=> n = 3
b. 5n+2 . 53 = 254
<=> 5n.52 . 53 = (52)4
<=> 5n = 53
<=> n = 3
c. 9n+1 . 3n+2 = 319
<=> 9n.9 . 3n.32 = 319
<=> 32n.32 . 3n.32 = 319
<=> 33n = 315
<=> 3n = 15
<=> n = 5
Câu d và e hơi mâu thuẫn
a, 5 . ( x - 6 ) - 415 = 15
5 . ( x -6 ) = 15 + 415
5 . ( x - 6 ) = 430
x-6 = 430 : 5
x - 6 = 86
x = 86 + 6
x = 92
b, ( 3 . x - 12 ) . 3 = \(3^3\)
3 . x - 12 = 27 : 3
3 . x - 12 = 9
3. x = 9 + 12
3 . x = 21
x = 21 : 3
x = 7
x, \(\left(5-x\right)^2\) . \(2^2\) = 64
\(\left(5-x\right)^2\) . 4 = 64
\(\left(5-x\right)^2\) = 64 : 4
\(\left(5-x\right)^2\) = 16
\(\left(5-x\right)^2\) = \(4^2\)
5 - x = 4
x = 5 -4
x =1
Tk mk nha
\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}\left(1+5\right)=162\)
\(3^{x-1}=162\div6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Ko viết lại đề
<=> 3x-1.(1+5)=162
<=> 3x-1.6=162
<=> 3x-1=27
<=> 3x-1=33
<=> x-1=3
<=> x=4
Vậy x=4.
Đúng thì tk nha :3
<=> \(7x=5^2+3\)
<=> \(7x=28\)
<=> \(x=4\)
Vay x=4
chuc ban hoc tot !!!
6x + x = 511 : 59 + 31
7x = 52 + 3
7x = 25 + 3
7x = 28
x = 28 : 7
x = 4.
~ Chúc em học tốt nha ~ :3
\(3^{-1}.3^n+5.3^{n-1}=162\)
\(\Leftrightarrow\dfrac{1}{3}.3^n+5.3^n:3^1=162\)
\(\Leftrightarrow\dfrac{3^n}{3}+5.\dfrac{3^n}{3}=162\)
\(\Leftrightarrow\dfrac{3^n}{3}.\left(1+5\right)=162\)
\(\Leftrightarrow\dfrac{3^n}{3}=27\)
\(\Leftrightarrow3^n=3^3.3\)
\(\Leftrightarrow n=4\)
`3^(-1) *3^n +5 * 3^(n-1) =162`
`1/3 *3^n + 5*3^n :3 =162`
`1/3 * 3^n + 5/3 *3^n =162`
`3^n ( 1/3 +5/3 ) =162`
`3^n * 2 =162`
`3^n = 162/2 =81`
`3^n = 3^4`
`=> n=4`