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2a) Áp dụng t/c của dãy tỉ số bằng nhau, ta có:
\(\frac{x}{10}=\frac{y}{6}=\frac{z}{21}\) => \(\frac{5x}{50}=\frac{y}{6}=\frac{2z}{42}=\frac{5x+y-2z}{50+6-42}=\frac{28}{14}=2\)
=> \(\hept{\begin{cases}\frac{x}{10}=2\\\frac{y}{6}=2\\\frac{z}{21}=2\end{cases}}\) => \(\hept{\begin{cases}x=2.10=20\\y=2.6=12\\z=2.21=42\end{cases}}\)
Vậy x,y,z lần lượt là 20; 12; 42
#)Giải :
Bài 2 :
d) Đặt \(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}=k\)
\(\Rightarrow x=2k;y=3k;z=5k\)
\(\Rightarrow2k.3k.5k=810\)
\(\Rightarrow30k^3=810\)
\(\Rightarrow k^3=3\)
\(\Rightarrow k=3\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{2}=3\\\frac{y}{3}=3\\\frac{z}{5}=3\end{cases}\Rightarrow\hept{\begin{cases}x=6\\x=9\\x=15\end{cases}}}\)
Vậy x = 6; y = 9; z = 15
\(a;0,25-\frac{1}{2}\left|1,5-x\right|=2,5\)
\(\Leftrightarrow\frac{1}{2}\left|1,5-x\right|=0,25-2,5\)
\(\Leftrightarrow\frac{1}{2}\left|1,5-x\right|=-2,25\)
\(\Leftrightarrow\left|1,5-x\right|=-2,25\cdot2=-4,5\)
Mà \(\left|1,5-x\right|\ge0\)Nên suy ra |1,5-x|=-4,5 là vô lý
\(b;\left|x+\frac{1}{6}\right|\cdot0,75+\frac{1}{4}=2\frac{1}{3}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|\cdot\frac{3}{4}=\frac{7}{3}-\frac{1}{4}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|\cdot\frac{3}{4}=\frac{25}{12}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|=\frac{25}{12}\cdot\frac{4}{3}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|=\frac{25}{9}\Leftrightarrow x+\frac{1}{6}=\pm\frac{25}{9}\)
TH1:\(x+\frac{1}{6}=\frac{25}{9}\)
\(\Leftrightarrow x=\frac{25}{9}-\frac{1}{6}=\frac{47}{18}\)
TH2:\(x+\frac{1}{6}=-\frac{25}{9}\)
\(\Leftrightarrow x=-\frac{25}{9}-\frac{1}{6}=\frac{-53}{18}\)
Vậy \(x=\frac{47}{18};-\frac{53}{18}\)
Phần a hình như sai hay sao ý
\(b,3^x+3^{x+2}=810\)
\(\Rightarrow3^x+3^x\cdot9=810\)
\(\Rightarrow3^x\cdot\left(1+9\right)=810\)
\(\Rightarrow3^x\cdot10=810\)
\(\Rightarrow3^x=810:10=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
a)2^4-2^x=16^4
2^4-2^x=2^16
2^x=2^4-2^16
2^x=2^-12
x=-12
câu b mik ko biet nha ban !!:))
Bài 1: Tính
\(\left(\frac{-2}{3}\right)^4\times9^2\)
Bài 2: Tìm x
\(x^4=\frac{16}{625}\)
Giups mk vs!!!
Bài làm
1. \(\left(-\frac{2}{3}\right)^4.9^2\)
\(=\frac{16}{81}.81\)
\(=16\)
2. \(x^4=\frac{16}{625}\)
=>\(x^4=\left(\frac{2}{5}\right)^4\)
=> \(x=\frac{2}{5}\)
Vậy \(x=\frac{2}{5}\)
# Học tốt #
Bài 1:
\(\left(-\frac{2}{3}\right)^4.9^2=\frac{\left(-2\right)^4}{3^4}.\left(3^2\right)^2=\frac{2^4}{3^4}.3^4=2^4=16\)
Bài 2:
\(x^4=\frac{16}{625}\Leftrightarrow x^4=\frac{4^4}{5^4}\Leftrightarrow x^4=\left(\frac{4}{5}\right)^4\)
\(\Rightarrow x=\frac{4}{5}\)hoặc\(x=-\frac{4}{5}\)
Vậy........
a) ta có: \(-3x=5y\Rightarrow\frac{x}{5}=\frac{y}{-3}\)
ADTCDTSBN
có: \(\frac{y}{-3}=\frac{x}{5}=\frac{y-x}{-3-5}=\frac{20}{-8}=\frac{5}{2}\)
=> y/-3 = 5/2 => y = -15/2
x/5 = 5/2 => x = 25/2
KL:...
b) ta có: \(\frac{2x}{3}=\frac{3y}{4}\Rightarrow8x=9y\Rightarrow\frac{x}{9}=\frac{y}{8}\)
\(\frac{3y}{4}=\frac{4z}{5}\Rightarrow15y=8z\Rightarrow\frac{y}{8}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{9}=\frac{y}{8}=\frac{z}{15}\)
ADTCDTSBN
có: \(\frac{x}{9}=\frac{y}{8}=\frac{z}{15}=\frac{x+y+z}{9+8+15}=\frac{49}{32}\)
=> x/9 = 49/32 => x = ...
...