Question

[ngọc nguyễn]

giúppp mình vs m.n

Answer 1

[Thảo]

Bài 1:

a) \(\dfrac{5x-6}{2x-1}=\dfrac{3x}{x-2}\)      (1)

ĐK:\(\left\{{}\begin{matrix}2x-1\ne0\\x-2\ne0\end{matrix}\right.\) ⇔\(\left\{{}\begin{matrix}x\ne\dfrac{1}{2}\\x\ne2\end{matrix}\right.\)

(1) ⇒\(\dfrac{\left(5x-6\right)\left(x-2\right)}{\left(2x-1\right)\left(x-2\right)}=\dfrac{3x\left(2x-1\right)}{\left(2x-1\right)\left(x-2\right)}\)

⇔\(5x^2-10x-6x+12=6x^2-3x\)

⇔\(5x^2-10x-6x+12-6x^2+3x=0\)

⇔\(-x^2-13+12=0\)

⇔\(\left[{}\begin{matrix}x=\dfrac{-13+\sqrt{217}}{2}\\x=\dfrac{-13-\sqrt{217}}{2}\end{matrix}\right.\left(TM\right)\)

KL:

Answer 2

[Thảo]

sorry! câu này mih làm sai mất rồi