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a) (x - 15) × 7 - 270 : 45 = 169
(x - 15) × 7 - 6 = 169
(x - 15) × 7 = 169 + 6
(x - 15) × 7 = 175
x - 15 = 175 : 7
x - 15 = 25
x = 25 + 15
x = 40
b) [(4x + 28) × 3 + 55] : 5 = 35
(4x + 28) × 3 + 55 = 35 × 5
(4x + 28) × 3 + 55 = 175
(4x + 28) × 3 = 175 - 55
(4x + 28) × 3 = 120
4x + 28 = 120 : 3
4x + 28 = 40
4x = 40 - 28
4x = 12
x = 12 : 4
x = 3
c) (455 × x : 2 × 6) : 5 = 31
455 × x : 2 × 6 = 31 × 5
455 × x : 2 × 6 = 155
x × 455 : 2 × 6 = 155
x × 1365 = 155
x = 155 : 1365
x = 31/273
d) 128 × x - 12 × x - 16 × x = 520800
(128 - 12 - 16) × x = 520800
100 × x = 520800
x = 520800 : 100
x = 5208
e) (x × 0,25 + 2022) × 2023 = (50 + 2022) × 2023
(x × 0,25 + 2022) × 2023 = 2072 × 2023
(x × 0,25 + 2022) × 2023 = 4191656
x × 0,25 + 2022 = 4191656 : 2023
x × 0,25 + 2022 = 2072
x × 0,25 = 2072 - 2022
x × 0,25 = 50
x = 50 : 0,25
x = 200
f) 4 × x + 100 = x + 280
4 × x - x = 280 - 100
(4 - 1) × x = 180
3 × x = 180
x = 180 : 3
x = 60
g) (x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 7450
x + 1 + x + 2 + x + 3 + ... + x + 100 = 7450
100 × x + 100 × 101 : 2 = 7450
100 × x + 5050 = 7450
100 × x = 7450 - 5050
100 × x = 2400
x = 2400 : 100
x = 24
a) = 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
b) = 1/3 x 4/5 + 1/3 x6/5 + 1/3 x 2 = 1/3(4/5 + 6/5 + 2) = 1/3 x 4 = = 4/3
c) 4/7 x 2/9 + 4/7 x 7/9 + 2/3 = 4/7 x (2/9 + 7/9) + 2/3 = 4/7 x 1 + 2/3 = 26/21
A) 17/19 - 17/19 + 27/35 + 35/35 = 0 + 62/35
B) 1/3 x 4/5 + 1/3 x 6/5 + 1/3 x 2 = 1/3 x(4/5 + 6/5 x 2 ) = 1/3 x 4 = 4/3
c) TƯƠNG TỰ CÂU A VÀ B
* HOKTOT*
NHA
\(\frac{4}{3}+\frac{x}{3}\text{ × }7=6\)
\(\frac{x}{3}\text{ × }7=6-\frac{4}{3}\)
\(\frac{x}{3}=\frac{14}{3}:7\)
\(\frac{x}{3}=\frac{2}{3}\)
\(\Leftrightarrow x=2\)
Các phần còn lại bạn làm tương tự nha
Bài 1:
câu a: 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)
= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)
= \(\dfrac{29}{6}\)
b, (15,25 + 3,75) \(\times\) 4 + ( 20,71 + 5,29)\(\times\) 5
= 19 \(\times\) 4 + 26 \(\times\) 5
= 76 + 130
= 206
c, \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{3}\) - \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{4}\)
= \(\dfrac{2}{5}\) + \(\dfrac{4}{15}\) - \(\dfrac{1}{5}\)
= \(\dfrac{6}{15}\) + \(\dfrac{4}{15}\) - \(\dfrac{3}{15}\)
= \(\dfrac{7}{15}\)
d, 1\(\dfrac{5}{7}\) + 7\(\dfrac{3}{6}\) + 2\(\dfrac{2}{7}\) - 4\(\dfrac{3}{6}\)
= (1 + 2 + \(\dfrac{5}{7}\) + \(\dfrac{2}{7}\)) + ( 7 + \(\dfrac{3}{6}\) - 4 - \(\dfrac{3}{6}\))
= 3 + 1 + 3
= 7
a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
\(a,\left(x-15\right)\times7-270=169\times45\\ \left(x-15\right)\times7-270=7605\\ \left(x-15\right)\times7=7605+270\\ \left(x-15\right)\times7=7875\\ x-15=7875:7\\ x-15=1125\\ x=1125+15\\ x=1140\\ b,64-\left(34\times x-8\right)=4\\ 34\times x-8=64-4\\ 34\times x-8=60\\ 34\times x=60+8\\ 34\times x=68\\ x=68:34\\ x=2\)
a) \(x+\dfrac{4}{5}=\dfrac{4}{5}+\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)
\(\Leftrightarrow x=\dfrac{3}{7}+\dfrac{3}{5}+\dfrac{4}{5}-\dfrac{4}{5}\)
\(\Leftrightarrow x=\dfrac{36}{35}\)
b) \(\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{x}{35}=\dfrac{4}{5}-\dfrac{5}{7}\)
\(\Leftrightarrow\dfrac{x}{35}=\dfrac{3}{35}\)
\(\Leftrightarrow x=3\)
c) \(\left(x-15\right).7-270\div45=169\)
\(\Leftrightarrow\left(x-15\right).7-6=169\)
\(\Leftrightarrow\left(x-15\right).7=175\)
\(\Leftrightarrow x-15=25\)
\(\Leftrightarrow x=40\)