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\(x^4\cdot x^7\cdot...\cdot x^{100}\)
\(=x^{4+7+...+100}\)
\(=x^{52\cdot33}=x^{1716}\)
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}\)
Ta có : \(x^1\cdot x^2=x^{1+2}=x^3\)
Tương tự : \(x^1\cdot x^2\cdot x^3=x^{1+2+3}=x^6\)
Áp dụng vào bài toán :
\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}=x^{1+2+3+...+2006}\)
\(\Rightarrow x^{1+2+3+...+2006}=x^{2013021}\)
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k nha
Bài 1.
a) 123.33=(12.3)3=363.123.33=(12.3)3=363.
b) 25.84=25.(23)4=25.212=217.25.84=25.(23)4=25.212=217.
c) 38.90.272=38.1.(33)2=38.36=314.38.90.272=38.1.(33)2=38.36=314.
d) 24.54=(2.5)4=104.24.54=(2.5)4=104.
e) 24.43=24.(22)3=24.26=210
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a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
cô ơi cho con hỏi
11 mũ 5 chia cho 11 mũ n trừ 4 bằng 11 mũ 5
giúp tính bài giải cho con nhé
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64*4^x =16^8
4^3*4^x=(4^2)^8
4^(3+x)=4^16
=> 3+x=16
=> x=16-3
=> x=13
vậy ...
\(x+7^4=8^4\\x+2401=4096\\x=4096-2401\\x=1695\)
X+7^4=8^4
X=8^4-7^4
X=4096-2401
X=1695