Question

[Cao Hoài Phúc]

giup minh may bai nay

2 . gia tri cua x³+y³+72 voi x+y=14 va xy=48 la?

Answer 1

[Min]

\(x^3+y^3+72=x^3+y^3+3x^2y+3xy^2-3x^2y-3xy^2+72\)

\(=\left(x+y\right)^3-3xy\left(x+y\right)+72\)

\(=14^3-3.48.14+72=800\)