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A = 1 x 2 + 2 x 3 + 3 x 4 + 4 x 5 + ... + 99 x 100
A = 2 + 6 + 12 + 20 + ... 9900
A = [2+9900] rồi bn nhân tổng số từ số 2 - 9900
\(3A=1.2.3+2.3.\left(4-1\right)+...+99.100.\left(101-98\right)\)
\(3A=1.2.3+2.3.4-1.2.3+...+99.100.101-98.99.100\)
\(3A=99.100.101\)
\(\Rightarrow A=\frac{99.100.101}{3}\)
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\(a,x=\dfrac{13}{2}-2\\ x=\dfrac{9}{2}\\ b,x=\dfrac{4}{5}\times\dfrac{3}{4}\\ x=\dfrac{12}{20}=\dfrac{3}{5}\)
Y +2 x y + 3 x y + 4 x y+ ... + 10 x y = 49,5
giupws mik nha nhớ ghi cách giải rõ ràng nha mọi người
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y+2xy+3xy+...+10xy=49,5
yx(1+2+3+4+...+10)=49,5
yx45 =49,5
y= 49,5:45
y= 1,1
t tôi ik
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\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}:\frac{3}{5}+\frac{10}{9}\)
\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{10}{21}+\frac{10}{9}\)
\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{100}{63}\)
\(\frac{2}{3}:\frac{x}{5}\) \(=\frac{100}{63}-\frac{5}{7}\)
\(\frac{2}{3}:\frac{x}{5}\) \(=\frac{55}{63}\)
\(\frac{x}{5}\) \(=\frac{2}{3}:\frac{55}{63}\)
\(\frac{x}{5}\) \(=\frac{42}{55}\)
\(\frac{x\cdot11}{55}\) \(=\frac{42}{55}\)
\(\Rightarrow x\cdot11=42\)
\(x\) \(=42:11\)
\(x\) \(=\frac{42}{11}\)
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Lớp học online hay j mà lắm giáo viên thế🤔🤔 Lớp học của tri thức à?
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\(\frac{2}{3}:y\) x \(\frac{3}{4}=\frac{3}{2}\)
\(\frac{2}{3.y}=\frac{3}{2}:\frac{3}{4}\)
\(\frac{2}{3y}=2\)
=> \(3y=\frac{2}{2}=1\)
=> y = \(\frac{1}{3}\)
\(\frac{2}{3}:y\times\frac{3}{4}=\frac{3}{2}\)
=> \(\frac{2}{3}:y=\frac{3}{2}:\frac{3}{4}=\frac{3}{2}\times\frac{4}{3}=2\)
=> \(y=\frac{2}{3}:2=\frac{2}{3}\times\frac{1}{2}=\frac{1}{3}\)