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2x+2 - 2x = 96
<=> 2x × 22 - 2x = 96
<=> 2x.( 22 - 1 ) = 96
<=> 2x . 3 = 96
<=> 2x = 96 : 3
<=> 2x = 32
<=> 2x = 25
<=> x = 5
Vậy x = 5
a) (9 - x)^3 = 216
(9 - x)^3 = 6^3
9 - x = 6
-x = 6 - 9
-x = -3
x = 3
b) 2^x + 2 - 2^x = 96
3.2^x = 96
2^x = 96 : 3
2^x = 32
2^x = 2^5
x = 5
a) \(\left(x^2-9\right)\cdot\left(4^x-16\right)=0\)
\(\Rightarrow x^2-9=0\)hoặc \(4^x-16=0\)
\(x^2=9\) \(4^x=16\)
\(x^2=\left(\pm3\right)^2\) \(4^x=4^2\)
\(\Rightarrow x=\pm3\)hoặc \(x=2\)
b) \(5^x+5^{x+2}=650\)
\(\Rightarrow5^x+5^x\cdot25=650\)
\(\Rightarrow5^x\cdot\left(1+25\right)=650\)
\(\Rightarrow5^x\cdot26=650\)
\(\Rightarrow5^x=650\div26=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)Vậy \(x=2\)
c) \(2^{x+2}-2^x=96\)
\(2^x\cdot4-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96\div3=32\)
\(2^x=2^5\)Vậy \(x=5\)
60 : {[(12-3). 2 ] + 2 }
=60 : [(9. 2 ) + 2 ]
=60 : (18 + 2 )
=60 : 20
=3
a) 5 (x + 35 ) = 515
x + 35=515:5
x + 35=103
x=103-35
x=68
b) 96 - 3 (x+1) = 42
3 (x+1) = 96-42
3 (x+1) = 54
x+1=54:3
x+1=18
x=18-1
x=17
câu a là dấu nhân đấy bạn
a) 5(x+35) = 515
x+35 = 515 :5
x+35 = 103
x = 103 -35
x = 68
b) 96 - 3(x-1) = 42
3(x-1) = 96 - 42
3(x-1) = 54
x-1 = 54:3
x-1 = 18
x = 18 + 1
x = 19
ko có dấu tức là dấu nhân
30+{96-3.[54-2.(32+6)]}.x =79
30+{96-3.[54-2.15]}.x=79
30+{96-3.[54-30]}.x=79
30+{96-3.24}.x=79
30+{96-72}.x=79
30+24.x=79
24.x=79-30
24x=49
x=49/24
\(30+\left\{96-3.\left[54-2\left(3^2+6\right)\right]\right\}.x=78\)
\(30+\left\{96-3.\left[56-2.15\right]\right\}.x=78\)
\(30+\left\{96-3.\left[56-30\right]\right\}.x=78\)
\(30+\left\{96-3.26\right\}.x=78\)
\(30+\left\{96-78\right\}.x=78\)
\(30+18.x=78\)
\(\Rightarrow18.x=48\)
\(\Rightarrow x=\frac{8}{3}\)
học tốt
a) 22.14x . 72 = 14100
=> (2.7)2 . 14x = 14100
=> 14x = 14100 : 142
=> 14x = 1498
=> x = 98
b) 15.x + 3(x + 2) = 96
=> 15x + 3x + 6 = 96
=> 18x = 96 - 6
=> 18x = 90
=> x = 90 : 18 = 5
c) 2x + 4.2x = 5.25
=> 2x(1 + 4) = 5.25
=> 2x .5= 5.25
=> 2x = 5.25 : 5
=> 2x = 25
=> x = 5
\(a,2^2.14^x.7^2=14^{100}\)
\(\Rightarrow14^2.14^x=14^{100}\)
\(\Rightarrow14^x=14^{98}\)
\(\Rightarrow x=98\)
\(b,15.x+3\left(x+2\right)=96\)
\(\Rightarrow3\left(5x+x+2\right)=96\)
\(\Rightarrow6x+2=32\)
\(\Rightarrow6x=30\)
\(\Rightarrow x=5\)
\(c,2^x+4.2^x=5.2^5\)
\(\Rightarrow2^x\left(1+4\right)=5.2^5\)
\(\Rightarrow2^x.5=5.2^5\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(30+\left\{96-3.\left[54-2.\left(3^{2+6}\right)\right]\right\}.x=79\)
\(30+\left\{96-3.\left[54-2.6561\right]\right\}.x=79\)
\(30+\left\{96-3.\left[54-13122\right]\right\}.x=79\)
\(30+\left\{96-3.-13068\right\}.x=79\)
\(30+\left\{96--39204\right\}.x=79\)
\(30+39300.x=79\)
\(39300.x=79-30\)
\(39300.x=49\)
\(\Rightarrow x=\frac{39300}{49}\)
\(2^{x+2}-2^x=96\)
=>\(2^x\cdot4-2^x=96\)
=>\(2^x\cdot3=96\)
=>\(2^x=\dfrac{96}{3}=32=2^5\)
=>x=5