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5 - ( 2x - 7 ) = 3 . ( -4) + 20
5 - ( 2x - 7 ) = ( -12 ) + 20
5- ( 2x - 7 ) = 8
2x - 7 = 5 - 8
2x - 7 = -3
2x = -3 + 7
2x = 4
x = 4 : 2
x = 2
chúc bn hok tốt
\(-7-5-x=12+\left(-5+8\right)\)
\(\Leftrightarrow-12-x=12+3\)
\(\Leftrightarrow-12-x=16\)
\(\Leftrightarrow x=-12-16\)
\(\Leftrightarrow x=-28\)
\(\text{Vậy }x=-28\)
-7-5-x=12+(-5+8)
-7-5-x=15
5-x=-7-15
5-x=-7+(-15)
5-x=-(7+15)
5-x=-22
x=5-(-22)
x=5+22
x=27
Vậy x=27
a) 3x + 27 = 9
3x = 9 - 27
3x = -18
x = -18 : 3
x = - 6
Vậy x=-6
b) 2x + 12 = 3(x - 7 )
2x + 12 = 3x - 21
12 + 21 = 3x - 2x
33 = x
Vậy x=33
c) 2x2 - 1 = 49
2x2=49+1
2x2=50
x2=50:2
x2=25
x2=52
=> x= + 5
Vậy x=+5
d) |x + 9 | . 2 =10
|x + 9 | = 10 : 2
|x + 9 | = 5
\(\Rightarrow\orbr{\begin{cases}x+9=5\\x+9=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5-9=-4\\x=-5-9=-14\end{cases}}\)
Vậy \(x\in\left\{-4;-14\right\}\)
\(\frac{12}{7}\times\frac{2}{11}+\frac{12}{11}\times\frac{15}{7}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\frac{2}{11}+\frac{12}{7}\times\frac{15}{11}-\frac{12}{7}\times\frac{6}{11}\)
\(=\frac{12}{7}\times\left(\frac{2}{11}+\frac{15}{11}-\frac{6}{11}\right)\)
\(=\frac{12}{7}\times1=\frac{12}{7}\)
\(\frac{12}{7}.\frac{2}{11}+\frac{12}{11}.\frac{15}{7}-\frac{12}{7}.\frac{6}{11}\)
= \(\frac{24}{77}\)+\(\frac{180}{77}\)-\(\frac{72}{77}\)
=\(\frac{132}{77}\)
2/3.x + 1/4 = 7/12
2/3.x = 7/12 - 1/4
2/3.x = 1/3
x = 1/3 : 2/3
x = 1/2
Bài làm
\(\frac{2}{3}x+\frac{1}{4}=\frac{7}{12}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{1}{4}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{3}{12}\)
\(\frac{2}{3}x=\frac{4}{12}\)
\(\frac{2}{3}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{2}{3}\)
\(x=\frac{1}{3}.\frac{3}{2}\)
\(x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
3. (x+5) - 4.(x+7)=20
3x +15-4x-28 . =20
-x . =20+28-15
-x . =33
x. -33
3(x+5)-4(x+7)=20
<=> 3x+15-4x-28=20
<=> -x-13=20
<=> x+13=-20
<=> x=-33
17x+3.(-16x-37) =2x+43+4x
17x+3.(-16).x-3.37=6x+43
17x+(-48)x-119 =6x+43
[17x-6x+(-48)x] =43+119
-37x =162
37x =-162
x =-162:37
x = -162/37
\(2x+12=3.\left(x-7\right)\)
=> \(2x+12=3x-21\)
=> \(2x-3x=-21-12=\left(-21\right)+\left(-12\right)=-33\)
=> \(x\left(2-3\right)=-33\)
=> \(x.\left(-1\right)=-33\)
=> \(x=\left(-33\right):\left(-1\right)=33\)
Vậy: x = 33
2x+12=3(x-7)
<=>2x+12=3x-21
<=>2x-3x=-21-12
<=>-x=-33
=>x=33
Vậy x=33