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\(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+...+\frac{1}{x\cdot\left(x+2\right)}=\frac{20}{41}\)
\(\frac{1}{2}\cdot\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{x\cdot\left(x+2\right)}\right)=\frac{20}{41}\)
\(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}=\frac{20}{41}:\frac{1}{2}\)
\(1-\frac{1}{x+2}=\frac{40}{41}\)
\(\frac{1}{x+2}=1-\frac{40}{41}\)
\(\frac{1}{x+2}=\frac{1}{41}\)
\(\Rightarrow x+2=41\Rightarrow x=39\)
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Sửa lại câu a
ĐKXĐ: \(x\ne5;x\ne-2\)
Đề \(\Rightarrow3\left(x+2\right)=\left(-4\right)\left(x-5\right)\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow-7x=-14\)
\(\Rightarrow x=2\left(n\right)\)
Vậy x = 2
c viết lại phân số đc k , k thể phân biệt đc giữa số và phân số
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1)4
2) 1 phần 5
3) 110 phần 13
4)7 phần 4
5)0
nếu đúng thì tk nhé hóng ^^
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\(\frac{x-5}{9}=\frac{-1}{3}\Rightarrow3.\left(x-5\right)=9.\left(-1\right)\)
\(\Rightarrow3x-15=-9\)
\(\Rightarrow3x=6\)
\(\Rightarrow x=2\)
Vậy x = 2
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a) ( 2x - 5 ) - 3 = 2
2x - 5 = 2 + 3
2x - 5 = 5
2x = 5 + 5
2x = 10
x = 10 : 2
x = 5
Vậy x = 5
a,(2.x-5)-3=2
<=> 2x-5-3=2
<=> 2x-5-3-2=0
<=> 2x-10=0
<=> 2(x-5)=0
<=> x-5=0
<=> x=5
Đs: x=5
b,(3.x+1)+(x+1)=4
<=> 3x+1+x+1=4
<=> 3x+1+x+1-4=0
<=> 4x-2=0
<=> 2(x-1)=0
<=> x-1=0
<=> x=1
Đs:x=1
c,-12.(x-5)+7(3-x)=15
<=> -12x+60+21-3x=15
<=> -12x+60+21-7x-15=0
<=> -19x+66=0
<=> -19x+66=0
<=> -19x=-66
<=> x=66/19
Đs: 66/19
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a)
\(6x+5=4x-7\)
\(\Leftrightarrow6x-4x=-7-5\)
\(\Leftrightarrow2x=-12\)
\(\Leftrightarrow x=-6\)
b)
\(-3\left(x-5\right)-1=2x-1\)
\(\Leftrightarrow-3x+15-1=2x-1\)
\(\Leftrightarrow-3x-2x=-1-15+1\)
\(\Leftrightarrow-5x=-15\)
\(\Leftrightarrow x=3\)
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=> 5 - [ 4 - ( 1 + 2x ) ] = -6
=> 4 - 1 - 2x = 11
=> 2x = 3 - 11 = -8
=> x = -4