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\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}:\left(4,5-2\right)-0,2\)
\(=\frac{4}{25}+\frac{11}{2}:\frac{5}{2}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{2}.\frac{2}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{11}{5}-\frac{1}{5}\)
\(=\frac{4}{25}+\frac{55}{25}-\frac{5}{25}\)
\(=\frac{54}{25}\)
a) Đề sai
b) \(\left|x+\frac{4}{5}\right|=\frac{1}{7}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{5}=\frac{1}{7}\\x+\frac{4}{5}=\frac{-1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{7}-\frac{4}{5}\\x=\frac{-1}{7}-\frac{4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{35}-\frac{28}{35}\\x=\frac{-5}{35}-\frac{28}{35}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{-23}{35}\\x=\frac{-33}{35}\end{cases}}}\)
Vậy \(x=\frac{-23}{35}\)hoặc \(x=\frac{-33}{35}\)
Đặt: \(A=1+5+5^2+...+5^{2013}\)
\(5A=5\left(1+5+5^2+...+5^{2013}\right)\)
\(=5+5^2+5^3+...+5^{2014}\)
\(5A-A=\left(5+5^2+...+5^{2014}\right)-\left(1+5+5^2+...+5^{2013}\right)\)
\(4A=5^{2014}-1\)\(\Rightarrow A=\frac{5^{2014}-1}{4}\)
Có: \(A.\left|x-1\right|=5^{2014}-1hay\frac{5^{2014}-1}{4}.\left|x-1\right|=5^{2014}-1\)
\(\left(5^{2014}-1\right).\left|x-1\right|=4.5^{2014}-4\)
\(\left|x-1\right|=\frac{4\left(5^{2014}-1\right)}{5^{2014}-1}\)
\(\left|x-1\right|=4\)
\(\Rightarrow x-1=4\)hoặc \(x-1=-4\)
+) Xét: \(x-1=4\)
\(x=4+1\)
\(x=5\)
+) Xét: \(x-1=-4\)
\(x=-4+1\)
\(x=-3\)
Vậy \(x=5\)hoặc \(x=-3\)
cảm ơn