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b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)
\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)
\(=5\)
c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)
\(A=\dfrac{-11}{12}.\dfrac{-4}{33}.\dfrac{84}{-25}.\dfrac{5}{8}\)
\(A=\dfrac{1}{9}.\dfrac{-21}{10}\)
\(A=\dfrac{-7}{30}\)
\(B=3\dfrac{2}{7}.12\dfrac{2}{7}-3\dfrac{2}{7}.5\dfrac{1}{2}\)
\(B=\dfrac{23}{7}.\dfrac{86}{7}-\dfrac{23}{7}.\dfrac{11}{2}\)
\(B=\dfrac{23}{7}.\left(\dfrac{86}{7}-\dfrac{11}{2}\right)\)
\(B=\dfrac{23}{7}.\dfrac{95}{14}\)
\(B=\dfrac{2185}{98}\)
Chúc bạn học tốt!
a. = \(\dfrac{-1}{24}-\left\{\dfrac{1}{4}-\dfrac{-3}{8}\right\}\)
= \(\dfrac{-1}{24}-\left\{\dfrac{1}{4}+\dfrac{3}{8}\right\}\)
= \(\dfrac{-1}{24}-\dfrac{5}{8}\)
= \(\dfrac{-2}{3}\)
b. = \(12\dfrac{7}{88}-3\dfrac{5}{11}\)
= \(8\dfrac{5}{8}\)
c. = \(\dfrac{-28}{9}+\dfrac{-413}{9}\)
= \(-49\)
d. = \(\dfrac{8}{35}:\dfrac{2}{11}+\dfrac{-8}{35}:\dfrac{2}{11}\)
= \(\dfrac{2}{11}:\left(\dfrac{8}{35}+\dfrac{-8}{35}\right)\)
= 0
a,\(\left(-1,25\right).14,7.\left(-8\right)\)
\(=\left[\left(-1,25\right).\left(-8\right)\right].14,7\)
\(=10.14,7=147\)
b, \(\dfrac{3}{4}-1\dfrac{1}{6}\)
\(=\dfrac{3}{4}-\dfrac{7}{6}\)
\(=\dfrac{9-14}{12}=\dfrac{-5}{12}\)
câu c: Mình không biết bạn có gõ sai không, bạn coi đề lại xem.
d, \(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|\)
\(=\dfrac{3}{4}.\dfrac{2}{3}=\dfrac{1.1}{2.1}=\dfrac{1}{2}\)
e, ?
8)\(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)
=\(\frac{4}{9}:\left(-\frac{1}{7}\right)+\frac{59}{9}:\left(-\frac{1}{7}\right)\)
=\(\left(\frac{4}{9}+\frac{59}{9}\right).\left(-7\right)\)
=7.(-7)
=-49
\(G=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{6}}{\dfrac{5}{2}+\dfrac{5}{3}-\dfrac{5}{6}}=\dfrac{1}{5}\)
\(H=\left[\dfrac{32}{99}\cdot\dfrac{14}{9}-\dfrac{25}{99}\right]\cdot\dfrac{11}{83}\)
\(=\dfrac{223}{891}\cdot\dfrac{11}{83}=\dfrac{223}{6723}\)